We added anhydrous Sodium Sulfate as a drying agent. To complete, we distilled the cyclohexene and collected the product. Knowing this data, we determined the yield % which is 58.5%. This experiment features the dehydration of cyclohexanol and produce cyclohexene. The acid catalyzed dehydration of cyclohexanol with distillative removal of the resulting cyclohexene from the reaction mixture
Which substance, water or the buffer does a better job of maintaining pH when small amounts of strong acid are added? The buffer does a much better job at maintaining pH. 3. Compare what happen to the pH of flask 2 to what happened to the pH of flask 4 when NaOH was added. Both flask’s pH went up 4.
The concentration of a solution is the amount of solute that is dissolved into each unit of solvent. In this lab, water (H2O) will be the solvent and sugar/sucrose (C12H22O11). When the density of the solute is greater than the density of the solvent, the density is directly proportional to the concentration of the solute. The relative density of the solute to the solvent can be observed by placing some solute into the solvent without mixing. If the solute floats, then the density of the solvent is greater than the density of the solute.
[1 pt] Ionic compounds dissociate when it dissolve in water. The ionic compound breaks up to ions. 2. Using Table F, classify each salt as soluble or insoluble: [1 pt each = 4 pts] a)AgNO3 __Soluble____ b)AgCl Insoluble c)CaCO3 _Insoluble_ d)(NH4)2CO3 Soluble 3. When 1 mole of CaCl2 is dissolved in water, it produces 1 mole of Ca+ ions and 2 moles of Cl- ions as illustrated by the equation: CaCl ( Ca+ + 2Cl- Complete the following equations (both are soluble) [2 pts each = 4 pts] a) CuSO4( Cu + SO4 b) Na3PO4( 3Na + PO4 Procedure: 4.
With the use of this technique we placed chlorine, bromine, and iodine into solutions containing chloride, bromide, and iodide. In the reaction the free halogen (X2) oxidizes the other halide ion (Y-) and gets reduced by gaining electron(s). In table 3, chlorine was the strongest oxidizing agent and iodine was the weakest oxidizing agent. Since chlorine was the strongest oxidizing agent it will react more and the weak agent will react less. This explanation can be demonstrated in table 3 also because the results of the reactions demonstrates that chloride reacted more by the color of the product compared to the color of chloride in the mineral oil.
Explain your answer. Water itself is an example of a homogeneous mixture. It often contains dissolved minerals and gases, but these are dissolved throughout the water. Is isopropyl alcohol (rubbing alcohol) a heterogeneous or homogenous mixture? Explain your answer.
A solvent is the substance in which the solute is being dissolving. Water Water is chemically H2O. Water molecules are formed when two hydrogen molecules and one oxygen molecule combine. Water is a good solvent due to its polarity. When an ionic or polar compound enters water, it is surrounded by water molecules Salt or Sodium Chloride Salt is a mineral that is composed primarily of sodium chloride (NaCl), a chemical compound belonging to the larger class of ionic salts.
Even though the results under hexane and toluene are similar, the distances of original mixture, first and second fraction are different from hexane and toluene solvent because they have different polarity. As first fraction containing fluorene, which is much non-polar than fluoreone, fluorene in first fraction is much easier to carry by the moving non-polar solvent. Thurs, as the more non-polar the solvent is the longer distance that fluorene will move. Since hexane has larger non-polar carbon-hydrogen single bond groups than toluene, it is much non-polar than toluene. As the result of this, it can explain why the distance of fluorine in hexane is longer (1.3 cm) than the one in toluene (0.5 cm) and due to less non polar toluene has.
Halides Lab: Background information: Halide ions are reactive and useful. Salts are positively charged ions (metals) combined with any negative ions (nonmetal), and when placed in a solution (water) it separates into the cations and anions that made it up. The Purpose of this lab is to find out how the Halides react with the indicators, and to determine the identity of the two unknown solutions (A and B). Color of solutions prior to experiment: NaF | NaCI | KBr | KI | Unknown A | Unknown B | clear | clear | clear | clear | clear | clear | Color of indicator prior to experiment: 5% Bleach (NaOCI) | 0.2 M Na2S2O3 | 0.1 M AgNO3 | 0.5 M Ca(NO3)2 | clear | clear | clear | clear | Halide solutions | NaF | NaCI | KBr | KI | unknown A | unknown B | Test 1: Ca(NO3)2 | Cloudy White (Nothing) | Clear | Nothing | light yellow (Nothing) | Nothing | Nothing | Test 2, Part A: AgNO3 | clear (Nothing) | Milky White | Gold (Cloudy yellow) | milky green (Cloudy yellow) | turned white, film developed on top layer | Milky | Test 2, Part B: add Na2S2O3 to test tube from part A | Dark Orange/brown | Clear | Dark Gold(precipitate yellow then clear) | milky green (no change) | white precipitation, settled on bottom | Milky | Test 3: NaOCI (Bleach) | Clear (Nothing) | Nothing | Nothing | Orange (Clear) | Nothing | Orange | Unknown A is identified as NaCI (Sodium Chloride), because in test#1 the solution turned a cloudy white color when Ca(NO3)2 (Calcium nitrate) was added. In the first part of test#2, when AgNO3 (Silver nitrate) is added, the solution turned white, with a thin layer of film developing on the surface.
For example, the reaction |BaCl2•2H2O ( BaCl2 + 2H2O |(2) | is reversible, and if water is added to the anhydrous salt BaCl2, formation of BaCl2•2H2O takes place: |BaCl2 + 2H2O ( BaCl2•2H2O |(3) | The reaction of dehydration of hydrated ferrous sulfate |FeSO4•7H2O ( FeSO4 + 7H2O |(4)