The bromine is acting first like an electrophile, and then after bromine has broken the π bond, a carbocation has formed, and a bromide ion has been created, the bromide ion then acts as the nucleophile and forms a bond with the carbocation. This experiment uses bromination, the specific name of halogenation with bromine. In order to for bromination to occur bromine must first be generated. This is done in situ through the oxidation of glacid acetic acid and puridinum bromide perbromide. Once generation is accomplished the available bromine can be brominated.
The synthesis of NaCl further identified the ionic compound by reacting sodium hydroxide and hydrochloric acid and obtaining solid sodium chloride. The synthesized compound formed was used to perform another flame test and the chloride anion test, which further solidified the identification of NaCl as the ionic compound. Introduction The purpose of the experiment was to identify unknown ionic compound
Radical Chlorination of 1-Chlorobutane. The radical chlorination of 1-chlorobutane was carried out using sulfuryl chloride and azoisobutyronitrile (AIBN). From the reaction there were for possible products which are as follows 1,1-dichlorobutane, 1,2- dichlorobutane, 1,3-dichlorobutane, and 1,4-dichlorobutane. The structures produced from the reaction are as follows; Attached to the four carbons in 1-chlorobutane are hydrogens that can react readily with chlorine, because of its electron withdrawing character. Chemical environment surrounding the carbons are different and therefore affecting the character of the hydrogens attached.
Computer Additivity of Heats of Reaction: Hess’s Law 18 (1) Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. (2) Solid sodium hydroxide reacts with aqueous hydrochloric acid to form water and an aqueous solution of sodium chloride. NaOH(s) + H+(aq) ) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ∆H2 = ? OBJECTIVES • • • • In this experiment, you will Combine equations for two reactions to obtain the equation for a third reaction. Use a calorimeter to measure the temperature change in each of three reactions.
However, the desired product is (-)-Isopinocampheol, in which the -OH group need to attach to the less substituted carbon instead. In order to form (-)-Isopinocampheol, we need to do hydroboration-oxidation reaction, in which (+)-α-Pinene will react with borane-tetrahydrofuran complex as hydroborating reagent to form an intermediate that have -OH group in anti-Markovnikov position. First of all, the carbon-carbon double bond in (+)-α-PInene will connect with H-BH group. Based on anti-Markovnikov rule, the H ion which has partial positive charge will connect to the most substituted carbon while -B which has partial negative charge will connect to the less substituted carbon. Since (+)-α-Pinene's double bond is trisubstituted and sterically hindered, only two compounds will reaction with borane to form dialkylborane as intermediate.
If the reaction is first order, its graphical representation is seen as ln[A] (natural log of concentration) vs. time, and the slope of its like is also the negative rate constant. Finally, for a second order reaction the graph is shown as 1/[A] (inverse of concentration) vs. time, and the slope of its given line is the positive rate constant. By understanding the rate law and finding the value of the correct rate constant with respect to the order of the reaction, one can determine the half-life of the crystal violet. This is because the crystal violet undergoes a decay reaction with the sodium hydroxide. According to Beer's Law, the absorbance of crystal violet is proportional to its concentration.
We added anhydrous Sodium Sulfate as a drying agent. To complete, we distilled the cyclohexene and collected the product. Knowing this data, we determined the yield % which is 58.5%. This experiment features the dehydration of cyclohexanol and produce cyclohexene. The acid catalyzed dehydration of cyclohexanol with distillative removal of the resulting cyclohexene from the reaction mixture
Write a hypothesis on what you think will happen when mixed. 3. Combine the substances; record observations. Hydrochloric Acid and Magnesium 1. Add hydrochloric acid to a test tube.
h) A way to make hard water softer is to put an sodium nitrate and create a precipitate to mellow out the reaction. Another way of making it softer is by removing the calcium ions one way of doing that is by boiling the solution to take out some of the ions. Conclusion: Overall, we determined that sodium carbonate, Na2CO3, is the anion that can be used to precipitate the most metal cations. Also, we learned that the anion sodium chloride, NaCl, could be used to remove silver ions from solutions. The stuff that I found interesting was that how many colours you can get when you mix the cations and anions
Ashley Peccatiello Experiment 7 – Dehydration of 2-Methylclyclohexanol, Tests for Unsaturation, and Gas Chromatography Date Performed: October 25, 2012 Date Written: October 29, 2012 Purpose: To dehydrate 2-methylclyclohexanol to obtain two isomers. To separate the products by simple distillation. To analyze the sample by introducing the technique of gas chromatography and unsaturation tests. Reaction: Figure 1. Overall reaction of the acid-catalyzed dehydration of 2-methylcyclohexanol Figure 2.