Show the steps of conversion that you used. Adding leading zeroes creates the number 001101102 which can be split into 00112 and 01102 the hexadecimal value for these two bytes are 316 and 616 respectively so this number would be 3616 Exercise 1.3.6 Represent the hexadecimal value f616 in binary and decimal. Show the steps of conversion that you used. F16 = 11112 and 616 = 01102 when put together the binary value is 111101102 which is equal to 246. Lab 1.3 review 1.
Use the commutative and associative laws to write at least three expressions equivalent to (3x)y. Copyright 2011, 2007, 2003, 1999 Pearson Education, Inc. Slide 94 3C • b Properties of Real Numbers Use the commutative and associative laws to find equivalent expressions. Copyright 2011, 2007, 2003, 1999 Pearson Education, Inc. Slide 95 3C Properties of Real Numbers Use the distributive laws to multiply expressions like 8 and x – y. Consider a multiplication problem from arithmetic: To carry out the multiplication, we actually added two products. That is, Copyright 2011, 2007, 2003, 1999 Pearson Education, Inc. Slide 96 3C Properties of Real Numbers Use the distributive laws to multiply expressions like 8 and x – y. Compute in two ways: Copyright 2011, 2007, 2003, 1999 Pearson Education, Inc. Slide 97 3C Properties of Real Numbers The Distributive Law of Multiplication over Addition Copyright 2011, 2007, 2003, 1999 Pearson Education, Inc. Slide 98 3C Properties of Real Numbers The Distributive Law of Multiplication over
3mn4 + 6mn4 9. −11c4d + 12c4d 8. 12g2 − 7g2 10. 42z3 − 15z3 Write each polynomial in standard form. Then name each polynomial based on its degree and number of terms.
Given any input (a0,a1,a2,…a2n-1 describe the permutation of the leaves of the recursion tree. (Hint: write indices in binary and see what the relationship is of the bits of the ith element of the original sequence and the ith element of the resulting permutation of elements as they appear on the leaves on the recursion tree.) 3) Timing Problem in VLSI chips. Consider a complete balanced binary tree with n = 2k leaves. Each edge has an associate positive number that we call the length of this edge (see picture below).
Radicals Tips 1. Make sure that one of the two factors of the radicand (expression under the radical) is the largest perfect square: Example: Simplify 72 Correct 72 = 36 ∙ 2 = 62 Incorrect 72 = 9 ∙ 8 = 38 2. To be able to add or subtract radicals, the radicands must be the same. Example 1: Add 32 + 52 Answer: Since radicands are the same, (3 + 5)2 = 82 Example 2: Subtract 73 - 3 Answer: (7 – 1)3 = 63 Example 3: 318 - 52 (Must simplify first) 39 2 - 52 3 ∙ 3 ∙ 2 - 52 92 - 520 Answer: 42
Problem 2. Find a recurrence relation for un , the number of bit strings of length n that do not contain two consecutive zeros, by (a): using the recurrence relation zn for the number of bit strings of length n that do contain two consecutive zeros. SOLUTION: We simply observe that all strings of length n either do or don’t have two consecutive zeros; mathematically, this means that zn +un = 2n . Hence, un = 2n −zn = 2n −(zn−1 +zn−2 +2n−2 ). (b): by reasoning from scratch.
(b) Solve the circuit. That is find all unknown currents, voltages, and resistances. 6. Consider the circuit in Figure 4, where R1 = 5.00×102Ω, R2 = 1.00×103Ω, and VB = 10.0V . (a) Find the equivalent resistance Req of the circuit.
Randy Michael NT 1210 Lab 1.1 Professor Chibuzo Onukwufor 4/1/15 Lab 1.1 1: Convert the decimal value 127 to binary. Explain the process of conversion that you used. Decimal Number | Binary Number | Remainder | 127 - | 64 | 63 | 63 - | 32 | 31 | 31 - | 16 | 15 | 15 - | 8 | 7 | 7 - | 4 | 3 | 3 - | 2 | 1 | 1 - | 1 | 0 | Binary | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | Decimal | 128 | 64 | 32 | 16 | 8 | 4 | 2 | 1 | Conversion | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | I took the decimal and divided it by two giving 1 for the remainders and 0 if it did not have a remainder. 2: Explain why the values 102 and 00102 are equivalent. They are equivalent because they represent the powers of 10 3: Based on the breakdown of the decimal and binary systems in this lab, describe the available digit values and the first four digits of a base 5 numbering system.
TOPIC 8 Chi-Square goodness-of-fit test Problem 12.1 Use a chi-square goodness-of-fit to determine whether the observed frequencies are distributed the same as the expected frequencies (α = .05) Category | fo | fe | 1 | 53 | 68 | 2 | 37 | 42 | 3 | 32 | 33 | 4 | 28 | 22 | 5 | 18 | 10 | 6 | 15 | 8 | Step 1 Ho: The observed frequencies are distributed the same as the expected frequencies Ha: The observed frequencies are not distributed the same as the expected frequencies Step 2 df = k – m – 1 Step 3 α = 0.05 x 2 0.05, 5df = 11.0705 Step 4 Reject Ho if x 2 > 11.0705 Category | fo | fe | | 1 | 53 | 68 | | 2 | 37 | 42 | | 3 | 32 | 33 | | 4 | 28 | 22 | | 5 | 18 | 10 | | 6 | 15 | 8
Set up the matrix equation to solve this system. 2. Given the inequality y < x2 + 2x – 3, is the point (0, -3) part of the solution? Name a point that is part of the solution and one that is not. 3.