AP Physics C Lab Report i. Purpose: To use derivatives to investigate the various characteristics of cardboard ii. Materials: Compass, Cardboard, mass balance, ruler, meter stick iii. Procedure: 1. Measure and record the diameter of each of the disks in meters.
due = downpayment – total 10. Write a pseudocode statement that multiplies the variable subtotal by 0.15 and assigns the result to the variable totalfee. First you must make the variables real numbers. example.Dim subtotal As Double = 0 The statement asked for in the question will appear as totalfee = subtotal *
Therefore, we had 36 data points for micrometer calibration. The caliper was calibrated in very similar way as micrometer. The six gage blocks caliper used were 0.105, 0.11, 0.16, 0.3, 0.5, 2 inch. Record all data in lab notebook. After the calibration, select one of unknown blocks in the shelf.
Juliana Park Mayumi Tamada CHEM 111B LAB/ M-F 1-4PM 15 August 2012 Spectroscopy Lab Introduction In this lab, the molar absorptivity of the complex FeLn2+ will be determined by using the absorbance of the complex and its concentration. The absorbance will be found by using a spectrophotometer. For the next part of the lab, the formula of the complex will be determined by also using the volume of ligand and the absorbance again. Experimental There are two different parts to the experiement. In the first part, five 100 mL flasks of 5 mL ligand solution, 5 mL 2 M sodium acetate, 4 mL 3 M NH2OH, and 1-5 mL Fe2+ solution are diluted with water.
120 MB x 1024 = 122,880 KB x 1024 = 125,829,120 bytes Exercise 1.3.4 Given a computer with a disk capacity of 16 GB and a word size of 32 bits, how many words can be stored on the disk? Show your calculations. First we must calculate how many bits are in 16GB: 16 GB x 1024 = 16,384 MB x 1024 = 16,777,216 KB x 1024 = 17,179,869,184 bytes x 2 = 34,359,738,368 We multiples the byte by two because one byte is 2 bits, now we divide the bits by 32: 34,359,738,368 ÷ 32 = 1,073,741,824 So we could fit 1,073,741,824 words (32 bit size) in 16 GB of space. Exercise 1.3.5 Represent the binary value 1101102 in hexadecimal. Show the steps of conversion that you used.
What is the mass of object 1? __________19.5g_____________________ An object’s volume is the amount of space it takes up. The volume of an irregular object can be measured by how much water it displaces in a graduated cylinder. Place object 1 into the Graduated Cylinder. What is the volume of object 1?
Record the readings of the three instruments at eight different speed settings of the tunnel: 15, 20, 25, 30, 35, 40, 45, & 50. 4. Plot two calibration curves with pressure transducer reading as the abscissa and micromanometer reading as the ordinate for the first, and micromanometer versus scannivalve as the second. Convert micromanometer data to read as total pressure in SI units [Pa]. 5.
K12_1821161 $500 Answer from 3 Jan 9, 2014 1:03:23 PM Page 34. Blackboard Collaborate ?? K12_1821161 $100 Question from 4 Jan 9, 2014 1:03:23 PM Page 35. Blackboard Collaborate ?? K12_1821161 $100 Answer from 4 Jan 9, 2014 1:03:23 PM Page 36.
Jose Flores 6th period 1-27-14 LAB REPORT Introduction: A substance can conduct an electrical current if it is made of positively charged and negatively charged particles that are free to move about and is called a conductor. The purpose is to figure out conductivity of substances and to check which one conducts electricity. The hypothesis is that sucrose would be the only one that could not conduct out of the other six solutions. Materials: The materials used in this lab where six solutions , napkins, 2 pairs of gloves, 2 cups (1 cup with distilled water and 1 cup with solid NaCI) and a conductivity meter. The six solutions are sodium chloride, hydrochloric acid, sodium hydroxide, acetic acid, ammonia and sucrose.
What pieces of laboratory equipment would you use to measure the properties needed to determine the density of a substance? The piece of laboratory equipment needed to find mass is a balance and for volume a graduated cylinder. 3. Using the properties stated in question 1, write the formula for density. D=m/v 4.