You can us+e the weight on each pully to calculate the magnitude and the direction of the component vectors at 90 and 0 degrees. For part c you need to find the components of triangles a, b, and c as labeled on the front bottom of my lab. You then need to find the sum all the x component and y component vectors. Then from the sum of the components you can use the Pythagorean theorem to find the resultant vector R. Data: part a experimental ax= 875g*m/s^2 ay = 980g*m/s^2 the theoretical values for ax and were
PK-S Lab 03 – Lab Report Name: ____________________ Section: ___________________ EXPERIMENT 3: Trigonometric Measurements Procedures: 1. Experimental measurement of the angles and sides of a right triangle: A. Create a triangle by taping a string against a wall and taping the bottom of the string to the floor or a table set against the wall. Make sure that the wall is perpendicular to the floor or table by measuring angle C, which should be 90o. B.
EXPERIMENTAL DATA: Table 1: Measured values from experimental data Resistor Measured Value 101 Ω Capacitor 1 μF Amplitude of voltage 5v Phase difference 58.752º Peak to peak voltage 10 v Amplitude of current 2.53 mA ANSWERS TO THE POST LAB REPORT: Q. 1. Dividw the amplitude of the signal generator voltage measured by the oscilloscope by √ and compares it with the measured value by voltmeter. Answer: Here given, Vm = 5 V Dividing Amplitude of voltage Vm by √2, 5 √2 = 3.54 Comment: Both values were not matching. There have more than 10% discrepancy.
Procedure 3: The Compound Pendulum The aim of this experiment is to determine the value of the acceleration due to gravity by measuring the period of oscillation of the pendulum when suspended from different distances from its centre of mass. A pendulum consisting of any swinging rigid body which is free to rotate about a fixed horizontal axis is called a compound pendulum. This experiment had to be carried out at Glasgow University as the required equipment was not available at school. Procedure 1) The pendulum was balanced on a large brass knife edge to determine the position of the centre of mass of the pendulum. 2) The larger moveable knife edge was then clamped to the pendulum, at a small distance (1cm) above the centre of mass.
Data: Isotope | M & M’s | Skittles | Reece’s Pieces | Number of Particles | 35 | 27 | 49 | Mass (g) | 0.85g | 1.03g | 0.74g | Calculations: Percentage of abundance: Reece’s: 49/111= 0.44 x 100= 44% Skittles: 27/111= 0.243 x 100= 24.3% M & M’s: 35/111= 0.31 x 100= 31% Average Atomic mass: (44 x 0.74g) + (24.3 x 1.03g) + (31 x 0.85g)= 83.94g Conclusion: Candium had three isotopes, Reece’s Pieces, Skittles, and M & M’s. The atomic mass of the model element Candium was measured and calculated in the experiment. . The mass and
Physics 1408 Section E1 Standing Waves in a Vibrating Wire Callie K Partner: Miguel E Date Performed: March 20, 2012 TA: Raziyeh Y Abstract This lab had two purposes. The first was to determine the relationship between the length of a stretched wire and the frequencies at which resonance occurs. The second was to study the relationship between the frequency of vibration and the tension and linear mass density of the wire. In the first part we found the resonance, frequency and wavelength of a wire and used this data to calculate the speed of the traveling waves. For first harmonic, our wavelength was 1.200 m, found by the formula λ=2L/n.
Through both qualitative observation, and our quantitative data, we deduced that the shorter the length of a pendulum, the smaller its period. At the longest length 42cm, the period was 1.33s. Each progressing length: 33.5cm, 30cm, 22cm, and 11cm yielded smaller and smaller periods of 1.16s, 1.15s, 0.96s, and 0.68s respectively. In our first graph of Period vs. Length, we plotted the points and discovered that it formed a root curve.
Pencils and paper to record data. In the first experiment the ball’s line trace was straight but when we rotated the turn table counter clock wise the line was not straight but curved from the deflection. QUESTIONS: 1. If you look at earth from above the North Pole does it rotate clockwise or counter Clockwise? If you look at the earth from above the North Pole ti rotates counter clock wise.
Both of these formulas were found on page 225 in Mathematics in Our World (Bluman, 2005). Problem #37 • This sequence is geometric • Ending balance is $814.45 STEPS/CALCULTATIONS YOU PERFORMED TO REACH THE ANSWER: To find the ending balance, the formula of An = a1(rn-1) will be used. The initial balance is $500, the interest is 5%, and the time span is 10 years. 5% will be listed as 1.05 as the initial balance is 100% plus 5% interest, so 105% is written 1.05. The number of terms is n=10, the first term is a1=525, the common ratio is r = 1.05.
Here is how we think about it: It is $100 for the first 10 feet. After that it is $25 for each additional 10 feet. This tells us that it is arithmetic sequence because we are multiplying. N= the number of terms altogether N= 8 D= the common difference D=25 A1= the first term A1= 100 An= the second term An= a8 Next, we need to compute what a8 is. An= a8+ (n-1) d A8= 100+ (8-1)25 A8=100+7(25) A8=100+200 A8=300 Now that we know what A8 is, we need to know what the sum of the sequence is from A1 to A8.