Review Pre Cal

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Grade 9 Math Review Solutions p. 82 #5, 6, 7, 9, 10, 11, 12, 18, 19, 20, 21, 22 Chapter 2 Review Page 82 Question 5 = 8 = 0.125 = –4 = 1. = –1.5 – = –3 = –6.8 – = 15 So, , , , and cannot be expressed as integers. Chapter 2 Review Page 82 Question 6 a) Divide the numerator and denominator by 3. = = So, = . b) –0.86 is to the left of –0.84 on the number line. Therefore, –0.86 < –0.84. c) = –0.6 –0.6 is to the right of –0.666… on the number line. Therefore, –0.6 > –0.666… d) –1 = = Therefore, –1 = . e) = = –0.7 –0.7 is to the left of on the number line. Therefore, > . f) –2 = –2.8 –2 = –2.875 –2.8 is to the right of –2.875 on the number line. Therefore, –2 > –2. Chapter 2 Review Page 82 Question 7 a) Example: Axel wrote each fraction in an equivalent form, so both fractions had a common denominator. He then compared the numerators to find that –6 < –5. –1 < –1 b) Example: Bree wrote as –1.5 and –1 as –1.25. She compared the decimal portions to find that –1.5 < –1.25. c) Example: Caitlin compared and and found that < . So –1 < –1. d) Example: Caitlin’s method is preferred. It involves fewer computations. Chapter 2 Review Page 82 Question 8 Example: If the fraction must be between 0 and –1, it must be negative. If its numerator must be 5, its denominator must be –6 or smaller. and Chapter 2 Review Page 82 Question 9 a) –5.68 + 4.73 = –0.95 b) –0.85 – (–2.34) can be rewritten as –0.85 + 2.34. Subtracting –2.34 is the same as adding the opposite of –2.34. –0.85 + 2.34 = 1.49 c) 1.8(–4.5) = –8.1 d) –3.77 ÷ –2.9 = 1.3 Chapter 2 Review Page 82 Question 10 a) 5.3 ÷ (–8.4) = –0.6 (rounded to the nearest tenth) b) –0.25 ÷ (–0.031) = 8.1 (rounded to the nearest tenth) c) –5.3 + 2.4[7.8 + (–8.3)]

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