How Does Alebra 2.1 Answer Key Ap Biology

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Answer Key

ALGEBRA 2 and TRIGONOMETRY

AMSCO

AMSCO SCHOOL PUBLICATIONS, INC.
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3/26/09

12:07 PM

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ANSWER KEY/ALGEBRA 2 AND TRIGONOMETRY
Copyright © 2009 by Amsco School Publications, Inc.
No part of this Answer Key may be reproduced in any form without written permission from the publisher except by those teachers using the AMSCO textbook ALGEBRA 2 AND
TRIGONOMETRY, who may reproduce or adapt portions of this key in limited quantities for classroom use only.
Printed in the United States of America
1…show more content…
9

8.
9.
10.
11.
12.

13.

Enrichment Activity 2-5: Investigating
Ratios and Growth Rate in Leaves
Students answers will all differ as they have different size leaves. If the length to width ratios are very similar, students should conclude that the rate of growth in their tree or bush is constant. If the length to width ratios vary a lot, they should conclude that the growth rate for their tree or bush is not constant.
Students should be assessed on the following characteristics: a. the accuracy of their measurement
b. the construction of their data table and scatter plot c. the accuracy of their computations with the calculator d. their knowledge of ratio and average
e. the neatness of their work
f. their ability to follow directions
g. how well they work with others if the activity is done as a group
h. their ability to reach a conclusion

Enrichment Activity 1-6: Factoring the
Sum and Difference of Two Cubes
1.
2.
3.
4.
5.
6.

a3 2 b3
5 a3 2 a2b 1 a2b 2 ab2 1 ab2 2 b3
5 a2( a 2 b) 1 ab ( a 2 b) 1 b2( a 2 b)
5 ( a 2 b)( a2 1 ab 1 b2)
(2x 1 y)(4x2 2 2xy 1 y2)
(x 2 2y)(x2 1 2xy 1 4y2)
(5 2 3d)(25 1 15d 1 9d2)
(4x 1 3y)(16x2 2 12xy 1 9y2) a4 2 b4
5 a4 2 a3b 1 a3b 2 a2b2 1 a2b2 2…show more content…
1

3
11. 4

14. 16
3

b
5. s 2 b 5 a 1 2 1 c 2 b
5 a 1 b 2 2b 1 c
2

15. 4 !3

12. 1
2

5c 1 a 2 b
2
b
6. s 2 a 5 a 1 2 1 c 2 a
1
5 a 2 2a 2 b 1 c

Enrichment Activity 13-4:
Solving Trigonometric Inequalities p p
1. p # x , p or 54 # x , 32
4
2 p 2. p , x , 32
2

5c 2 a 1 b
2
2
7. 1 2 cos C 5 ab ? c 1 a 2 b ? c 2 a 1 b
2
2
2
5 ab ( s 2 b)( s 2 a)

p
3. p # x # 32
2
p
4. p , x , p or 76 , x , 2p
6
p
5. a. p, 54
4
b. Graph y 5 sin x and y 5 cos x and identify intervals where the graph of sin x is below the graph of cos x. The solution is 0 # x , p or
4
5p
4 , x , 2p.

8. ( 1 1 cos C)( 1 2 cos C)

2
5 A ab B s( s 2 a)( s 2 b)(s 2 c)
2

2
1 2 cos2 C 5 A ab B s( s 2 a)( s 2 b)(s 2 c)
2

2 sin2 C 5 A ab B s( s 2 a)( s 2 b)(s 2 c)
2

2 sin C 5 ab !s(s 2 a)( s 2 b)( s 2 c)
(Reject negative root since the sine of any angle of any triangle is always positive.)

p
c. p # x # 54
4

6.
7.
8.

p
# x # 74 p p
, x , 56 or 76 , x , 11p
6
p
0 , x # p or p , x # 34 or p
4
2 p p or 32 , x # 74 p 4 p 6

9. Area 5 1ab sin C
2
2
5 1ab ? ab !s(s 2 a)( s 2 b)( s 2 c)
2

p
, x # 54

5 !s( s 2 a)(s 2 b)( s 2