Zinc Iodine Essay

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Observations Chemical Observation Boiling Chip Porous: small grey solid, oxidized Zinc Sulfate: white solid powder, dry Barium Iodide dehydrate: white solid powder Chemical Equation ZnSO4 7H2O(aq) +BaI2 2H2O(aq)9H2O(l) + BaSO4(s) + ZnI2(aq) Tabulated Masses Substance Mass in Grams Zinc Sulfate .45grams Barium Iodide .68grams Boiling Tube + Boiling Chip 41.6g+.01=41.16grams Boiling Tube + Boiling Chip + Zinc Iodide 42.1grams Zinc Iodide 42.12g-41.6g-.01g= .51grams Calculations 1) Theoretical yield of Zinc Iodide: .45 * 319.17=143.62/287.34=.49998=.50 The theoretical yield is .50grams 2) Percent yield: Actual is .51, theoretical is .50 so .52/.5=1.02 * 100%=102% the percent yield of zinc iodide is 104% Theoretical Yield Percent Yield .45*319.17=143.62/287.34=.49998= .50 grams .51/.50=1.04*100%= 102% Steps 1) Weigh the Boiling tube: 41.6 grams 2) Weigh out .45grams of zinc Sulfite: .45 grams 3) weigh two test tubes: test tube 1) 5.61 grams, test tube 2) 5.28 grams 4) pour zinc sulfite into test tube 1 and add 2mL of water 5) weigh barium iodide: .68 grams 6) pour barium iodide into test tube two and add 2mL of water Observation: Barium mixed with water turned into a yellow mixture with barium on the sides of the test tube. 7) Combine test tube 1 and test tube 2 Observation: solution turned baking powder white 8) Wash test tube one into test tube 2 Observation: solution became less cloudy, you can see the barium sulfate on the walls. The mixture set lower than the water. 9) Centrifuge for 1 minute

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