K12_1821161 $500 Answer from 3 Jan 9, 2014 1:03:23 PM Page 34. Blackboard Collaborate ?? K12_1821161 $100 Question from 4 Jan 9, 2014 1:03:23 PM Page 35. Blackboard Collaborate ?? K12_1821161 $100 Answer from 4 Jan 9, 2014 1:03:23 PM Page 36.
1,054,848 c. 1,405,888 d. 1,045,828 5. Evaluate: 12xy, when x = 8 and y = 11. a. 31 b. 228 c. 1056 d. 188 6. Write
264,000 / 25,000 hrs = $10.56 2650 hrs x 10.56 = $27,984 (d) Sum-of-the-years’-digits. n(n+1) = 10(11) = 55 10/55 x 264,000 x 1/3 = $16,000 9/55 x 264,000 x 2/3 = $28,800 Total = $44,800 (e) Double-declining-balance. 279,000 x 20% x 1/3 = $18,600 [279,000-(279,000x20%)] x 20% x 2/3 = $29,760 Total = $48,360 E11-9 (Composite Depreciation) Presented below is information related to Morrow Manufacturing Corporation. Machine | Cost | Estimated Salvage Value | Estimated Life (in years) | A | $40,500 | $5,500 | 10 | B | 33,600 | 4,800 | 9 | C | 36,000 | 3,600 | 8 | D | 19,000 | 1,500 | 7 | E | 23,500 | 2,500 | 6 | Instructions (a) Compute the rate of depreciation per year to be applied to the machines under the composite method. A: 40,500/10=4050 B: 33,600/9=3733 C: 36,000/8=4500 D: 19,000/7=2714 E: 23,500/6=3916 Total Straight-line depreciation = $18,913 Total Cost = $152,600 Depreciation Rate = 18,913/152,600 = 12.4% (b) Prepare the adjusting entry necessary at the end of the year to record depreciation for the year.
[ (Mark, A. et al, 1987) ] [ 3 ]. [ (Jones, S. & Shelley, R., 2009) ] [ 4 ]. [ (Sunset Scavenger Company v. Commissioner 84, 1936) ] [ 5 ]. [ (Section 501, 2010) ] [ 6 ]. [ (IRC Section 4958, 2010) ] [ 7 ].
5, 6) Lima Parts, Inc., shows the following overhead information for the current period: Actual overhead incurred $ 29,400 2/3 of which is variable Budgeted fixed overhead $ 8,640 per hour Standard variable overhead rate per direct labor-hour $ 9.00 Standard hours allowed for actual production 2,350 hours Actual labor-hours used 2,200 hours ________________________________________ Required: What are the variable overhead price and efficiency variances and fixed overhead price variance? (Input all amounts as positive values. Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect (i.e., zero variance). Omit the "$" sign in your response.) Amounts Variable overhead: Price variance $ (0%) (0%) Efficiency variance $ (0%) (0%) Fixed overhead: Price variance $ (0%) (0%) ________________________________________ P16-45 Overhead Variances (L.O.
| Week 7 Case Study Fujiyama Electronics, Inc. | | | Observations | | Sample | | 1 | 2 | 3 | 4 | | | | | | | 1 | | 4.92 | 4.26 | 4.94 | 4.29 | 2 | | 4.65 | 5.54 | 5 | 5.42 | 3 | | 5.77 | 5.26 | 4.76 | 4.79 | 4 | | 6.25 | 4.88 | 5.66 | 4.44 | 5 | | 5.27 | 5.41 | 6.02 | 4.91 | 6 | | 5.22 | 5.38 | 5.08 | 4.65 | 7 | | 5.47 | 4.68 | 4.56 | 4.7 | 8 | | 5.71 | 4.54 | 4.17 | 4.87 | 9 | | 5.24 | 5.58 | 4.72 | 5.41 | 10 | | 4.42 | 5.18 | 4.79 | 4.73 | 11 | | 5.14 | 4.26 | 4.71 | 5.48 | 12 | | 4.92 | 5.78 | 5.5 | 5.05 | 13 | | 5.79 | 3.83 | 4.3 | 4.78 | 14 | | 4.92 | 4.8 | 4.75 | 5.59 | 15 | | 5.68 | 5.74 | 4.65 | 5.2 | 16 | | 5.43 | 4.81 | 5.27 | 4.96 | 17 | | 4.79 | 6.04 | 4.47 | 5.18 | 18 | | 4.43 | 5.08 | 3.69 | 6.43 | 19 | | 6.35 | 5.95 | 6.29 | 5.89 | 20 | | 5.03 | 4.66 | 5.25 | 4.46 | 21 | | 6.32 | 6.09 | 5.57 | 5.91 | 22 | | 4.3 | 5.47 | 4.27 | 4.34 | 23 | | 6.07 | 4.97 | 5.51 | 5.02 | 24 | | 5.11 | 4.9 | 5.91 | 4.66 | 25 | | 4.5 | 5.24 | 4.86 | 4.35 | 26 | | 4.91 | 4.79 | 5.74 | 5.03 | 27 | | 4.65 | 4.71 | 4.81 | 5.32 | 28 | | 4.7 | 5.5 | 6.04 | 4.3 | 29 | | 5.87 | 5.3 | 5.78 | 5.07 | 30 | | 4.41 | 4.75 | 4.95 | 5.11 | 1. Calculate X-Bar-Bar, R-Bar, and associated control limits using the data in the table above. 2. Create X-Bar•R (Average & Range) Control Charts from the data in the table above. 3.
