Objective To determine of heats from three exothermic reactions and investigate the Hess Law Summary Based on this experiment, we have study three related exothermic reactions involving sodium hydroxide. The first reaction (Part A), solid sodium hydroxide will dissociate into water. The heat produce by this reaction (∆H1) and this called as the heat of solution of solid NaOH. From the experiment we have managed to determined that ∆H1 = -41.84 KJ/mol In the second reaction (Part B), an aqueous solution of NaOH is allowed to react with an aqueous solution of HCl. This is a neutralization reaction between a strong acid and strong base.
Write a balance equation for the above reaction B. Which of the 2 reactants is the limiting reagent? C. Calculate the mass of aluminium oxide formed D. How much excess reagent is left at the end of the reaction? E. If the actual yield of ammonium oxide formed was 980g what is its yield % ANS a. 2Al + Fe2O3 ( Al2O3 + 2Fe (26.98) ( 159.7) (101.96) 124 601 80 b. Al c. 234.3 d. 234 e. 34.1% 1c.
Is There a Change in Temperature when an Alkali Neutralizes an Acid? Aim The aim of the experiment was to find out if there was a change in temperature when we added an alkali (Sodium Hydroxide) to an acid (Hydrochloric Acid) to neutralize it. Hypothesis We hypothesized that there was going be a raise in temperature as we add 1ml of Sodium Hydroxide at a time to the Hydrochloric Acid due to the neutralization of the acid. The neutralization is chemical reaction that causes an exothermic reaction. Sodium Hydroxide + Hydrochloric Acid Sodium Chloride + Water NaOH(aq) + HClaq → NaCl(aq) + H2O(l) Variables Independent The independent variable of the experiment was the amount of sodium hydroxide that we added to the acid.
1. Calculate the average atomic mass of silver using the following data: |Isotope |Abundance |Mass | |107Ag |51.84% |106.9051amu | |109Ag |48.16% |108.9048amu | |106.91 amu • 107.87 amu • 108.00 amu • 108.90 amu What is the average mass of one S atom? • 32.07 g • 32.07 amu • 32.07 g/mol • 32.07 mol What is the mass of 3.50 x 1024 Ti atoms? • 47.9 amu • 47.9 g • 5.81 g • 278 g How many C atoms are in 5.50 g of C? • 5.01 x 1022 C atoms • 2.76 x 1023 C atoms • 3.31 x 1024 C atoms • 5.50 x 1023 C atoms How many Cl atoms are in 0.0728 g of PCl3?
The temperature was raised to 70 degrees Celsius and 4.419 g of salicylic acid was measured out on a balance and transferred into a 125. mL Erlenmeyer flask. Next, 8.00 mL of acetic anhydride was measured out and poured into the flask containing salicylic acid, ten drops of phosphoric acid was placed inside. The flask was then immersed into the hot water bath for twenty minutes. A vacuum filtration system was set up and the contents of the flask was transferred onto the filter paper. The mass of the filter paper and watch glass was 42.7131 grams.
Synthesizing Cyclohexene by Dehydrating Cyclohexanol Abstract 12.0mL of 85% phosphoric acid, 10.0mL of cyclohexanol and heat were used to perform an alcohol dehydration reaction and produce 5.85g of cyclohexene. The percent yield was found to be 74.84% after being washed with 10% sodium carbonate and dried with anhydrous Na2SO4. IR was used, along with a bromine test to confirm the identity of the newly formed cyclohexene. Introduction In organic chemistry, many different functional groups exist that have tendencies to react with each other in specific ways. Four main types of reactions relevant to this experiment are uni/di-molecular nucleophilic substitution (SN1 and SN2) and uni/di-molecular elimination (E1 and E2).
Synthesis and Derivitazation of a Chalcone Introduction Chalcone is prepared for this experiment by aldol reaction of aldehyde and an acetophenone. Chalcone is synthesized to other reactions such as isoxazole, chalcone dibromide, and chalcone oxide. In these synthesizing experiments filtration and recrystallization takes place. The filtration is done to separate the solvent from the sample. With increasing temperatures the solute can be dissolved by a solvent during recrystallization.
Lastly, the final product was analyzed by mass spectrometry and HNMR. Reaction setups: Drawing of the new apparatus is attached. Spectra: Please see attached GC-MS and HNMR. Calculations: Mechanism: Conclusion: The hydroboration-oxidation reaction is a reaction that is used to form an alcohol from an alkene. In this reaction there were two isomers of an alcohol formed.
The ultimate goal of this experiment is to synthesize benzocaine from p-nitrotoluene. In order to achieve this, the following multiple steps will be employed: 1. The reduction of p-nitrotoluene to create p-methylaniline. The reducing agent for this phase is a metal –acid combination, tin and hydrochloric acid. 2.
Micro-scale Cannizzaro Reaction with 4-Chlorobenzaldehyde Name: Saoirse Treacy | Date: 11/11/14 | I.D. Number: 13379026 | | Abstract: This experiment illustrates the simultaneous oxidation and reduction of an aromatic aldehyde to form the corresponding benzoic acid and benzyl alcohol [1]. The aromatic aldehyde, 4-chlorobenzldehyde, is refluxed so that the Cannizzaro reaction takes place in order to synthesise an alcohol, 4-chlorobenzyl alcohol. These products are then isolated by extraction methods and purified by re-crystallisation. Introduction: This reaction is the redox disproportionation of an aldehyde to an equimolar mixture of primary alcohol and carboxylic salt when treated with a concentrated strong base [2].