2.12 b. 1.734 c. -1.740 d. 1.740 ANSWER: d -same process but now go to one tailed α=0.05 and dof = 17 4. Read the t statistic from the table of t distributions and circle the correct answer. A one-tailed test (lower tail), a sample size of 10 at a .10 level of significance; t = a. 1.383 b.
Type Your Name in the Report title. C. Page numbers should be RIGHT JUSTIFIED at the page bottom. D. Ensure you have at least 1” spacing all around. 1. Create a report that Sum Sales, Costs, and Profit by Region.
Interpret. From the scatter plot it is evident that the slope of the ‘best fit’ line is positive, which indicates that Credit Balance varies directly with Size. As Size increases, Credit Balance increases and vice versa. MINITAB OUTPUT: Regression Analysis: Credit Balance ($) versus Size The regression equation is Credit Balance ($) = 2582 + 404 Size Predictor Coef SE Coef T P Constant 2581.9 195.3 13.22 0.000 Size 404.13 51.00 7.92 0.000 S = 620.793 R-Sq = 56.7% R-Sq (adj) = 55.8% Analysis of Variance Source DF SS MS F P Regression 1 24200717 24200717 62.80 0.000 Residual Error 48 18498431 385384 Total 49 42699149 Predicted Values for New Observations New Obs Fit SE Fit 95% CI 95% PI 1 4602.6 119.2 (4363.0, 4842.2) (3331.6, 5873.6) Values of Predictors for New Observations New Obs Size 1 5.00 2. Determine the equation of the ‘best fit’ line, which describes the relationship between CREDIT BALANCE and SIZE.
From the CIA data set, we computed a 95% and 99% confidence interval factoring in the mean, standard deviation and the population sizes. For a 95% confidence interval, the true range of the data ranges from 89.61 to 95.13 (this represents a plus/minus range of 2.76). For
a) How many independent network servers would be needed if each has 99 percent reliability? independent failure rate = 0.01 combined failure rate = 0.00001 0.01^n = 0.00001 10^(-2n) = 10^-5 -2n = -5 n = 2.5 servers needed = 3 b) If each has 90 percent reliability? independent failure rate = 0.1 combined failure rate = 0.00001 0.1^n = 0.00001 10^(-n) = 10^-5 -n = -5 n = 5 servers needed = 5 5.74 Refer to the contingency table shown below. (a) Calculate each probability (i–vi) and explain in words what it means. (b) Do you see evidence that smoking and race are not independent?
(b) One correct answer to this part is as follows: We can say that we are 95 percent confident the average balance for all overdue bills is in the range from $480 to $520. Since the standard error SE for the sample mean should equal 100/square root of 100 = 10, the margin of error would be twice this value, or $20. This means $480 to $520 is a 95 percent confidence interval for the average of all overdue balances. Another correct answer to this part is as follows: Instead of the average balance, we can find the percentage of all balances that fall in this interval. When we think of all balances, $480 is 0.2 standard deviations below the average (480 -500)/100 = - 0.20), and $520 is 0.2 standard deviations above the average (520 -500)/100 = 0.20).
Both of these formulas were found on page 225 in Mathematics in Our World (Bluman, 2005). Problem #37 • This sequence is geometric • Ending balance is $814.45 STEPS/CALCULTATIONS YOU PERFORMED TO REACH THE ANSWER: To find the ending balance, the formula of An = a1(rn-1) will be used. The initial balance is $500, the interest is 5%, and the time span is 10 years. 5% will be listed as 1.05 as the initial balance is 100% plus 5% interest, so 105% is written 1.05. The number of terms is n=10, the first term is a1=525, the common ratio is r = 1.05.
This means that this problem can be solved cross multiplying the extremes and means of the problem. y – 1/x +3 = -3/4 This is the problem that we were given to solve for y. First we multiply both sides by x+3 so we will have y-1(x+3) =-3/4(x+3) Then we simplify so we are left with y-1= -3/4x+3 Then we add 1 to both sides which gives us y-1(+1) = -3/4x+ 3(+1) Now we simplify again which us leaves
Statistics 121 Problem set #1 1. Suppose {A, B, C, D, E, F} is a partition of the sample space Ω. Suppose it is known that P(A∪B∪C)= 0.6. The probability of event B is the same as the probability of event D. It is also known that P(A∪B)= P(E∪F)= 0.5 P(B∪C). Find the probabilities of the following events: a) B Solution: PA∪B∪C=0.6 ; PD∪E∪F=0.4 PB= PD = PA∪B= PE∪F = PA+ PB= PE+ PF = PA+ PB= 0.4- PD = PA+ PB= 0.4- PB = PA+ 2PB= 0.4 PA∪B= 0.5PB∪C 2PA+ 2PB= PB+ PC 0.4 + PA= PB+ PC 0.4 + PA+PA= PA+PB+ PC 0.4 + 2PA= 0.6 2PA= 0.2 PA= 0.1 PA+ 2PB= 0.4 0.1 + 2PB= 0.4 2PB=0.3 PB=0.15 b) c) A∪B∪D = PA+ PB+ PD = PA+ 2PB = 0.1 + 2(0.15) P(A∪B∪D)= 0.4 * I can’t find numbers 2, 3 and 4 5.
Economics 1480 Answer key #5 1) Rosen Chapter 12: problem 2 a. To maximize W, set marginal utilities equal; the constraint is Is + Ic = 100. So, 400 - 2Is = 400 - 6Ic. substituting Ic = 100 - Is gives us 2Is = 6 (100 - Is ). Therefore, Is = 75, Ic = 25. b.