Ai9Eee Essay

5213 WordsSep 22, 201221 Pages
www.estudentzone.com www.estudentzone.com AIEEE - 2002 Physics and Chemistry Solutions 2. 4. 5. 6. λmax / 2 = 40 ⇒ λmax = 80 Large aperture increases the amount of light gathered by the telescope increasing the resolution. KE = 1 1 2 mvesc = m( 2gR)2 = mgR 2 2 A voltmeter is a high resistance galvanometer and is connected in parallel to circuit and ammeter is a low resistance galvanometer so if we connect high resistance in series with ammeter its resistance will be much high. 7. In coil A, B = µ 0 2πI . 4π R I B I R 2 ∴Bα ; Hence, 1 = 1 . 2 = = 1 R B2 R1 I2 2 8. No. of images, n = (360 / θ) − 1. As θ = 600 so n = 5 9. V2 V2 V2 + =4 = 4P1 P1 =V /R ; P2 = (R / 2) (R / 2) R 2 10. En = − 13.6 13.6 ⇒ E2 = − 2 = 3.4eV 2 n 2 λA = 2L 11. 12. n 2 λA 1 = ⇒ A = nB 1 λB 2 A= B= λB = 4L The fact that placing wax decreases the frequency of the unknown fork and also the beat frequency states that the unknown fork is of higher frequency. n - 288 = 4 ⇒ n = 292 cps y1 + y2 = a sin(ωt − kx) − a sin(ωt + kx) 13. = −2a cos ωt × sin kx ⇒ y1 + y 2 = 0 at x = 0 14. 15. 16. 17. W = qV ⇒ VA - VB = 2/20 = 0.1 V Here W is the work done in moving charge q from point A to B r = mv / Bq is same for both K.E. is maximum and P.E minimum at mean position Angular momentum = conserved 1 1 Mω1 MR2 ω1 = 2mR2 ω + MR2ω ⇒ ω = 2 2 M + 4m 18. 19. The condition to avoid skidding, v = µrg = 0.6 × 150 × 10 = 30 m / s v= 2gh = 2 × 10 × 20 = 20 m / s 19 www.estudentzone.com www.estudentzone.com 20. 21. 22. 24. 27. 28. 29. 32. 33. K 800  x2  2 W = ∫ Fdx = ∫ Kxdx = K   = [ x 2 − x 1 ] = [(0.15)2 − (0.05)2 ] = 8 J 2 2  x1 2 2 x1 x1  x2 x2 x2 Conserving Linear Momentum 2Mvc = 2Mv - Mv ⇒ vc = v/2 It will compress due to the force of attraction between two adjacent coils carrying current in the same direction Semiconductors are insulators at low temperature Neutrons can’t be

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