8689 WordsApr 28, 201235 Pages

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123techbooks@gmail.com
IMPRTANT FORMULAS
PROBLEMS ON TRAINS:
1. Speed, Time and Distance:
Speed =
Distance
, Time =
Distance
, Distance = (Speed x Time).
Time Speed
2. km/hr to m/sec conversion: x km/hr = x x
5
m/sec.
18
3. m/sec to km/hr conversion: x m/sec = x x
18
km/hr.
5
4. If the ratio of the speeds of A and B is a : b, then the ratio of the the times taken by then to cover the same distance is
1
:
1
or b : a. a b
5. Suppose a man covers a certain distance at x km/hr and an equal distance at ykm/hr. Then, the average speed during the whole journey is
2xy
km/hr. x + y
1. km/hr to m/s conversion: a km/hr = a x
5
m/s.
18
2. m/s to km/hr conversion: a m/s = a x
18
km/hr.
5
3. Time taken by a train of length l metres to pass a pole or standing man or a signal post is equal to the time taken by the train to cover l metres. http://123techbooks.blogspot.com/ 123techbooks@gmail.com
4. Time taken by a train of length l metres to pass a stationery object of length bmetres is the time taken by the train to cover (l + b) metres.
5. Suppose two trains or two objects bodies are moving in the same direction at um/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
6. Suppose two trains or two objects bodies are moving in opposite directions at um/s and v m/s, then their relative speed is = (u + v) m/s.
7. If two trains of length a metres and b metres are moving in opposite directions atu m/s and v m/s, then: The time taken by the trains to cross each other =
(a + b) sec. (u + v)
8. If two trains of length a metres and b metres are moving in the same direction atu m/s and v m/s, then: The time taken by the faster train to cross the slower train =
(a + b) sec. (u - v)
9. If two trains (or bodies) start at the same time from points A and B towards each other and

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