The chemical reaction used to find this constant is as follows: MgC2O4 (s) ↔Mg(aq)2++ C2O4 (aq)2- Kc= Mg2+[C2O42-][MgC2O4] Ksp=Mg2+[C2O42-] The solid salt magnesium oxalate is prepared through the following precipitation reaction: Mg(SO4)(aq)+NaC2O4 (aq) → MgC2O4 (s)+NaSO4 (aq) Next, the concentration of the Mg2+ and C2O42- ions is found through a redox titration. This redox titration uses a standardized potassium permanganate solution. The potassium permanganate solution is standardized by titrating it with samples of iron(II)ammonium sulfate hexahydrate . The end point is reached when the solution has turned light purple which is a result of excess amounts of MNO4-. This reaction can be summed up using the following formula: 5Fe2++8H++MnO4- →5Fe3++Mn2++4H2O After standardization, the potassium permanganate solution is then titrated with 3 different magnesium oxalate solutions.
With the use of this technique we placed chlorine, bromine, and iodine into solutions containing chloride, bromide, and iodide. In the reaction the free halogen (X2) oxidizes the other halide ion (Y-) and gets reduced by gaining electron(s). In table 3, chlorine was the strongest oxidizing agent and iodine was the weakest oxidizing agent. Since chlorine was the strongest oxidizing agent it will react more and the weak agent will react less. This explanation can be demonstrated in table 3 also because the results of the reactions demonstrates that chloride reacted more by the color of the product compared to the color of chloride in the mineral oil.
(4 points) n = 125 4. If magnesium was the limiting reactant in this lab, calculate the theoretical yield of the gaseous product. Show all steps of your calculation. (4 points) Moles of Mg: (0.0281 g)(1 mole / 24.305 g) = 1.156 x 10^-3 moles 5. Determine the percent yield of this reaction, showing all steps of your calculation.
The purpose of the lab was to determine which reactant was the limiting reactant, and to see how much of the other reactant was used. The true molarity of a compound can be defined as the amount of moles per liter of that substance. The equation of this single displacement chemical reaction done during this lab is 2Al(s) + 3CuCl(aq) → 3Cu (s) + 2AlCl2 (aq). In the reaction, the solid Aluminum replaces the Copper in Copper (II) Chloride to produce solid copper, and Aluminum Chloride. In order to find which reactant is the limiting reactant, an equation based on the molarity of the Copper (II) Chloride may be used, or the products of the reaction may be observed.
In well A2: Place 10 drops of Magnesium Sulfate, MgSO4 c. In well A3: Place 10 drops of Zinc Nitrate, Zn(NO3)2 d. In well A4: Place 10 drops of Iron (III) Chloride, FeCl3 e. In well A5: Place 10 drops of Copper (II) Sulfate, CuSO4 3. Take the metal solids from your LabPaq; there should be one piece each of magnesium, zinc, and iron plus two pieces of lead. NOTE: Magnesium and lead oxidize very easily and an almost invisible oxidation layer may coat the metal. To insure good reactions you should scrape the surface of those metals with a pocketknife or remove the oxidation layer by rubbing the metal pieces with steel wool or something similar. Evidence that a reaction is taking place is the formation of bubbles or a coating on the metal immersed into the solution.
Aim To compare the reactivity of various metals by observing their reaction with hydrochloric acid Hypothesis That the all the metals will produce foam and a pop. Variables Independent – Magnesium, Aluminium, Zinc, Copper Dependent – Detergent, Hydrochloric Acid Controlled – Size of the metals, amount of detergent and hydrochloric acid Materials 2 M hydrochloric acid Detergent 10 x test tubes and test tube rack and 5 rubber stoppers 0.5 cm pieces of magnesium, aluminium, zinc and copper 2 cm pieces of magnesium, aluminium, zinc and copper Steel wool Ruler Timer Bench mat Matches and birthday candle Marking pen Safety Remember to wear safety glasses and protective gloves when you do this experiment. 2 M HCl is corrosive. Wash with plenty of water should you get any on your skin or in your eyes. Method Part 1 1 Clean the surface of the 0.5cm piece of magnesium with a piece of steel wool 2 Place the magnesium into a test tube 3 Add three drops of detergent to the test tube 4 Add 2 cm of hydrochloric acid to the test tube.
CHEMISTRY Name _____________________________ Lab - Molar Volume of a gas lAB 12 OBJECTIVE OF THE LAB: The purpose of this lab is to determine the molar volume of a sample of Hydrogen gas that is created through the reaction of Magnesium and Hydrochloric Acid. The concept of molar volume is that 1 mole of a gas occupies 22.4 liters at STP. Unfortunately the conditions of the lab are not at STP. You will have to use gas law formulas to calculate the volume that one mole of this gas would occupy at STP. In addition, since this lab is being done over water, and water will evaporate at any temperature, the vapor pressure of water must be determined.
Molecular, Ionic and Net Ionic Equations 1. Strontium compounds are often used in flares because their flame color is bright red. One industrial process to produce low-solubility strontium compounds (that are less affected by getting wet) involves the reaction of aqueous solutions of strontium nitrate and sodium carbonate. Write the balanced molecular equation, the total ionic equation, and the net ionic equation for this reaction. 2.
Experimental Design: - Independent Variable: different types of metals: magnesium, zinc and Copper - Dependent Variable: amount of reactants observed for each metal - Control : The Air -Constants: The amount of chemical solutions, the time the metals were in the chemical solutions and size of each metal during the experiment 4. The Dependent variable, the number of reactions the metal will receive and will be measured based on their reactivity. The higher the reactant, the more reactions and the less reactive the less amount of reactions The Independent variable, the different metals that are tested by observing for chemical change. Once the metals which are magnesium, copper and zinc are put into the 3 different solutions along with the control which is water and air, we will be able to determine if they do