No tenderness or pain was noted, No drainage, no perforation, no swelling or redness noted of the ear canal, Tympanic membrane is pearly gray, Shinny, translucent, non bulging or retracted. No impacted cerumen noted. Cranial Nerve 8 is intact with no auditory hearing loss. He was able to repeat words (Apple and Base ball). Good response to Rinne and Weber test, sound is symmetrical with no
Chem 112 Assignment for Chapter 19 1. Calculate ΔS° values for the following reactions by using tabulated S° values from Appendix B (Petrucci text) a) N2H4 (g) + H2 (g) → 2NH3 (g) b) 2Al (s) + 3 Cl2 (g) → 2 AlCl3 (s) c) Mg(OH)2 (s) + 2 HCl (g) → MgCl2 (s) + 2 H2O (l) d) 2 CH4 (g) → C2H6 (g) + H2 (g) 2. Use data in your Appendix B to find ΔH° and ΔS° values at 25°C to calculate ΔG° where ΔG° = ΔH° - T ΔS° for each of the following reactions. a) Ni (s) + Cl2 (g) → NiCl2 (s) b) CaCO3 (s, calcite) → CaO (s) + CO2 (g) c) P4O10 (s) + 6 H2O (l) → 4 H3PO4 (aq) d) 2 CH3OH (l) + 3 O2 (g) → 2 CO2 (g) + 4 H2O (l) Note: the following values ΔHf° (kJ/mol) S° (J/K) Ni (s) 0 29.9 NiCl2
Normally, net diffusion of both solute and water occurs until the concentration of water (and solute) is the same on both sides of the membrane (equilibrium). When the membrane is impermeable to solutes it creates a different result. In this situation, water diffuses from the side with lower solute concentration to the side with higher solute concentration. This continues until its concentration is the same on the two sides of the membrane. The movement of water leads to dramatic changes in the volumes of the two compartments.
Conditions that must remain constant in this experiment include the temperature of the water baths and the volume of peas and beads in the respirometers. The general gas law states that if temperature and volume remain constant, then the pressure of the gas will change in proportion to the number of molecules of gas present. 2. Water moves into the respirometer pipettes because as oxygen is consumed by the peas, the pressure within the pipettes will decrease and thus the negative pressure will draw the water into the pipette. It is important to correct the readings from the peas because the glass beads are used as a control in which no changes should occur in CO2 and oxygen levels due to their abiotic nature.
A con is the higher risk of destruction of normal body flora. Drug allergy, drug toxicity, and creation of resistant microorganisms are also facts that need to be taken into consideration. Narrow-spectrum antimicrobials can only target either Gram-negative or Gram-positive microorganisms or a small variety of microorganisms at the time used. A con is that the bacteria have to be indentified first, before treatment can start. The pros are the reduced risk of creating resistant microorganisms and less chance of harming the host.
If there are higher levels of potassium, then the resting membrane potential will be less than normal and an action potential will be not likely with the same amount stimulation. More voltage is needed. • Explain how hypokalemia will initially affect the resting membrane potential and the generation of an action potential. The resting membrane potential is based on the polarization of the cell. If there are lower levels of potassium, then the resting membrane potential will be higher than normal and an action potential will be more likely with less stimulation.
Therefore the two kinds of fatty acids compete for same enzyme complex; however, monounsaturated fatty acids are formed in greater concentration than VLCSFA. The reduction in the elongation of VLCSFA and a diet low in VLCSFA will slow the demyelination
They are both very soluble in alcohol and hexane so that doesn’t help, but in water ethyl ether is semi soluble and pentane is in soluble. This would make us lean toward pentane but we felt strongly that ethyl ether because of the density was a much better test because there is much less human error and the we asked about how do you decide if something is insoluble
Also, there is a limit of how much solute you can put in the solvent and you should not exceed that certain percentage. If you put too much solute and end up having more solute than the water, the freezing point will start going back up again because the solute won’t be able to dissolve within the solvent at such a big quantity. Another limitation is that the concentration of the solvent in the mixture should be at least 10% and if it’s lower, the freezing point depression might not be affected because the amount of solute used will be too low. Lastly, the solution must be cooled to a lower temperature than the pure solvent in order to freeze. If water was used as the solvent, it has a freezing point of 0 °C and the solution will freeze at even a lower temperature so you have to put it somewhere cool like a freezer.
Substances undergoing net diffusion are said to move down or with their concentration gradient. After time (dependant on the substance) the substance will become evenly distributed. This is what’s known as equilibrium, although random kinetic motion continues, there’s no further net diffusion. Certain attributes can affect diffusion, such as heat, this will make diffusion occur more rapidly due to transferring more energy to the molecules to move around faster. Also a larger concentration gradient produces a faster diffusion, and smaller molecules diffuse more rapidly than larger molecules.