Which position-time graph represents an object with an increasing velocity moving in a westward direction? a.|| b.|| c.|| d.|| ____ 6. A car is passing another car on the highway. It increases its velocity from 12 m/s [E] to 21 m/s [E] over a time interval of 10 s. What is the car’s average acceleration? a.|0.6 m/s2| b.|0.9 m/s2| c.|0.3 m/s2| d.|1.9 m/s2| ____ 7.
(F) frequency variable? Jog a mile in 10 minutes 3 times a week. 2. (I) intensity variable? Jog 1.1 miles in 10 minutes 3.
K12_1821161 $100 Answer from 1 Jan 9, 2014 1:03:23 PM Page 6. Blackboard Collaborate ?? K12_1821161 $200 Question from 1 Jan 9, 2014 1:03:23 PM
Cowan 2 At the 10° incline of the ramp for the distance of 96 centimeters (cm), the average time was 1.04 seconds (s). For the first trial at this distance, the time was 1.09s, the second trial time was .88s, and the third trial time was 1.16s. For the distance of 80cm, the average time it took the ball to roll down the ramp was .86s. For the first trial the time was .86s, the second trial time was 1.01s, and the third trial time was .70s. For the distance of 64cm, the average time it took the ball to roll down the ramp was .62s.
100 Part II: Principle of Progression If you were able to jog one mile in 10 minutes, how would you progressively increase your performance by using of the following? 1. (F) frequency variable? A 10 minute mile twice. 2.
A: 40,500/10=4050 B: 33,600/9=3733 C: 36,000/8=4500 D: 19,000/7=2714 E: 23,500/6=3916 Total Straight-line depreciation = $18,913 Total Cost = $152,600 Depreciation Rate = 18,913/152,600 = 12.4% (b) Prepare the adjusting entry necessary at the end of the year to record depreciation for the year. Depreciation – Plant Assets 18,913
Calculate the area (in square miles) of the white space, which is a quarter of a quarter of a section at: NE 1/4, NE 1/4, S 24, T3N, R2E? (6 points) A: 1/16 sq mile CONTOUR LINES 4. What is the contour interval on this map? (4 points) A: The contour interval on this map is 20. 5.
Week 1 Assignment Ashford University BUS 640: Managerial Economics Instructor: Marlo Chavarria September 10, 2012 Chapter 1: Applied Problem 1 A) Explicit Cost Total operating costs and expenses $555,000 Interest expenses $45,000 Income taxes $28,000 Net Income $165,000 Total Explicit Costs for 2010 $793,000 Implicit Costs Annual Salary $175,000 15% interest on a $100,000 investment $15,000 Total Implicit Costs for 2010 $190,000 Economic Costs Total Explicit Costs $793,000 Total Implicit Costs $190,000 Total Economic Costs for 2010 $983,000 B) Accounting Profit Revenue $970,000 Operating costs and expenses -$555,000 Interest Expenses -$45,000 Income Taxes -$28,000 Net Income -$165,000 Total Accounting Profit for 2010 $177,000 C) D) Chapter 2: Applied Problems 2 A) In knowing that Florida faces a major freeze in which the price of oranges and quantity of produce will fall below. B) In knowing that new technological development has occurred in which the amount of oranges will increase and the cost of oranges will decrease. If the suppliers can reduce or cut back their supply then it would lead to more sales and increase in supply. So therefore if technology is not made for everyone meaning all suppliers then this could affect these suppliers in their financial and could even lead them to lose their business. C) If the AMA announces that drinking orange juice can reduce the risk of heart attacks then this could cause a huge increase in demands and could also lead an increase in price or price could stay neutral temporarily but the supply would decrease the price later on the line.
This is a manual problem! t = 16 therefore the forecast for the year 2006 = 80 + 16*15 = 320 thousand bottles #4: Freight car loadings over a 12-year period at a busy port are as follows: The units are in thousands of tons. Year 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 a. Loadings 220 245 280 275 300 310 350 360 400 380 420 450 460 475 500 510 525 541 Determine the linear trend equation for the freight car loadings. Forecast = 208.48 + 19 * year b. What is the slope?
1. Days to repair As we know, the number of days in which the copier can be repaired is random. So, we will generate some random numbers between 0 and 1 and denote it by r1 then according to the given probability distribution: If 0 < r1 < 0.2, then it will take one day to repair the copier. If 0.2 < r1 < 0.65, then it will take two days to repair the copier. If 0.65 < r1 < 0.90, then it will take three days to repair the copier.