(n.d.). What are Dominant and Recessive? Retrieved from
On comparing this equation with standard equation of ellipse with centre (h,k) which is given by x-h2a2+y-k2b2=1 , we have , h = 3 and k = -5. Therefore, coordinates of centre of ellipse = (3, -5). b) Given equation of ellipse. On comparing this equation with standard equation of ellipse with major axis 2a and minor axis 2b which is given by x-h2a2+y-k2b2=1 , we have, a2=64=>a=8 And b2=100=>b=10 Therefore, length of major axis = 2a = 2*8 = 16. And length of minor axis = 2b = 2*10 = 20. c) From part a) and b), we have a = 8 and b = 10 and h=3,k=-5 So, c2=b2-a2=102-82=100-64=36 =>c=sqrt36= 6.
CASES CONTROLS Genotype N Frequency N Frequency A/A 39 51% 55 44% A/G 35 46% 64 51% G/G 2 3% 7 6% Table 3 shows Allele frequencies of c.2756A>G polymorphism of MTR gene. CASES CONTROLS Allele N Frequency N
13. A white, square quilt has a purple square in the center. The side length of the purple square is (x − 5) inches and the width of the quilt is 60 inches. What is the area of the white part of the quilt? Prentice Hall Algebra 1 • Teaching Resources Copyright © by Pearson Education, Inc., or its affiliates.
RES342 Week 3 Quiz 1. A frequency distribution can be shown as • a statistic • a histogram • a scatter plot • a stem and leaf plot 2. Simple statistics are • for simpletons • presented in stem and leaf plots • things like correlations • things like standard deviations 3. What would you do with a median? • Use it do show spread.
Step 1) Identify the legs and the hypotenuse of the right triangle. | The legs have length '14' and 48 are the legs. The hypotenuse is X. See Picture | The hypotenuse is red in the diagram below: Steps 2 and 3 | Step 2) Substitute values into the formula (remember 'c' is the hypotenuse) | A2 + B2 = C2 142 + 482 = x2 | Step 3) Solve for the unknown | | Problem 2) Use the Pythagorean theorem to calculate the value of X. Round your answer to the nearest tenth.
It was found that a variation of the gene COMT occurred in 50% of male OCD suffered, 10% of female OCD sufferers and 16% of the general population. This suggests that there is a genetic base for OCD in males. Further evidence that OCD has a genetic basis comes from Menzies et al (2007). It was found that OCD patients and their first degree relatives had reduced grey matter in key regions of the brain including the OFC when compared to the general
a. | 4x + 3 | b. | –8x – 11 | c. | –8x + 3 | d. | 4x – 11 | ____ 12. What is the inverse of the given relation? .
C. Sum of the possible outcomes is 1.00. D. The outcomes are mutually exclusive. Ans: A 6) In which of the following distributions is the probability of a success usually small? A. Binomial B. Hypergeometric C. Poisson D. All distribution Ans: C 7) The difference between the sample mean and the population mean is called the A. Population mean.
As monozygotic twins have 100% of genes in common, it is suggested that the concordance rate for them is greater then dizygotic twins. Gottesman and Shields confirmed that the average concordance rate for monozygotic twins is 46% whereas is it only 14% in dizygotic twins. These averages were worked out from five studies that they conducted. Adoption studies can separate the environment from genes. An early adoption study by Heston in 1966 of 47 mothers with schizophrenia whose