To perform this experiment, we will utilize emission spectra, titrations, and thermal gravimetric analysis, using knowledge from Experiments 10, 4, Titrations of Na2CO3 and NAHCO3 by HCl (hydrochloric acid) will be performed to determine the concentration of HCl, as well as the number of moles of HCl present within the sample of baking soda. As a result, we will be able to determine the molar concentration of HCl by determining its equivalence point (the point on the graph where the exact amount of rectant needed to perform a reaction has been added) from graphical analysis. Na2CO3(aq.) + HCl(aq.) ==> NaHCO3(aq.)
We added anhydrous Sodium Sulfate as a drying agent. To complete, we distilled the cyclohexene and collected the product. Knowing this data, we determined the yield % which is 58.5%. This experiment features the dehydration of cyclohexanol and produce cyclohexene. The acid catalyzed dehydration of cyclohexanol with distillative removal of the resulting cyclohexene from the reaction mixture
Computer Additivity of Heats of Reaction: Hess’s Law 18 (1) Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. (2) Solid sodium hydroxide reacts with aqueous hydrochloric acid to form water and an aqueous solution of sodium chloride. NaOH(s) + H+(aq) ) + Cl–(aq) → H2O(l) + Na+(aq) + Cl–(aq) ∆H2 = ? OBJECTIVES • • • • In this experiment, you will Combine equations for two reactions to obtain the equation for a third reaction. Use a calorimeter to measure the temperature change in each of three reactions.
Write a hypothesis on what you think will happen when water is added. 3. Fill the test tube with two thirds of water and record the results. Copper (II) Sulphate Solution and Iron Nail 1. Record physical properties of the copper (II) sulphate
________________________________________ Chart 1.2: the difference between the readings in each of the trails. Chart 1.3: the difference between the sum and the average. CONCLUSION AND EVALUATION CONCLUSION: Equivalence point is the point at which the moles of H+ is equal to the moles of OH+,an indicator is used to show the equivalence point during a titration. in a titration the method is about totaling one reactant from the burette (regularly the acid),to a known volume of the other reactant in a conical flask(regularly the base) . In order to find the concentration of NaOH we need to tag along the following steps: a- note down the balanced chemical equation for the reaction C8H5O5K+NaOH→C8H4O4KNa+H2O b- pull out applicable information from the experiment: C8H5O5K V=0.025 dm3 C=0.2M NaOH V=0.021 dm3 C= ??
Objectives: The purpose of this lab is to observe the reaction of crystal violet and sodium hydroxide by looking at the relationship between concentration and time elapsed of the crystal violet. CV+ + OH- CVOH To quantitatively observe this reaction of crystal violet, the rate law is used. The rate law tells us that the rate is equal to a rate constant (k) multiplied by the concentration of crystal violet to the power of its reaction order ([CV+]p) and the concentration of hydroxide to the power of its reaction order ([OH-]q). Rate = k[CV+]p[OH-]q To fully understand the rate law, concentrations of the substances must be looked at first. The concentration is measured in molarity.
2) Predict which of the following in each set of compounds will have the highest water solubility. Which will have the lowest? Explain your answers. 3) Show how you could separate the components of the following mixtures. a) + O OH 1) dissolve in organic solvent like Et2O or CH2Cl2 2) add water solution of NaOH + O H2O layer O Et2O layer O O 1) add Et2O 2) add HCl OH O H2O layer Et2O layer 1) dry over MgSO4 2) remove Et2O NaCl O OH 1) dry over MgSO4 2) remove Et2O OH O b) O O + N 1) dissolve in organic solvent like Et2O or CH2Cl2 2) add water solution of HCl O O H2O layer + N H Et2O layer O N H O 1) dry over MgSO4 2) remove Et2O O O H2O layer Et2O layer 1) add Et2O 2) add NaOH N NaCl N 1) dry over MgSO4 2) remove Et2O N c) O O + N 1) dissolve in organic solvent like Et2O or CH2Cl2 2) add water solution of HCl O O H2O layer + N H Et2O layer O N H O 1) dry over MgSO4 2) remove Et2O O O H2O layer Et2O layer 1) add Et2O 2) add NaOH N NaCl N 1) dry over MgSO4 2) remove Et2O N d)
This reaction can be summed up using the following formula: 5Fe2++8H++MnO4- →5Fe3++Mn2++4H2O After standardization, the potassium permanganate solution is then titrated with 3 different magnesium oxalate solutions. To find the concentration of the C2O42- the balanced net ionic redox reaction formula is used: 5C2O42-+16H++2MnO4- →10CO2+2Mn2++8H2O It is important to note the addition of sulfuric acid (9M H2SO4) in performing this experiment because of the following reasons: 1) Sulfuric acid keeps the iron (II) from air oxidizing into iron (III) 2) Sulfuric acid keeps the iron (II) from hydrolyzing into Fe(OH)2 3) Sulfuric
These can be removed by adding a solution of potassium iodide, KI. In this investigation, you will combine different pairs of solutions to discover which cation/anion combinations result in the formation of a precipitate. Purpose: To identify which anion could be used to precipitate
Separation of the components of Extra-Strength Excedrin I: Acid-Base extraction Introduction The purpose of this experiment is to analyze the purity of Extra-Strength Excedrin® by utilizing thin-layer chromatography and determine the percent recoveries of its components. Three active ingredients will be extracted and collected from two tablets of Extra-Strength Excedrin® by utilizing acid-base extraction method. Three active ingredients of Extra-Strength Excedrin® are acetylsalicylic acid(aspirin), acetaminophen and caffeine, and their structures are: In addition, there is a binding material, which binds other three components together. These compounds can be separated by acid-base extraction because of their different acidities. A binding material can be separated by dissolving the tablet in ether since three active ingredients are soluble.