Both of these formulas were found on page 225 in Mathematics in Our World (Bluman, 2005). Problem #37 • This sequence is geometric • Ending balance is $814.45 STEPS/CALCULTATIONS YOU PERFORMED TO REACH THE ANSWER: To find the ending balance, the formula of An = a1(rn-1) will be used. The initial balance is $500, the interest is 5%, and the time span is 10 years. 5% will be listed as 1.05 as the initial balance is 100% plus 5% interest, so 105% is written 1.05. The number of terms is n=10, the first term is a1=525, the common ratio is r = 1.05.
2.12 b. 1.734 c. -1.740 d. 1.740 ANSWER: d -same process but now go to one tailed α=0.05 and dof = 17 4. Read the t statistic from the table of t distributions and circle the correct answer. A one-tailed test (lower tail), a sample size of 10 at a .10 level of significance; t = a. 1.383 b.
Revision Year 12 Maths B, Term 4 1. The function, y=3cosx+5 has an amplitude of 3 and a mean value of 5. Using these values, the range can be found to be 2≤y≤8 . Find the range of the function y=4cosx+7 2. Find the exact value of tan600 (Hint, draw a standard triangle to help) 3.
Degree Specific Requirements (40 Hours) | 3 | MTH 284 (MATH 2384) | | | 3 | EED 374 (CIEE 3374) ¥ Apply online for Ed Prep admission in this class, if not before- $100.00 | Prerequisite for Literacy Methods | 3 | MTH 285 (MATH 2385) | | | 3 | EED 385 (CIEE 3385) ¥ | | 3 | MTH 383 (MATH 3383) | | | 3 | BSL 333 (BESL 3301) | | 3 | MTH 384 (MATH 3384) | | | 3 | SPD 390 (SPED 3301) | Fall & Spring Only | 3 | MTH 386 (MATH 3386) | | | 4 | BIO 245 (BIOL 2401) | | 3 | MTH 387 (MATH 3387) |
From the CIA data set, we computed a 95% and 99% confidence interval factoring in the mean, standard deviation and the population sizes. For a 95% confidence interval, the true range of the data ranges from 89.61 to 95.13 (this represents a plus/minus range of 2.76). For
b. One inch on this map equals exactly __24,000___ inches in real life. c. One inch on this map equals exactly _0.3__ mile(s) in real life, so we can say that 1 inch on the map equals approximately 1/3 mi on the ground. (Lab Man) 3 6. Review how the location of point x in Fig.9.5 in 9th ed’n was determined using PLS shorthand (see caption for Figure 9.5). Then, determine the location of point V in the Figure below using PLS shorthand.
| | Instructor Explanation: | Chapter 38. | | | | Points Received: | 1 of 1 | | Comments: | | | | 6. | Question : | (TCO 9) Answer the next question(s) on the basis of the following table which indicates the dollar price of libras, the currency used in the hypothetical nation of Libra. Assume that a system of freely floating exchange rates is in place. (1)Quantity of Libras Demanded (billions) | (2)Dollar Price of Libras | (3)Quantity of Libras Supplied (billions) | 100200300400 | $5432 | 32520010075 | The equilibrium dollar price of libras is | | | Student Answer: | | $5.
AP Statistics Name _______________ 3/24/09 Wood/Myers Period _____ Test #12 (Chapter 13) Honor Pledge __________ Part I - Multiple Choice (Questions 1-10) – Circle the letter of the answer of your choice. 1. An SRS of size 100 is taken from a population having proportion 0.8 successes. An independent SRS of size 400 is taken from a population having proportion 0.5 successes. The sampling distribution for the difference in sample proportions has what standard deviation?
Comm 314, Midterm Exam Fal1 2010 Name --------------~=------------(Exam = 100/400 pts) I..., fj1 W Ir; .. "-I ! ,1/' (V\ Part A: Please circle the letter corresponding to the correct answer. Do a1l3! ; I'll count 29-(1 point each; 29 points for the section). 1.
2. Verify the equation of the pendulum T = 2 q L g by means of the graph of T2 vs L and determine the value of g from the graph. 1 3 Data Collection Length (m) Period (s) 1.954 1.00 1.959 1.955 1.879 0.91 1.888 1.880 1.747 0.80 1.754 1.765 1.759 0.82 1.757 1.761 1.653 0.72 1.645 1.641 1.501 0.60 1.506 1.504 Table 1: Data Collection 4 Data Analysis See Table 2 and attached graph. Slope = 3.826 1 = 3.826 m/s2 g = (2)2 3.826 = 10.3 m/s2 2 Length L(m) Period T(s) Average T T2 1.954 1.00 1.959 1.956 3.826 1.955 1.879 0.91 1.888 1.882 3.543 1.880 1.747 0.80 1.754 1.755 3.081 1.765 1.759 0.82 1.757 1.759 3.094 1.761 1.653 0.72 1.645 1.646 2.710 1.641 1.501 0.60 1.506 1.504 2.261 1.504 Table 2: Data Analysis 5 Evaluation In this lab, we were able to estimate the value of the acceleration due to gravity g on Earth by means of a simple pendulum. Because the length of a pendulum L, and the square of the period of the pendulum T2 are directly proportional, we were able to determine g by calculating the slope of the T2 vs L graph.