100. g Al reacts with excess O2 to produce 150. g Al2O3 according to Calculate the theoretical and percentage yield. 4Al + 302 → 2 Al2O3. 79.4 % 14. Calculate the energy produced by the complete reaction of 150. g H2. 2H2 + O2 → 2H2O + 130KJ 4.83 x 103 kJ 15.
-0011 0110 0011 represents 3 0110 represents 6 - 36 Exercise 1.3.6 Represent the hexadecimal value f6 16 in binary and decimal. Show the steps of conversion that you used. - The best way I feel to do this propose is to change it to binary first. - F is 1111 - 6 is 0110 - 11110110 in binary - Then do the decimal step , 246 Lab 1.3 Reviews Explain why it is important to know how many system words will fit in a primary storage device on a computer (such as the hard drive). -So that you know how much ad primary storage unit can hold.
Solve using the multiplication principle first. Then use the elimination method. 2x+y=13 4x+2y=23 8. Solve by rearranging the equations first. Then use the multiplication principle and then use the elimination method: 3x=8y+11 x+6y-8=0 9.
Experimental Data Trial 1 Trial 2 Trial 3 Sample Volume 10 mL 10 mL 10 mL Weight sample + capped vial 26.5g 26.5g 26.3g Weight vial + cap 15.5g 15.4g 15.4g Sample weight 11.0g 11.1g 10.9g Calculated Results Trial 1 Trial 2 Trial 3 Density of samples: 1.10g/mL 1.11g/mL 1.09g/mL Average density: 1.10g/mL 1.10g/mL 1.10g/mL Deviation from Average: ±0.00g/mL ±0.01g/mL -0.01g/mL Average Deviation: add absolute values of deviations from average and divide by the number of trials. +0.00++0.01+-0.01= 0.02 ∴ Therefore, the average deviation in density = ±0.02/3 = ±0.01 Average weight of 10mL Volume Samples 10mL x 1.1g/mL = 11g Percent Inherent Error in Average Weight of Samples ±0.1 g/reading*2 readings 11* 100 = 1.8~2% Percent Inherent Error in Average Volume of Samples ±0.1 mL/reading*1 readings 10 mL*100 = 1% Total Percent Inherent Error in Density ±2%+ ±1%= ±3% Inherent Error in Density 1.10g/mL x (±3/100) = ±0.03g/mL Conclusions Since the deviations from the average density are equal to or less than the total possible inherent error computed, it is concluded that the precision of the data collected was good. Second
3. The rate variance is calculated by the difference between the $16.90 actual labor rate vs the $16 budgeted rate, then we multiply the difference by the 9000 actual labor hours which gives us an $8,100 unfavorable rate variance. To figure out the efficiency variance we multiply the $16 budgeted rate by the difference between the 9,000 actual labor hours and the 10,000 budgeted hours, giving us a $16,000 favorable efficiency variance. As a result of the difference between the rate and efficiency variances we end up having a $7,900 favorable flexible budget variance. 4.
The tax on the year 1 deprecation would then be $28,050 * .40, which equals $11,220. After adding $11,020 to the $15,000 in savings, the cash flow for year 1 would equal $26,220. For year 2, the depreciation expense would equal $85,000 * .45, or $38,250. The tax on the year 2 deprecation would then be $38,250 * .40, which equals $15,300. After adding $15,300 to the $15,000 in savings, the cash flow for year 2 would equal $30,300.
Radicals Tips 1. Make sure that one of the two factors of the radicand (expression under the radical) is the largest perfect square: Example: Simplify 72 Correct 72 = 36 ∙ 2 = 62 Incorrect 72 = 9 ∙ 8 = 38 2. To be able to add or subtract radicals, the radicands must be the same. Example 1: Add 32 + 52 Answer: Since radicands are the same, (3 + 5)2 = 82 Example 2: Subtract 73 - 3 Answer: (7 – 1)3 = 63 Example 3: 318 - 52 (Must simplify first) 39 2 - 52 3 ∙ 3 ∙ 2 - 52 92 - 520 Answer: 42
Solve the system of equations algebraically to determine when the two savings plans yield identical balances and state this balance. Plan A Balance = Y1 = (20)X + 400 Plan B Balance = Y2 = (10)X + 600 When Two Saving plan yield same balance the algebraically we can demonstrate it with following equation. Plan A Balance (Y1) = Plan B Balance (Y2) Mean Y1=Y2 (20)X + 400 = (10)X + 600 (20)X – (10)X
MAT221: Introduction to Algebra Week 5 Discussion Factoring According to what I calculated, the GCF of 92 and 64 is 4. I found this answer by : Divisor 92 divided by 4 equals 23 and 64 divided by 4 equals 16. I used the factor of numbers to help me. 92/4=23 1,2,4,23,46,92 2/24 2/12 2/6 3/3 64/4=16 1,2,4,8,76,32,64 24=2x2x2x3 Prime factors are also know as natural numbers. It means a number that is more than one and I can only divide it by one, and has no remaining numbers.
Using the Pythagorean Theorem, solve for the missing sides. ____________10) ___________ 11) Find the value of x and y in each special right triangle. Give final answers in most simplified form. 12) x = _____y = _______ 13) x = ______y = ______ 14) x = _____y = _______ REGULAR POLYGONS 15) Given a hexagon with apothem length of [pic]cm. Determine the following.