# Hcs 438 Week 2 Assignment

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Thanks for completing HCS438 Week 2 Assignment at 7/21/2012 16:52:18. Questions | Your answer | 1. A 90th percentile means the percentage of values lower than this percentile value is: | 90 percent | 2. An outlier is not a legitimate value, and it indicates mistakes in a data set, and we must delete this value in data analysis. | Wrong | 3a. SD for the set of numbers: {6, 6, 6, 6, 6, 6, 6} | 0 | 3b. SD for the set of numbers: {5, 5, 6, 6, 6, 7, 7} | 0.816 | 3c. SD for the set of numbers: {5, 5, 5, 6, 7, 7, 7} | 1 | 3d. SD for the set of numbers: {3, 3, 3, 6, 9, 9, 9} | 3 | 4. Is the described plot a distribution? | No | 5. Is it very likely that the number of patients visiting will follow a normal distribution. | No | 6a. IQ question. The first mean (the mean for N=100): | 100 | 6b. IQ question. The second mean (the mean for N=400): | 100 | 6c. IQ question. The first SD (the SD for N=100): | 1.6 | 6d. IQ question. The second SD (the SD for N=400): | 0.8 | 7a. Twelve-sided dice. The mean for N=36: | 6.5 | 7b. Twelve-sided dice. The SD for N=36: | 0.575 | 7c. Twelve-sided dice. The mean for N=100: | 6.5 | 7d. Twelve-sided dice. The SD for N=100: | 0.345 | 8a. Perentile score for 99°F: | 0.89 | 8b. z score for 99° F: | 1.29 | 8c. Is a body temperature of 99.00°F “unusual”? Why or why not? | Not unusual, because it is within 2 standard deviations of the mean | 8d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98°F or lower? | 0.62 percent | 9a. Random numbers. A mean greater than 0.550: | 4 percent | 9b. Random numbers. A mean less than 0.480: | 25 percent | 9c. Random numbers. A mean between 0.450 and 0.550: | 92 percent | 9d. Random numbers. A mean between 0.480 and 0.530: | 60 percent | 10. What you observed and how it illustrates from the Central