276 Words2 Pages

-1 ≤ -3 +2x< 17 Initial inequality
-1+3≤-3+3 +x2x<17+3 add 3 to all numbers separated by the ≤ and <
2≤2x<20 totals with 3 added must be divided by 2 to find x
2≤2x<20 divided by 2
2 2 2
1≤ x < 10
The value of x is greater than or equal to 1 and less than 10. 1≤ x < 10 as an intersection will look like this: <----------------[------------------------------]--------------> 0 1 10
Since the one is equal to or less than ex the bracket stops at one and since x is greater than ten it continues on the bar past 10 since the number is not 10.
My or inequality is 7-x ≥6 or 7x-1>27
7-x ≥ 6
7-7-x≥6-7 subtract 7 from both sides
-x≥-1 cannot have a negative variable so both sides are divided by -1*…show more content…*

This is the first part the second part of the or equation is 7x-1>27 7x-1>27 7x-1+1>27+1 add one to both

This is the first part the second part of the or equation is 7x-1>27 7x-1>27 7x-1+1>27+1 add one to both

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