Subtract -28 – (-17). a. -45 b. 11 c. -11 d. 45 20. Find the difference between -27 and -32. a.
This shows me that the median age of the male is 26 which is 1.33 years less than the average male age and 4.1 years younger than the average female. Now I will look at the mode for the ages of the men: 19 21 22 26 26 28 29 34 41. In this situation there is only mode in the men’s ages which is 26 because this is the only age of the males that appears more than one time. The median age and mode age is the same for the males for this survey which is actually 1.33 years less than the average male. The measure of central tendency that best described my data for the age in my sampling was the mean because the results showed that the average female at 30.1 years old.
kg HCl = 6.0 × 105 ton HCl soln 100 ton HCl soln 1 ton 2.205 lb 30 ton HCl 2000 lb 453.6 g 1 kg ? kg HCl = 6.0 × 105 ton soln 3 100 ton soln 1 ton 1 lb 10 g = 1.6 108 kg HCl 88. A typical nonobese male has about 11 kg of fat. Each gram of fat can provide the body with about 38 kJ of energy. If this person requires 8.0 103 kJ of energy per day to survive, how many days could he survive on his fat alone?
Standing erect, a measurement was taken from the axillary to the longest finger tip of each subject 4. Standing erect, a measurement was taken of each subjects height minus shoes 5. #3 and #4 data was collected from each subject and logged 6. Height was multiplied by .4 to determine expected upper limb length and logged 7. Upper limb length was divided by height to give actual % of height and logged TABLE 1.1 Subject: | Measured Upper Limb Length (cm) | Height | Height x 0.4= Expected Upper | Actual % of Height = Upper Limb Length (cm) Height (cm) | Shane | 71.5 | 178.6 | 71.4 | 40% | Gena Lyn | 62.9 | 155.6 | 62.2 | 40.40% | Kayli | 76.4 | 163.9 | 65.5 | 46.60% | L.B.
Then use the multiplication principle and then use the elimination method: 3x=8y+11 x+6y-8=0 9. A vending machine contains nickels and dimes worth $14.50. There are 95 more nickels than dimes. How many nickels and how many dimes are there? 10.
Multiplication and division were performed here as part of the equation. According to the results, people who may be at the height of 65 inches and weigh between 146.2lbs and 174.2lbs may be overweight. 25.1(4096)/703<W<29.9(4096)/703 102809.6/703<W<122470.4/703 146.2<W<174.2 INEQUALITIES 4 For this last weight interval, we shall find those who may be obese at this height. For this compound inequality, all I need to do is take the middle and right terms of the basic inequality and substitute 30 for 29.9. I multiplied the terms and then divided them.
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2a. What is the shortest loan (36 months, 48 months, 60 months or 72 months) that has a monthly payment within your $500 budget that will allow you to buy the $30,000 car? Answer: Through Bank of America, I found a rate of 2.99% for the 36, 48 and 60 month loans. We are able to put down 20% and will need to finance $24,000. The shortest loan period for the $30,000 car that would be under our $500 limit is the 60 month loan at a rate of $431.13 per month.
Math 80 Final Exam Review (Chapter 9 -11) This is not worth any points. The actual final exam will not have this many problems. I put more problems on this review to help you practice. Review the homework problems. Anything that was a homework problem could appear on the final exam.
The total risk score is 4.14, the greatest relative or standardized difference between pretest and 3 month outcomes. This t ratio has a statistical significance of 0.05 - the least acceptable value for statistical significance. Also the larger the t ratio, the smaller the observed p value and increased odds of being able to reject the null hypothesis. 3. Which t-ratio listed in Table 3 represents the smallest relative difference between the pretest and 3 months?