755 Words4 Pages

Writing Assignment 4: worksheet for Flygene computer simulation of genetic crosses (20 points)
Name: FlyGene unknown code: 629
PS ID #: Lab Section: 15698
BIOL 3311 Spring 2013 TA Instructor Name: Igor Bado
Date: 2/19/13
Discriminant Cross 1 (DC1)
Parental Genotypes: Female: XN Male: Cy Pm; D Sb
F1 progeny (NOTE, NOT all crosses will have 8 classes): Class | Phenotypes | Females | Males | 1 | CYDD | 1008 | 1019 | 2 | CYSB | 1013 | 1009 | 3 | DDPM | 990 | 1004 | 4 | PMSB | 993 | 1014 | | | | | | | | | | | | | | | | | | Totals: | 4004 | 4046 |
Hypothesis after DC1: XN is an autosomal recessive gene.
DC1 Chi Square Analysis: Class | Phenotypes | Observed | Expected | O - E |*…show more content…*

Calculate Expected Values for MCA: Parental: 3396 Recombinant: 596.5 Mapping Cross A Chi Square Analysis: Class | Phenotypes | Observed | Expected | O - E | (O - E)2 | (O - E)2/E | 1 | XN | 3396 | 3396 | 0 | 0 | 0 | 2 | CC | 3396 | 3396 | 0 | 0 | 0 | 3 | XNCC | 602 | 596.5 | 5.5 | 30.25 | 0.0507124 | 4 | ++ | 591 | 596.5 | -5.5 | 30.25 | 0.0507124 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | Total | | | | X2 = | 0.10142497 | Conclusions: With df=3, p=0.05, my critical value is 7.815 and since my X2 is less than my critical value, I accept the hypothesis that XN is 14.94 mu away from c on chromosome 2. Mapping Cross B (MCB): Marker gene: speck (sp) Chromosome: 2 Map Location: 107.0 Parental Genotypes: Female: XN/sp Male: XN/XN F1 progeny (NOTE, NOT all crosses will have 8 classes): Class | Phenotype | Females | Males | 1 | XN | 1660 | 1660 | 2 | SP | 1664 | 1656 | 3 | XNSP | 342 | 340 | 4 | ++ | 337 | 341 | | | | | | | | | | | | | | | | | | Totals: | 4003 | 3997 | Total Progeny: 8000 Total Parental Progeny:

Calculate Expected Values for MCA: Parental: 3396 Recombinant: 596.5 Mapping Cross A Chi Square Analysis: Class | Phenotypes | Observed | Expected | O - E | (O - E)2 | (O - E)2/E | 1 | XN | 3396 | 3396 | 0 | 0 | 0 | 2 | CC | 3396 | 3396 | 0 | 0 | 0 | 3 | XNCC | 602 | 596.5 | 5.5 | 30.25 | 0.0507124 | 4 | ++ | 591 | 596.5 | -5.5 | 30.25 | 0.0507124 | | | | | | | | | | | | | | | | | | | | | | | | | | | | | | Total | | | | X2 = | 0.10142497 | Conclusions: With df=3, p=0.05, my critical value is 7.815 and since my X2 is less than my critical value, I accept the hypothesis that XN is 14.94 mu away from c on chromosome 2. Mapping Cross B (MCB): Marker gene: speck (sp) Chromosome: 2 Map Location: 107.0 Parental Genotypes: Female: XN/sp Male: XN/XN F1 progeny (NOTE, NOT all crosses will have 8 classes): Class | Phenotype | Females | Males | 1 | XN | 1660 | 1660 | 2 | SP | 1664 | 1656 | 3 | XNSP | 342 | 340 | 4 | ++ | 337 | 341 | | | | | | | | | | | | | | | | | | Totals: | 4003 | 3997 | Total Progeny: 8000 Total Parental Progeny:

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