A quota sample C. A convenience sample D. A probability sample 6. Which of the following is not a method of probability sampling? A. Simple random sampling B. Systematic random sampling C. Stratified sampling D. All of the above are methods of probability sampling 7.
2.12 b. 1.734 c. -1.740 d. 1.740 ANSWER: d -same process but now go to one tailed α=0.05 and dof = 17 4. Read the t statistic from the table of t distributions and circle the correct answer. A one-tailed test (lower tail), a sample size of 10 at a .10 level of significance; t = a. 1.383 b.
Absolute value (ABSO) is: Represents the distance a number is from zero no matter it’s a positive or negative number. For example, the number 5 would have an absolute valve of 5 and the number -5 would also have an absolute value of 5. 11. Define Confidence interval and level In statistics, a confidence interval (CI) is a type of interval estimate of a population parameter and is used to indicate the reliability of an estimate. It is an observed interval in principle different from sample to sample, that frequently includes the parameter of interest if the experiment is
We can conclude that the data are Poisson distributed. Chi-Square test of independence Problem 12.12 Use the following contingency table to determine whether variable 1 is independent of variable 2. Let α = .01 | Variable 2 | Variable1 | 24 | 13 | 47 | 58 | | 93 | 59 | 187 | 244 | Step 1 Ho: the two classifications are independent Ha: the two classifications are dependent Step 2 d.f = (r – 1) (c – 1) Step 3 α = 0.01 x 2 0.01, 3df = 11.3449 Step 4 Reject Ho if x 2 > 11.3449 | Variable 2 | Total | Variable1 | 24 (22.92) | 13 (14.10) | 47 (45.83) | 58 (59.15) | 142 | | 93 (94.08) | 59 (57.90) | 187 (188.17) | 244 (242.85) | 583
Carry it over to the right. 32 is less than 63 so you will subtract and put a 1 for that value, and continue down the line. 2. Explain why the values 102 and 00102 are the same. Because when you plug the binary numbers into the 8 bit conversion table, the two zeros before the 10 equal nothing.
The coefficient of correlation is given as r = 0.752843. The positive sign of the correlation coefficient indicates a positive or direct
Rules For Sig. Figs: 1. All non zero digits are significant  1466 = 4 sig figs 2. Zeros: o Zeros between non zero digits are significant  1048 = 4 sig
Using the data from attachments 10-11 (provided below), compute the optimal portfolio allocations if the portfolio mean return objective is 6.4% with some constraints (all weights sum to 100%, weights on cash >= -50% and weights on all other asset classes >=0) and the investor wishes to minimize standard deviation. What is the standard deviation and sharpe ratio of this portfolio? 11. Repeat for returns of 4.4-9.4% with increments of .5% (a total of 11 optimizations, e.g. 4.4, 4.9, 5.4… 9.4).
5. A test statistic is a value determined from sample information used to reject or not reject the null hypothesis. 6. The region or area of rejection defines the location of all those values that are so large or so small that the probability of their occurrence under a true null hypothesis is rather remote. 7.
Statistics 121 Problem set #1 1. Suppose {A, B, C, D, E, F} is a partition of the sample space Ω. Suppose it is known that P(A∪B∪C)= 0.6. The probability of event B is the same as the probability of event D. It is also known that P(A∪B)= P(E∪F)= 0.5 P(B∪C). Find the probabilities of the following events: a) B Solution: PA∪B∪C=0.6 ; PD∪E∪F=0.4 PB= PD = PA∪B= PE∪F = PA+ PB= PE+ PF = PA+ PB= 0.4- PD = PA+ PB= 0.4- PB = PA+ 2PB= 0.4 PA∪B= 0.5PB∪C 2PA+ 2PB= PB+ PC 0.4 + PA= PB+ PC 0.4 + PA+PA= PA+PB+ PC 0.4 + 2PA= 0.6 2PA= 0.2 PA= 0.1 PA+ 2PB= 0.4 0.1 + 2PB= 0.4 2PB=0.3 PB=0.15 b) c) A∪B∪D = PA+ PB+ PD = PA+ 2PB = 0.1 + 2(0.15) P(A∪B∪D)= 0.4 * I can’t find numbers 2, 3 and 4 5.