In This Experiment Copper Chloride and Iron Chloride Are Separately Reacted with Sodium Hydroxide to Determine What Their Charge Is

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Introduction In this experiment copper chloride and iron chloride are separately reacted with sodium hydroxide to determine what their charge is. The copper chloride can be either copper (I) or copper (II) chloride. The iron chloride can either be iron (II) or iron (III) chloride. By completing a double replacement reaction with the sodium hydroxide the formulas of the iron and copper chlorides can be found. Objective The objective of this lab is to find the formula of an ionic compound. Materials: Copper Chloride Iron Chloride Sodium Hydroxide Well plate Indicator Toothpicks safety goggles pipets Procedures - collect materials label pipets according to the solutions inside. (CuCl, FeCl, NaOH, and the indicator) Using the pipet with the CuCl place 5 drops in the 5 wells in the well plate. Place one drop of indicator in those 5 wells. Starting on the 1st well place one drop of the NaOH at a time and mix with a toothpick until the NaOH has dissolved. Keep doing so until the color of the indicator remains. (bright pink) Repeat the same process for what still remains in the well plate. Repeat the same process with the iron chloride. (each time record the number of drops placed in the wells) Data: Analysis: a. CuCl+ NaOH -> NaCl+ CuOH b. CuCl2+2NaOH -> Cu(OH)2+2NaCl c. FeCl2+2NaOH -> Fe(OH)2+2NaCl d. FeCl3+3NaOH-> Fe(OH)3+3NaCl 1. The average number of drops of sodium chloride needed to react with copper chloride was 11 drops. 2. For the sodium hydroxide to react with the Iron Chloride, it took on average 21 drops of sodium hydroxide into the Iron Chloride. 3. To determine which copper chloride was being used (Copper (1) or Copper (II) we could look at the ratio of copper chloride to sodium hydroxide and if it is the same or closest, that is which chloride

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