Nuclear fusion however is the reaction in which two or more nuclei combine together to form a new element with higher atomic number. The fusion of two nuclei with lower masses than iron generally releases energy, while the fusion of nuclei heavier than iron absorbs energy. This means that fusion generally occurs for lighter elements only, and likewise, that fission normally occurs only for heavier elements. For a nuclear fusion reaction to occur it is necessary to bring two nuclei so close that nuclear forces become active and glue the nuclei together. Nuclear forces are small-distance forces and have to act against the electrostatic forces where positively charged nuclei repel each other.
How pollution reduction policies have attempted to lessen the incidence of particulate pollution and photochemical smog. (10 marks) Particulates are tiny pieces of solids and tiny droplets of liquids floating in the air and are in a higher concentration. Photochemical smog is formed by pollutants such as nitrogen oxides, sulphur oxides, and hydrocarbons, coming into contact with UV light, which means they break down into harmful chemicals such as ozone, which forms photochemical smog. Lots of cities have tried to reduce pollution by reducing traffic; there are various ways this can be done. One of these methods is congestion charges, London adopted this method meaning any vehicle owner who wants to drive into the CBD must pay a charge to do so, this has been successful and since 2003, there has been a 15% reduction in traffic and emissions in the congestion zone.
In addition, MobAir has significantly more production capacity. Although having large production capacity is a liability during times of weak demand, such as the ones characterizing the current market, it becomes an advantage during times of strong demand. With larger capacity, Team PinkLadies has the ability to grow its sales and thus its market share more rapidly. Understanding the threat that this presents, MobAir has begun increasing plant
In this process, the original atom will lose two neutrons and two protons, changing the element’s atomic number and mass, and subsequently making it into a different element. My model clearly and simply demonstrates this process due to the fact that it does not over complicate the process. I did not label the parent atom intentionally, to imply that this process can generally happen to almost any charged particle. Also, empty spaces are left in the atom to show that the particles that form the helium nucleus were released. On top of this, the helium nucleus is clearly labeled and is shown containing two neutrons and two protons (which are also labeled using an “N” and a “+”).
Gas Law Problems - Graham's Law Return to Graham's Law Return to KMT & Gas Laws Menu Problem #1: If equal amounts of helium and argon are placed in a porous container and allowed to escape, which gas will escape faster and how much faster? Solution: Set rate1 = He = x Set rate2 = Ar = 1 The molecular weight of He = 4.00 The molecular weight of Ar = 39.95 Graham's Law is: r1 over r2 = √MM2 over √MM1 Substituting, we have: x / 1 = √(39.95 / 4.00) x = 3.16 times as fast. Video: Solution to a Graham's Law Problem Problem #2: What is the molecular weight of a gas which diffuses 1/50 as fast as hydrogen? Solution: Set rate1 = other gas = 1 Set rate2 = H2 = 50 The molecular weight of H2 = 2.02 The molecular weight of the other gas = x. By Graham's Law (see the answer to question #1), we have: 1 / 50 = √(2.02 / x) x = 5050 g/mol Video: Solution to a Graham's Law Problem Problem #3: Two porous containers are filled with hydrogen and neon respectively.
I will be using these in my experiment to measure the resistance of the wire. My Prediction I predict that the longer wires will have bigger resistance. I think this because in a longer wire the electrons will have more collisions
The neutralization, reduction, or removal of fission products and subsequently their associated negative effects will allow for higher burnup in nuclear reactors. Source and Quantity of Fission Products The total quantity of fission products present in the fuel can be determined by a direct mass balance relating the rate of production by fission (requires that the fission product yield be known) to the rate of loss by radioactive decay. In order to determine the overall fission product yield the contribution from beta decaying precursors to the independent yield of the isotopes must be accounted for. The independent fission yield (iy) is the
2. “A body at rest will remain at rest unless acted upon by an outside force.” Example- A car accelerates from a stop sign or a stopped car is propelled forward by a rear –end collision. Conservation of Energy The law of conservation of energy states, “Energy can neither be created nor destroyed. It can only be changed from one form to another.” Example- If a car slows down gradually; the brakes develop friction and heat. During an auto crash, the transfer of energy happens at a much greater rate into different forms.
During the explosion not only are gases produced quickly, but they are also hot, and they expand rapidly, according to Charles’ Law, which states that as the temperature of enclosed gas increases, the volume increases, if the pressure is consistent(Antonis, K. 2010). The chemical reaction the firework puts off is when [a]toms, as well as molecules, come together to form larger molecules, and larger molecules break up(Trefil, 2014). The chemical reaction also depends on the color of the firework. How do Chemists make the colors for Fireworks? When scientists make the different colors, each color has its own element.
Student designed practical investigation Title: Atwood’s Machine (Newtons 2nd law of motion). Partner: Qurban Aim: To explore how two different masses act with each other on a pulley and therefore calculate acceleration a (theoretical and experimental) and the Tension T. Hypothesis: When both masses are the same, there should be no acceleration. The larger the ratio between one mass and the other, the higher the acceleration should be. Materials: Pulley, string, mass 1 + 2, ruler, stopwatch, scissors Apparatus: Theory: Since we are trying to find a, the equations we need are: For experimental a: Transposed to: Theoretical a: For tension: where x = displacement u = initial velocity t = time taken = mass 1 = mass 2 Let Method: 1. Set up the apparatus in the diagram above.