MAT221: Introduction to Algebra Week 5 Discussion Factoring According to what I calculated, the GCF of 92 and 64 is 4. I found this answer by : Divisor 92 divided by 4 equals 23 and 64 divided by 4 equals 16. I used the factor of numbers to help me. 92/4=23 1,2,4,23,46,92 2/24 2/12 2/6 3/3 64/4=16 1,2,4,8,76,32,64 24=2x2x2x3 Prime factors are also know as natural numbers. It means a number that is more than one and I can only divide it by one, and has no remaining numbers.
WAMAP. Did you get close to 100% on a section of the WAMAP exercises? Yes No |Quiz1B.1. Consider the given graph of f(x). [pic] |Find the following limits (if they don’t exist, write DNE).
Math 471 Problem 1. Group Work #8 Fall 2011 (a): Find a recurrence relation for the number tn of bit strings of length n that contain three consecutive zeros. SOLUTION: We break up all of the bit strings of length n according to the following nonoverlapping cases: • Bit Strings Beginning with “1”: In this case, the three consecutive zeros must appear in the last n − 1 slots, and there are tn−1 bit strings that will have three consecutive zeros there. • Bit Strings Beginning with “01”: In this case, the three consecutive zeros must appear in the last n − 2 slots, and there are tn−2 bit strings that will have three consecutive zeros there. • Bit Strings Beginning with “001”: In this case, the three consecutive zeros must appear in the
( ....................... , ....................... ) [1] ( ....................... , ....................... ) [1] 185-02 Turn over. 10 Examiner only 7. (a) Use the following diagrams to write down two pairs of congruent shapes. [2] B A C D F G E H One pair of congruent shapes is Another pair of congruent shapes is ...................................... and
Randy Michael NT 1210 Lab 1.1 Professor Chibuzo Onukwufor 4/1/15 Lab 1.1 1: Convert the decimal value 127 to binary. Explain the process of conversion that you used. Decimal Number | Binary Number | Remainder | 127 - | 64 | 63 | 63 - | 32 | 31 | 31 - | 16 | 15 | 15 - | 8 | 7 | 7 - | 4 | 3 | 3 - | 2 | 1 | 1 - | 1 | 0 | Binary | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | Decimal | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | Conversion | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | I took the decimal and divided it by two giving 1 for the remainders and 0 if it did not have a remainder. 2: Explain why the values 102 and 00102 are equivalent. They are equivalent because they represent the powers of 10 3: Based on the breakdown of the decimal and binary systems in this lab, describe the available digit values and the first four digits of a base 5 numbering system.
Chapter 1 review questions 1. Which of the following is true about 1 bit? a. Can represent decimal values 0 through 9 b. Can be used to represent one character in the lowercase English alphabet c. Represents one binary digit d. Represents four binary digits 2.
Exercise 1.3.1 What is the decimal value of Byte 1 by itself? What is the decimal value of Byte 2 by itself? -6400 -233 Exercise 1.3.2 What is the decimal equivalent of the binary sequence in Figure 1- 12 (the combined sequence of Byte 1 and Byte 2 as a single decimal value)? How does this compare to the individual values of Byte 1 and Byte 2? -6633 -There is an increase of bits.
Show the steps of conversion that you used. Adding leading zeroes creates the number 001101102 which can be split into 00112 and 01102 the hexadecimal value for these two bytes are 316 and 616 respectively so this number would be 3616 Exercise 1.3.6 Represent the hexadecimal value f616 in binary and decimal. Show the steps of conversion that you used. F16 = 11112 and 616 = 01102 when put together the binary value is 111101102 which is equal to 246. Lab 1.3 review 1.
Assignment #2 1) Improve the result from problem 4 of the previous assignment by showing that for every e> 0, no matter how small, given n real numbers x1,...,xn where each xi is a real number in the interval [0, 1], there exists an algorithm that runs in linear time and that will output a permutation of the numbers, say y1, ...., yn, such that ∑ ni=2 |yi - yi-1| < 1 + e. (Hint: use buckets of size smaller than 1/n; you might also need the solution to problem 3 from the first assignment!) 2) To evaluate FFT(a0,a1,a2,a3,a4,a5,a6,a7) we apply recursively FFT and obtain FFT( a0,a2,a4,a6) and FFT(a1,a3,a5,a7). Proceeding further with recursion, we obtain FFT(a0,a4) and FFT(a2,a6) as well as FFT(a1,a5) and FFT(a3,a7). Thus, from bottom up, FFT(a0,a1,a2,a3,a4,a5,a6,a7)
Given is the augmented matrix of a system of equations: 1 5 6 2 7 1 3 5 1 5 7 13 Write the new form of the augmented matrix after the following row operations. R1 r1 r3 , R2 r2 7r3 6. Four times the number of white marbles exceeded 9 times the number of red marbles by 10. The ratio of blue marbles to red marbles was 3 to 1. There is a total of 65 marbles of all 3 colors.