Fin 571 Unit 4 Assignment

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Assignment One Answer 1. i) Range = 90 – 15 = 75 Mean = (15 + 24 + 30 + 45 + 66 + 90) / 6 = 45 Variance = ( (15 – 45)2 + (24 – 45)2 + (30 – 45)2 + (45 – 45)2 + (66 – 45)2 + (90 – 45)2 ) / 6 = 672 Standard deviation = √(672) = 25.923 ii) Range = 120 – 2 = 118 Mean = (2 + 29 + 49 + 67 + 90 + 109 + 120) / 7 = 66.571 Variance = ( (2 – 66.571)2 + (29 – 66.571)2 + (49 – 66.571)2 + (67 – 66.571)2 + (90 – 66.571)2 + (109 – 66.571)2 ) + (120 – 66.571) ) / 7 = 1584.816 Standard deviation = √(1584.816) = 39.810 2. i) A∪B = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} (ii) A∩B = ∅ (iii) A∩C…show more content…
i) [pic] (ii) P(L) = P(A and L) + P(B and L) + P(C and L) = 0.5*0.05 + 0.3*0.10 + 0.2*0.15 = 0.085 (iii) P(A|L) = P(A and L)/P(L) = 0.025/0.085 = 0.294 P(B|L) = P(B and L)/P(L) =

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