Investigating a Factor That Affects the Output of a Potential Divider Circuit

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Monday 4th February Investigating a Factor that affects the output of a potential divider circuit Aim – My aim is to investigate different factors that affect the output of a potential divider circuit. Introduction – A potential difference, also called voltage, across an electrical component is needed to make a current flow through it. Cells or batteries often provide the potential difference needed. Potential difference is measured in volts, V. The potential difference across a component in a circuit is measured using a voltmeter. This must be connected in parallel with the component. The potential difference between two points in an electric circuit is the work done when a coulomb of charge passes between the points. You can calculate the size of a potential difference using this equation: V = W ÷ Q * V is the potential difference in volts, V * W is the work done (energy transferred) in joules, J * Q is the charge in coulombs, C * For example, what is the potential difference if 48 J of energy is transferred when 4 C of charge passes? * Potential difference = 48 ÷ 4 = 12 V Hypothesis- I predict that during the experiment, the resistor will resist and the output would be smaller coming from the resistor whereas the output from the thermistor would be much greater depending on the temperature of the water. I will test this theory by measuring the temperature of my water before the experiment and after. I will also keep a record of the outputs shown on my voltage metres coming from my thermistor and resistor. Equipment; Power pack – I used a power pack in my experiment instead of the mains plug. The reasons for this were could measure precisely the amount of volts I was using. The most important reason was the safety reason, using a power pack ensured that I did have too much voltage. If I did have a large amount coming through

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