2NaCl + H2SO4 —> Na2SO4 + 2HCl 4. If 0.380 mole of barium nitrate is allowed to react with an excess of phosphoric acid, how many moles of barium phosphate could be formed? 3Ba(NO3)2 + 2H3PO4 —> Ba3(PO4)2 + 6HNO3 5. Calculate the number of grams of carbon dioxide produced from the burning of 1.65 moles of C3H8. C3H8 + 5O2 —> 3CO2 + 4H2O 6.
The crystalline size of the prepared nanoparticles where determine by scherrer’s equation and it was in the range of 28 nm. From the XRD, The diffraction peaks are at 2θ values of 32.00, 34.12, 36.46, 47.64, 56.8, 62.82, 66.76, 68.20, 69.50, 73.08, 77.48 and 82.28 were identified to originate from (100), (002), (101), (102), (110), (103), (200), (112), (201), (004), (202) and (104) planes. Based on the Scherrer equation the average crystallite size of the nanoparticles is observed as 28 nm. The main diffraction peak is observed at 2θ value of 32.00. This peak is identified to originate from (100) planes of the ZnO.
Initial Concentration Chemical Mass of Graduated Cylinder (g) Mass of Sugar (g) Molar Mass (g) Moles in Graduated Cylinder Total Volume (L) Molarity (mol/L) Sugar (C12H22O11) 16.6 10 342.29 .29 .1 .29 Data Table 9. Dilution Series Dilution Volume (mL) Mass (g) Density (g/mL) Initial Concentration (M) Volume Transferred (mL) Final Concentration (M) 0 25.0 mL 25 25 0 mL 0ml 1 25.0 mL 10 10 .29 2.5 mL 5.4M 2 25.0 mL 15 40 .435 4.5 mL 6.8M 3 25.0 mL 20 45 .58 3.0 mL 9.4M 4 25.0 mL 25 50 7.25 6.0 mL 11.2M Data Table 10. Molarity vs. Density Molarity vs. Density molarity is the concentration of a solution given in gram moles of solute per liter of solution. Density is the degree of compactness of a substance. Questions: How would you prepare 10 mL of a 0.25M HCl solution if 1M HCl was available?
What element in Period 5 of the periodic table is a member of Group 14? (1 point) Answer: The element that is in Period 5 as well as Group 14 is tin or Sn. 4. The word interpolate means to use a given line graph to find unknown points between the plotted points of the graph. Use your line graph from Part II to interpolate, or estimate, atomic radius of Tin (Sn).Â (1 point) Answer: By using the given line to interpolate the atomic radius of tin, it can be found that its radius is around 149pm.
Briefly, 25 µl of ethanolic extract of propolis was added to 1 ml of reagent solution (0.6 M sulfuric acid, 28 mM sodium phosphate, and 4 mM ammonium molybdate). The mixture was capped and incubated in a thermal block at 95°C for 1h. The absorbance of the reaction mixture was measured at 700 nm against a blank. Ascorbic acid was used as the standard calibration. The results were expressed as milligrams of ascorbic acid equivalent per gram of sample.
When you add the values 3, 5, 8, 12, and 20 and then divide by the number of values, the result is 9.6. Which term best describes this value: average, mean, median, mode, or standard deviation? Answer: ____The term that describes 9.6 would be the mean, it is the sum of all the values divided by the total number of values______ 4. What is the range of the values 2.0, 3.7, 4.9, 5.0, 5.7, 6.7, 8.5, and 9.0? Answer: __9.0 – 2.0 = 7___________ What is the median?
Assignment Chapter 7 Concept Explorations 7.23. Light, Energy, and the Hydrogen Atom a. Which has the greater wavelength, blue light or red light? Red light radiates close to 700nm, blue light closer to 450nm, so 700 is greater than blue 450. Red light b.