G. Take pulse for 10 seconds and multiply by 6. ___630___ H. Do 3 to 5 minutes of stretching exercises. I. Take pulse for 10 seconds and multiply by 6. __934____ J.
C. Take pulse for 10 seconds and multiply by 6. 110 D. Do 3 to 5 minutes of stretching exercises. E. Take pulse for 10 seconds and multiply by 6. 90 F. Jog slowly for 440 yards. G. Take pulse for 10 seconds and multiply by 6.
Find the mass of the 5 dry pennies, then record the data. 2. Add 5 more pennies to the first group for the mass of 10 pennies, record mass. 3. Repeat step two, then continue adding 5 dry pennies each step to balance until you have used all 30 pennies 4.
Repeat steps 1-5 for trial 2. Variables and Control test: Independent Variable: Amount of each reactant poured into the test tubes Dependent Variable: Height of each solution Constant variables: Amount of time waiting for solution Data Table: Test tube # | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | Trial 1 | 0.5 cm | 1.0 cm | 1.1 cm | 1.5 cm | 1.5 cm | 1.5 cm | 1.3 cm | 1.5 cm | Trial 2 | 0.5 cm | 0.7 cm | 1.0 cm | 1.0 cm | 1.3 cm | 1.7 cm | 1.9 cm | 1.5 cm | Observation/Analysis: Solution turns yellow when a separate product is added, solid of the solution leaks down to the bottom after 20 minutes. Conclusion: The group tried to find the excess or limiting for the reaction between KI and Pb. In the end the hypothesis was supported by the data. We found that little amounts of each product led to a greater height of solids.
1 set of 20 rounds at 300m using 5-round shot groups to obtain 6 out of 10 rounds within 19-inch circle. ENABLING LEARNING OBJECTIVE: Action- Identify procedures for BRM Confirm Zero Range Conditions-
If 0.100 mol of hydrogen iodide is placed in a 1.0 L container and allowed to reach equilibrium, find the concentrations of all reactants and products at equilibrium. 2 HI (g) === H2 (g) + I2 (g) Ke = 1.84(10-2 [H2]=[I2]= 1.07(10-2 mol/L, [HI]=7.86(10-2 mol/L 6. A 1.00 L reaction vessel initially contains 9.28(10-3 moles of H2S. At equilibrium, the concentration of H2S of 7.06(10-3 mol/L. Calculate the value of Ke for this system.
It told us the only way to change the motion of an object it to apply a force. en.wikipedia.org/wiki/Isaac_Newton 6. How much force are you exerting when you lift a 50-pound dumbbell? What units will you use to describe this force? F= Force M=Mass g=Earth gravity 50 pounds= 22.67 KG F=22.67 X 9.8 N =222.16 N You are exerting 222.16 N(Newton)
Why is this necessary? Obtain an appropriate amount of 5.00 M NaCl and fill your 25 mL buret. Pipet a 20.00 mL aliquot of 0.100 M acetic acid solution into a 100 mL beaker, add a magnetic stirring bar, and then set up the titration apparatus as indicated in Figure 1. Record the initial pH and then begin titrating. You will titrate in 0.25 mL intervals for the first 2 ml and then in 1 mL intervals until a total of 6 mL of 5.00 M NaCl has been delivered.
c. Prepare the solution by dissolving 38.90 grams of ZnI2 with 500 mL of water. d. 0.0125/0.25 = 0.05 L = 50 mL. This produces 0.0125 moles of ZnI2 5. Exercise 5: a. (0.125)(0.1) = 0.0125 moles of solute b. Pour 50 mL of the stock solution to get the number of moles needed.
For example, if a particular isotope has a half-life of 20 yr, and the starting amount of the isotope is 100 mg, how much of the isotope will be left in exactly 100 yr? To solve this problem, we first make a chart containing the information we know. time |0 yrs | | | | | | | |amount |100 mg | | | | | | | | Since the half-life is 20 yr, each time interval in the chart should add 20 yr to the previous interval until the time of 100 yr is reached. time |0 yr |20 yr |40 yr |60 yr |80 yr |100 yr | |amount |100 mg | | | | | | | Since the time represented by each interval is the half-life of the isotope, the amount of the isotope must decrease by 1/2 for each interval. For instance, at the end of the first 20 yr interval, the amount of the isotope would decrease by 1/2 to 50 mg.