0.00079 moles EDTA4- c. 0.00079 moles ZnI2 d. 0.0517 grams of ZnI2 are in the sample e. 0.0517/0.237= 21.8% f. Error Is 6.34% Lab Report: Part 1: In this lab we used the following supplies: * Zinc Iodide * Na2H2EDTA(s) * Calmagite indicator solution * pH 10 buffer solution * 6M Acetic Acid * Unknown Zinc Compound The main purpose for this part of the lab was to determine the amount of zinc ion in a sample of ZnI2 by titration. The two types of zinc: * Zinc iodide made by zinc and iodine * Commercially purchased zinc iodide (the
The recommended maximum allowable concentration for a daily 8-hour time-weighted exposure is 0.1 parts per million. The fluorine-containing mineral fluorspar (or fluorite) was described in 1529 by the German physician and mineralogist Georgius Agricola. It appears likely an unknown English glassworker first prepared the crude hydrofluoric acid in 1720. In 1771 the Swedish chemist Carl Wilhelm Scheele obtained hydrofluoric acid in an impure state by heating fluorspar with concentrated sulfuric acid in a glass retort, which was greatly corroded by the product; as a result, vessels made of metal were used in subsequent experiments with the substance. The nearly anhydrous acid was prepared in 1809, and two years later the French physicist André-Marie Ampère suggested that it was a compound of hydrogen with an unknown element, analogous to chlorine, for which he suggested the name
Synthesis of Methyl Stearate Post-Lab Submitted by Matthew Sharma TA: Evan Determining the Limiting Reagent Methyl Oleate (MW= 296.49 g/mol) Amount used = 1.141g (1.141g)(1mol / 296.49g) = 0.003848 mol ∴ The limiting reagent for the reaction is methyl oleate because hydrogen is used in excess Theoretical Yield Methyl Stearate (0.003848 mol)(298.504g/mol product) = 1.1486 g methyl stearate Percent Yield Given the 1:1 stoichiometry of the reaction: 100% x (0.2551g product / 1.1486g theoretical yield) = 22.2% Conclusion A 22.2% yield of synthesized methyl stearate was obtained via the catalytic hydrogenation of methyl oleate in the presence of the catalyst 10% palladium on carbon. The product
b) Calculate the enthalpy of combustion per gram of each sugar. C6H12O6 + 6O2 --> 6CO2 + 6H2O (-383.5 x 6 + -285.8 x 6) - (-1273) = -2742.8kJ C12H22O11 + 12O2 --> 12CO2 + 11H2O (-383.5x12 + -285.8x11) - (-2221) = -5524.8kJ -2742.8kJ / 180g/mole = -15.24kJ/g -5524.8kJ / 342g/mole = -16.14kJ/g 107. Three common hydrocarbons that contain four carbons are listed here, along wiht their standard enthalpies of formation: Formula Delta H in kJ per mol 1,3-Butadiene C4H6(g) 111.9 1-Butene C4H8(g) 1.2 n-Butane C4H10(g) -124.7 a. For each of these substances, calculate the molar enthalpy of combustion to CO2(g) and H2O(l). b.
1. 25 cm3 of a solution of 0.1 moldm-3 NaOH reacts with 50 cm3 of a solution of hydrochloric acid. What is the molarity of the acid? 2. 25.0 cm3 of a 0.10 moldm-3 solution of sodium hydroxide was titrated against a solution of hydrochloric acid of unknown concentration.
The relatively high oxidising power of the halogens could be due to their electronic configuration. All the halogens are in the p sub shell. The P sub shell contains the highest energy electrons, so this is also another factor due to their high oxidising power. As you go down the group the elements become less volatile. Fluorine is a yellowish green gas at room temperature, Chlorine is Greenish yellow gas, Bromine is a dark red liquid that is volatile and give off a dark red-brown vapour , and iodine is a shiny grey solid.
Using Numbers: Calculate the moles of iron used in the reaction. 6. Using Numbers: Determine the whole number ratio of moles of iron to moles of copper. 7. Comparing and Contrasting: Compare the ratio of moles of iron to moles of copper from the balanced chemical equation to the mole ratio calculated using your data.
2NaCl + H2SO4 —> Na2SO4 + 2HCl 4. If 0.380 mole of barium nitrate is allowed to react with an excess of phosphoric acid, how many moles of barium phosphate could be formed? 3Ba(NO3)2 + 2H3PO4 —> Ba3(PO4)2 + 6HNO3 5. Calculate the number of grams of carbon dioxide produced from the burning of 1.65 moles of C3H8. C3H8 + 5O2 —> 3CO2 + 4H2O 6.
The ULTIMATE Chemistry Semester 2 Study Guide! Iron: Fe+2 is ferrous Fe+3 is ferric Copper: Cu+1 is cuprous Cu+2 is cupric Lead: Pb+2is plumbous Pb+4 is plumbic Tin: Sn+2 is stannous Sn+4 is stannic Periodic Table TRENDS * As you move right along the periodic table… decreasing atomic radius, increasing ionization energy, increasing electronegativity, increasing electron affinity, constant shielding * As you move down the periodic table… increasing atomic radius, decreasing ionization energy, decreasing electronegativity, increasing shielding WTF is that stuff? * Atomic radius is the distance between the nuclei of atoms when they are involved in a chemical bond. As you increase the number of protons in the nucleus
The energy released is in the form of increased kinetic energy of the product particles and any radiation emitted. The energy released in a nuclear fission is very much larger compared to the energy released in a chemical reaction. Spontaneous natural nuclear fission reactions very rarely occur. Nuclear fission reactions are normally initiated by bombarding the nucleus with slow neutrons or thermal neutrons of low energy of about 10-2 eV. Nuclear fussion: Nuclear fusion is the process in which two light nuclei combine to form a heavier nucleus.