72 PSATP = P part(O2) + P part(CO2) + P part(N2) P part(N2) = PSATP - P part(O2) - P part(CO2) P part(N2) = 101.3 kPa – 79 kPa – 0.75 kPa = 21.55 kPa Answer: P part(N2) = 21.55 kPa 73 PV=nRT n = PV/RT P = 2500 kPa V = 12 L R = 8.314 J/mol*K T = 22 + 273.15 = 295.15 K n = (2500000*12*10-3m3)/ (8.314 J/mol*K*295.15 K) = 12.22 mol. Answer: n = 12.22 mol. 74 C3H8 + 4O2 => 3CO2 + 2H2O n (O2) = 3.5 mol * 4 = 14 mol PV = nRT V(O2) = nRT/P V(O2) = (14 mol * 8.314 J/mol*K *(28 + 273.15) K) / 1.013 * 105 Pa V(O2) = 0.3311 m3 = 331.1 L Answer: V(O2) = 331.1 L 75 PV=nRT n = PV/RT n = (1.013*105 Pa * 65 * 10-3 m3) / (8.314 J/mol*K * 298 K) = 2.65 mol Answer: n = 2.65 mol 76 PV=nRT n = PV/RT n = (1.013*105 Pa * 7.5 * 10-3 m3) / (8.314 J/mol*K * 298 K)
1) 46/313 Harris st. 1/1/1 $390 1300 553 814 (LJ) Insp : 21 sat 10:00 2) 19/333 Bulwara rd 2/1/1 $475 1300 553 893 Insp : 21 sat 10:30~10:45 3) 14/313 Harris st. 1/1 1300 553 893/0403 185 117 (Ray white) Insp : 21 sat 11:~11:15 3) 70/732 Harris st. 3+1/2/2 $1000 02)9804 8288/ 02) 9804 6522 Insp : 21 sat / 11:15 4) 5/104 Clarence st. 1/1(1study) 1300 663 894 Insp : 21 sat 11:30~12:00 5) **409/243 Pyrmont st 1/1 $430 0411 804 925 Insp : 21 sat 12:30~12:50 10/558 Jones St 1/1 $400 1300 727 581 Insp : 21 sat 12:45~13:05 6) 908/743-755 George st. 3(study)/2/1 $790 0416 282 952 Insp : 21 sat 1:30~2:00 21 cadiga Ave 3/2/2+1 $950 0432 716 000/ 02)8586 7800 Insp : 25 wed / 4:30~5:00
Credit Balance($) 0.01193 0.00129 9.25447 0.000 Summary of Model S = 8.40667 R-Sq = 64.08% R-Sq(adj) = 63.34% PRESS = 3613.50 R-Sq(pred) = 61.74% Analysis of Variance Source DF Seq SS Adj SS Adj MS F P Regression 1 6052.72 6052.72 6052.72 85.6452 0.000000 Credit Balance($) 1 6052.72 6052.72 6052.72 85.6452 0.000000 Error 48 3392.26 3392.26 70.67 Lack-of-Fit 47 3390.26 3390.26 72.13 36.0666 0.131532 Pure Error 1 2.00 2.00 2.00 Total 49 9444.98 Correlations: Income ($1000), Credit Balance($) Pearson correlation of Income ($1000) and Credit Balance($) = 0.801 P-Value = 0.000 To calculate the for the confidence levels at α=0.05 General Regression Analysis: Income ($1000) versus Credit Balance($) Regression Equation Income ($1000) = -3.51589 + 0.0119264 Credit Balance($) Coefficients Term Coef SE Coef T P Constant -3.51589 5.48309 -0.64123 0.524 Credit Balance($) 0.01193 0.00129 9.25447 0.000 Summary of Model S = 8.40667 R-Sq = 64.08% R-Sq(adj) =
Combined Account Statement Statement Period:from Nov 7, 2013 5:00:00 PM through Nov 8, 2013 11:06:18 AM User Name:sajida habib FXCMUK sajida habib house Trade account#:02184120 CLOSED TRADE LIST Ticket # Symbol Volume 3,000 3,000 4 4 4 Date 11/8/13 1:35 AM 11/8/13 2:19 AM 11/8/13 1:40 AM 11/8/13 6:05 AM 11/8/13 2:05 AM 11/8/13 8:15 AM 11/8/13 2:34 AM 11/8/13 5:49 AM 11/8/13 5:51 AM 11/8/13 8:15 AM Sold 1.69969 1.34204 1,311.18 1,309.08 1,311.62 Bought 1.69968 1.33996 1,310.10 1,309.99 1,309.58 Gross P/L 0.03 6.24 4.32 -3.64 8.16 15.11 15.11 Comm 0.00 0.00 0.00 0.00 0.00 0.00 0.00 Rollover 0.00 0.00 0.00 0.00 0.00 0.00 0.00 Adj 0.00 0.00 0.00 0.00 0.00 0.00 0.00 Net P/L Condition Created By d172180780001 d172180780001 d172180780001 d172180780001