| The legs have length '24' and 'X' are the legs. The hypotenuse is 26. See Picture | The hypotenuse is red in the diagram below: Step 2) Substitute values into the formula (remember 'c' is the hypotenuse) | A2 + B2 = C2 x2 + 242 = 262 | Step 3) Solve for the unknown | | Problem 1) Find the length of X | | Step 1 | Remember our steps for how to use this theorem. This problems is like example 1 because we are solving for the hypotenuse . Step 1) Identify the legs and the hypotenuse of the right triangle.
x and c-x, then the diagram looks as follows: The perpendicular has divided the triangle into two right-angled triangles. Now for any right-angle triangle, according to Pythagorean Theorem, [pic] = [pic] + [pic] If Pythagorean is applied to the right-angled triangles in the above triangle, then in the case of left right-angle triangle in the above diagram, it would give us the equation [pic] = [pic] + [pic] where ‘a’ = hypotenuse and ‘h’ = height/perpendicular and ‘x’ = base. Re-writing it, the equation would become which we will call Eq. A [pic] = [pic] - [pic] ---------------------( Eq. A Similarly, for the right angle triangle on the right half to triangle ABC, [pic] = [pic] + [pic] where ‘b’ = hypotenuse, ‘h’ = height/perpendicular and ‘c-x’ = base.
As per the textbook, what test can we use to determine whether a graph is a function or not? The vertical line test . Piecewise Functions: 3. The following graph displays the rates of a computer repairperson: The rates are described by the following piecewise function: fx=$50 if 0≤x≤6043x-30 ifx>60 Use this function to answer the following questions: a. What is the cost if the repairman works for 45 minutes?50$ Reason is : Because it lies between the range 0 to 60, under this function it returns the value 50 b.
Solve the triangle. Given: A = 48° C = 97° a = 12 B = 35° b = 9.2 c = 16.0 5. The given measurements produce one triangle. Given: a = 7, b = 5, A = 70° C = 67.8, B = 42.1, c = 6.8 6. x×tan62 = (x+300)×tan53 = perpendicular x = 300×tan53/(tan62-tan53) = 719.0295 yards AB = (x+300/cos53 = 1019.0295/cos53 = 1693.3 yards Distance between A and B is 1693.3 yards 7. Given: sides, 5,6,7 in miles Island A = 78.46° Island B = 135.58° Island C = 57.12° Given the information… From Island B I would travel a Northwest Bearing to Island C. 8.
Begin by writing the corresponding linear equations, and then use back-substitution to solve your variables. 10–1301–8001 159–1 x,y,z=( , , ) 10–1301–8001 159–1 = x-13z=15y-8z=9z=-1 = x-13(-1)=15y-8(-1)=9z=-1 = x=2y=1z=-1 x,y,z=(2 , 1 , -1) Determinants and Cramer’s Rule: 2. Find the determinant of the given matrix. 8–2–12 8–2–12 = 8*2 - (-1)(-2) = 16 - 2 = 14 3. Solve the given linear system using Cramer’s rule.
Write a paragraph describing the relationship between triangles and circles. Be sure to include a description of the different centers a triangle can have. Answer: Circles can be found in triangles. They can be found inside outside triangles too. The circles located on the inside are called inscribed circles, inscribed circles should touch each side of the triangle at a single point.
Problems Answer Grade Problem-1 a x+y=56 /3 b x+y=56 x+3x=56 56/4= 14 x=14 56-14=42 y=42 check 14+42=56 or 14+(14*3)=56 /3 c before we use elimination, we simplify the second equation by dividing by 25,000: new equation for b): 7x + 8y = 288 in order to eliminate a variable, multiply the first equation by -7: new equation for a): -7x + -7y = -266 Elimination: add the two equations and the x's cancel out: y = 22 x = 38-22 = 16 /3 d For the first equation, the intercepts are (56, 0) and (0,56). The intercept for the second equation is (0, 0). The lines would intersect at (14, 42) /3 Problem-2 a x+y=38 /3 b $175,000x+$200,000y=$7,200,000 /3 c Before we use elimination, we simplify the second equation
ANSWERS page 1 page 2 ELL Support 1-1 1-1 Nets and Drawings for Visualizing Geometry folds into a solid right-side view Nets and Drawings for Visualizing Geometry Multiple Representations There are eight different nets for the solid shown at the right. Draw as many of them as you can. (Hint: Two nets are the same if you can rotate or flip one to match the other.) Add the phrases to the web. Place them where you think they should go.
Show your working. 3 t + 4 = t + 13 t= 2 marks 2 (3n + 7) = 8 n= 1 mark KS3/03/Ma/Tier 6–8/P1 3 Shapes 2. The drawing shows how shapes A and B fit together to make a right-angled triangle. Work out the size of each of the angles in shape B. Write them in the correct place in shape B below.
Pythagorean Triples and Theorem Equation Constance Hall Lindemann Survey of Mathematical Methods Instructor: David Gualco January 20, 2012 The Pythagorean Theorem comprises a right triangle, its hypotenuse c and other two sides a and b. within this paper I will provide several examples of and describe the steps taken to find Pythagorean Triples and using the examples found in the text on page 559 item 10-9. To understand Pythagorean Triples you must first recognize that this is expressed as a^2 + b^2 = c^2 within math circle. What is the Pythagorean Theorem? The Pythagorean Theorem comprises a right triangle, its hypotenuse c and other two sides a and b. It then has a right triangle, an triangle which has a one 90-degree angle.