Pt1420 Unit 2 Exercise 1

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-1 ≤ -3 +2x< 17 Initial inequality -1+3≤-3+3 +x2x<17+3 add 3 to all numbers separated by the ≤ and < 2≤2x<20 totals with 3 added must be divided by 2 to find x 2≤2x<20 divided by 2 2 2 2 1≤ x < 10 The value of x is greater than or equal to 1 and less than 10. 1≤ x < 10 as an intersection will look like this: <----------------[------------------------------]--------------> 0 1 10 Since the one is equal to or less than ex the bracket stops at one and since x is greater than ten it continues on the bar past 10 since the number is not 10. My or inequality is 7-x ≥6 or 7x-1>27 7-x ≥ 6 7-7-x≥6-7 subtract 7 from both sides -x≥-1 cannot have a negative variable so both sides are divided by -1…show more content…
This is the first part the second part of the or equation is 7x-1>27 7x-1>27 7x-1+1>27+1 add one to both

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