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AIEEE - 2002 Physics and Chemistry Solutions
2. 4. 5. 6.
λmax / 2 = 40 ⇒ λmax = 80
Large aperture increases the amount of light gathered by the telescope increasing the resolution.
KE =
1 1 2 mvesc = m( 2gR)2 = mgR 2 2
A voltmeter is a high resistance galvanometer and is connected in parallel to circuit and ammeter is a low resistance galvanometer so if we connect high resistance in series with ammeter its resistance will be much high.
7.
In coil A, B =
µ 0 2πI . 4π R
I B I R 2 ∴Bα ; Hence, 1 = 1 . 2 = = 1 R B2 R1 I2 2
8.
No. of images, n = (360 / θ) − 1. As θ = 600 so n = 5
9.
V2 V2 V2 + =4 = 4P1 P1 =V /R ; P2 = (R / 2) (R / 2) R
2
10.
En = −
13.6 13.6 ⇒ E2 = − 2 = 3.4eV 2 n 2 λA = 2L
11. 12.
n 2 λA 1 = ⇒ A = nB 1 λB 2
A=
B=
λB = 4L
The fact that placing wax decreases the frequency of the unknown fork and also the beat frequency states that the unknown fork is of higher frequency. n - 288 = 4 ⇒ n = 292 cps y1 + y2 = a sin(ωt − kx) − a sin(ωt + kx)
13.
= −2a cos ωt × sin kx ⇒ y1 + y 2 = 0 at x = 0
14. 15. 16. 17. W = qV ⇒ VA - VB = 2/20 = 0.1 V Here W is the work done in moving charge q from point A to B r = mv / Bq is same for both K.E. is maximum and P.E minimum at mean position Angular momentum = conserved
1 1 Mω1 MR2 ω1 = 2mR2 ω + MR2ω ⇒ ω = 2 2 M + 4m
18. 19. The condition to avoid skidding, v = µrg = 0.6 × 150 × 10 = 30 m / s v=
2gh = 2 × 10 × 20 = 20 m / s
19
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20. 21. 22. 24. 27. 28. 29. 32. 33.
K 800 x2 2 W = ∫ Fdx = ∫ Kxdx = K = [ x 2 − x 1 ] = [(0.15)2 − (0.05)2 ] = 8 J 2 2 x1 2 2 x1 x1 x2 x2
x2
Conserving Linear Momentum 2Mvc = 2Mv - Mv ⇒ vc = v/2 It will compress due to the force of attraction between two adjacent coils carrying current in the same direction Semiconductors are insulators at low temperature Neutrons can’t be

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