Measure the time it takes to completely dissolve. Record time in data table. Cold Water: Fill beaker with 80mL if ice water. Use thermometer to record temperature of water. Record the temperature.
It binds with starch so the more starch, the darker the solution was. We also used a blank solution with no starch to set the spectrometer to zero. The spectrometer was used to compare the absorbency of the starch in the control solutions and the non-control solutions over time. Amylase was the last solution added to start the initial breakdown of the starch. Adding it at one minute intervals allowed the students to see how much starch the amylase was actually breaking down over time.
Jessica Yan Rick St. Denis, Tyler Wiseman 13 September 2012 Projectile Motion: Ball in the Bin Purpose: The purpose of the experiment is to determine the velocity of a ball launched from the Projectile Launcher device, and then to use that velocity to find where on the floor the ball will land given a specific angle. Theory: Two-dimensional motion is as it sounds, made of the two components of Vertical velocity and Horizontal Velocity. Horizontal Motion can be described as constant, neglecting air resistance, and Vertical Motion is characterized by the acceleration of gravity pulling at 9.8m/s². In this particular experiment, the total velocity will be split into the two components in order to find the time in the air, and horizontal distance from the launcher. The motion of these components can be described as d=vt for constant horizontal motion, and d=1/2at² + Vit.
Physics Lab Report: Popper Hopper. Purpose: The purpose was to find the speed of a hopper popper as it leaves the table. Materials: The materials used were a timer, ruler and a popper Procedure: I put the popper on the table. When it popped up in the air i looked how high it went up and how long it took. Data: |Trial # | | |4.5 secs |52 cm | |3.1 secs |90 cm | |2.8 secs |84 cm | |1.3 secs |74 cm | |.8 secs |65 cm | Calculations & Data Analysis: Given: mass = .0102 kg, height = .73 m, g= 9.8 m/s Unknown: velocity?
6. Describe how frequency of sEMG spikes changed with increasing muscle load. The frequency of sEMG spikes started increasing as the muscle load increased until it reached it's optimal point at a 5 lb threshold and then started to slowly decreased thereafter. 7. Based on changes in amplitude and frequency of sEMG, did motor unit activation increase, decrease, or stay the same with increasing muscle load?
Determining the mass of the two unknown weights (unknown weight #1 and #2) was determined using only the centigram balance using the weighing by difference method. Unknown weight # 1 had a mass of 24.82 g while unknown weight #2 had a mass of 25.17 g. The average mass experiment was conducted by individually weighing five different copper slugs on an electronic balance, then
Marshmallows and Balloons Reveal a Change in Volume Due to Increasing and Decreasing Pressures Chemistry Period 1 20 February 2013 Chemistry- Per.1 20 February 2013 Marshmallows and Balloons Reveal a Change in Volume Due to Increasing and Decreasing Pressures INTRODUCTION Pressure can define the amount of volume in an object depending on how much is used, hence Boyle’s Law. Some scientists have tried to understand the different ways that gases work. Boyle is one of the scientists that experimented with gases; he states that whenever the pressure of a gas increases, the volume of the gas will decrease, and vise versa. Demonstrated in Mr. Squiddy’s demo, when the bottle was squeezed he would float down and when it was released he would float back up. Some might think that by squeezing the bottle, Mr. Squiddy would go up with the water however, he would go down due to the pipette being used.
Friction Objectives: To provide an understanding of the concept of friction. To calculate the coefficient of friction of an object by two methods. Materials: Ramp board: 3 - 4 feet long, 10 cm wide Can of soft drink or item of similar weight Friction block set-PK Protractor Scale-Spring-500-g Tape measure, 3-m Lab notes: Using the wooden block provided in LabPaq, a long board, a can of beans and the 500-g spring scale I will try and determine the force of kinetic friction, N, and the force of static friction, N while pulling the block at a constant speed. I will convert kg-mass to Newtons by multiplying the kg-weight by 9.8 m/s2, i.e., 100 g = 0.1 kg = 0.1 x 9.8 = .98 N. Observations: Mass of block (with can): 3995 kg Weight: 3.91 N Data Table 1: Flat board Flat board Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.1 0.6 Trial 2 1 0.7 Trial 3 1 0.9 Average 1.03 0.73 Data table 2: Flat board - Block Sideways Mass of block (with can) 3995 kg Weight: 3.91 N Flat Board - Block sideways Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.3 1.4 Trial 2 1.1 1.5 Trial 3 1.1 1.1 Average 1.2 1.5 Data Table 3: Different surfaces Surfaces tried: Glass surface Force of Kinetic Friction, N Force of Static Friction, N Trial 1 0.4 0.1 Trial 2 0.4 0.1 Trial 3 0.4 0.2 Average 0.4 0.13 Data Table 4: Different Surfaces Surfaces tried: Sandpaper Force of Kinetic Friction, N Force of Static Friction, N Trial 1 2.2 1.5 Trial 2 2.1 1.7 Trial 3 2 1.1 Average 2.1 1.43 Data Table 5: Different Surfaces Surfaces tried: Wood on Carpet Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.4 1.9 Trial 2 1.5 1.6 Trial 3 1.5 1.7 Average 1.47 1.73 Data Table 6: Raised Board Height Base Length θ max μs Trial 1 .44196 m .71120 m 60 deg 0.62143 Trial 2
Record Person A’s average time to the nearest .1s 5. Repeat steps 1, 3, and 4 for Person B Results/Observations: We measured the vertical height of the stairs from the basement to the second floor and found that this was 3.76 meters. To find the mass of each person, we multiplied their weight in pounds by .454 to get the value in kilograms. To find the weight of person A and B, we multiplied their mass in kilograms by 9.81. Person A (187.6 lbs x .454 = 85.0939 kg) Weight= mass(gravity) Work=(Fcosθ)s Power= (Work/Time) Weight= 85.0939kg( 9.81) Work= (843.77cos0) 3.76 Power= (3172.6J/4.6s) Weight= 843.77 N Work= 3172.6 J Power= 689.7 W Horsepower= Watts/746 PEg=mgh Power= Force(velocity) Horsepower= 689.7/746 PEg=(85.0939)(9.81)(3.76) 689.7= 843.77 v Horsepower= .925hp PEg=3138.74J .82 m/s = velocity Person B (140 lbs x .454 = 63.56 kg) Weight=mass(gravity) Work=(Fcosθ)s Power= (Work/Time) Weight=63.56kg(9.81) Work=(623.5cos0)3.76 Power= (2344.4/14.53) Weight=623.5 N Work= 2344.4 J Power= 161.3 W Horsepower= Watts/746 PEg=mgh
5 .For part III, Average was needed to be found after Find the Mass/A of each all 5 disk. To do that Add all the values in Table 3 and divide them by 5. 6 .For Part III, Percent difference between the average value and the slope of the derivative diameter graph was found by doing this: ((slope of the derivative vs. diameter graph- average)/slope of derivative vs. diameter graph)*100 =67.9% VII. Analysis Questions/Answers 1. The Slope in Part I represents π 2.