Therefore, it is general practice to conduct various trials and statistical analysis is also carried out on benchmark functions as shown in Table 5.5. Also it is illustrated using Fig. 5.5 with different population on 20-D. It is observed that population size of 100 shows good consistencies compared to other population for f6 – f9, whereas f10 and f11 has better consistency with population size of 150 and 200. 5.2.2.4 Comparison of consistency characteristics Table 5.6 shows the consistency analysis of all the nine multimodal benchmark functions on 30 dimensions.
(a) Find a 99% confidence interval for the true mean heart rate of all people with this untreated condition. Show your calculations. (b) Interpret this confidence interval and write a sentence that explains it. 23. Determine the minimum required sample size if you want to be 80% confident that the sample mean is within 2 units of the population mean given sigma = 9.4.
To find the mean of the sample data set the formula must be used: Sample mean x̄ = (∑x)/N = 446.1/30= 14.87 According to Larson and Farber, 2009, the median of a data set is the value that lie in the middle of the data when the data set is ordered. The given numbers in the table are in order, there are thirty entries (an even number). The median is the mean of the two middle entries. Median = (14.8+14.8)/2 = 14.8 According to Larson and Farber, 2009, the standard deviation is the difference between the entry data and the entry mean. Sample standard deviation x=√(∑(x-µ)^2 )/(N-1) = √8.783/(30-1) = √0.302862 = 0.5503 Construct a 95% Confidence Interval for the ounces in the bottles.
What is correct here? 26 Which of the following is never negative? 27 If the marginal product of labor is 100 and the price of labor is 10, while the marginal product of capital is 200 and the price of capital is $30, then what should the firm? 28 In a production process, an excessive amount of the variable input relative to the fixed input is being used to produce the desired output. This statement is true for: 29 What method of inventory valuation should be used for economic decision-making problems?
How would you demonstrate the central limit theorem to your classmates? * When the sample size is larger the smaller the standard deviation or error, then you will have a more dependable estimate. Also remember to analyze the mean with bigger samples. Based on the normality, the central limit theorem is relied on all statistics and tests. It is possible to normalize the data when the population shape has a known skew.
Our mean is $46,020 and our standard deviation is 13.88, and our sample size is 50. To test this hypothesis, we will use a 5% rejection region and 95% confidence interval. Per the rules of hypothesis testing, we must not reject the null hypothesis if the p-value is greater than sigma (rejection region), and reject it if the p-value is less than sigma. Since our p-value for this test is 0.302 is less than sigma (1.645), we must reject the null hypothesis. There is sufficient evidence to indicate the true mean is greater than $45,000.
Abbott Laboratories Problem February 3, 2014 Abbott Laboratories After reading the Value Lines figures and information on Abbott Laboratories in the Questions and Problems section of Chapter 6 (just before Problem 27), complete the following Problems: Problem 27: What is the sustainable growth rate and required return for Abbott Laboratories? Using these values, calculate the 2010 share price of Abbott laboratories Industries stock according to the constant dividend growth model. The dividend = 1.60 for 2009. The growth rate is calculated as follows: 1-(1.6/3.65) = .5616 g=28%*.5616 = 15.72% Discount rate: k=3.13%+-.60(7%) = 7.33% 2010 share price: Po = 1.6(1.15)/.07-.15 = $26.14 share price Problem 28: Using the P/E, P/CF, and P/S ratios, estimate the 2010 share price for Abbott Laboratories. Use the average stock price each year to calculate the price ratios.
Based on your findings in 1–5, what is your opinion about using creditbalance to predict income? Explain. 7. Compute the 95% confidence interval for beta-1 (the population slope). Interpret this interval.
Reflection questions about the Drake equation: Equation | Minimum values | Maximum values | R= | 1 | 7 | Fp= | 0.4 | 0.6 | Ne= | 2 | 2.5 | F1= | 0.5 | 1 | Fi= | 0.001 | 1 | Fc= | 0.5 | 0.8 | L= | 10,000 | 200,000 | N= | 2 | 1,680,000 | What value did you get for the number of civilizations? After calculating the maximum and minimum values of the equation through researching them individually, the minimum value of the Drake equation, N = R x fp x ne x f1 x fi x fc x L, was N = 2. The values were as such: * R = 1 * fp = 40 % (0.4) * ne = 2 * f1 = 50% (0.5) * fi = 0.001 * fc = 50% (0.5) * L = 10,000 (1 x 0.4 x 2 x 0.5 x 0.001 x 0.5 x 10000). These figures lead the end of the equation at the number of communicative civilizations at N = 2; meaning there is a minimum of 2 expected communicative civilizations in the galaxy. The maximum value that was proposed for the Drake equation, N = R x fp x ne x f1 x fi x fc x L, was N = 1,680,000.
Conversely, if the test statistic does not fall in the rejection region, then we cannot reject the null hypothesis (H0) stating that there is insufficient evidence (McClave, p. 325). The Average (mean) annual income was less than $50,000 Summary The null and alternative hypotheses from Appendix A are H0: µ =50 and Ha: µ <50. The Minitab results from Appendix B bii, shows a z test statistic of -3.02, and a p value of 0.001. The p value actually represents the “probability that our test statistic will be as extreme, or more extreme, than one observed by chance alone, if the null hypothesis H0, is true; or the probability of wrongly rejecting the null hypothesis if it is in fact true” (Easton & McColl). In hypothesis testing, the smaller the p value the more important it is.