24•3•5 b. 2³•3²•5 c. 2³•3•5² d. 24•3²•5 11. Evaluate: x4y² when x = 2 and y =11. a. 176 b.
Arkansas, 435 U.S. 475 (1978). ............................................ 13 Morgan v. United States, 309 F.2d 234, 237 (D.C. Cir. 1962) ...................... 8 People v. Belge, 83 Misc. 2d 186 (N.Y. County Ct. 1975) ......................... 14 People v. Collie, 30 Cal. 3d 43 (1981)....................................................... 13 Richmond Newspapers, Inc. v. Virginia, 448 U.S. 555 (1980) ................... 13 State v. Kociolek, 23 N.J. 400 (1957)........................................................ 14 United States ex.
72 PSATP = P part(O2) + P part(CO2) + P part(N2) P part(N2) = PSATP - P part(O2) - P part(CO2) P part(N2) = 101.3 kPa – 79 kPa – 0.75 kPa = 21.55 kPa Answer: P part(N2) = 21.55 kPa 73 PV=nRT n = PV/RT P = 2500 kPa V = 12 L R = 8.314 J/mol*K T = 22 + 273.15 = 295.15 K n = (2500000*12*10-3m3)/ (8.314 J/mol*K*295.15 K) = 12.22 mol. Answer: n = 12.22 mol. 74 C3H8 + 4O2 => 3CO2 + 2H2O n (O2) = 3.5 mol * 4 = 14 mol PV = nRT V(O2) = nRT/P V(O2) = (14 mol * 8.314 J/mol*K *(28 + 273.15) K) / 1.013 * 105 Pa V(O2) = 0.3311 m3 = 331.1 L Answer: V(O2) = 331.1 L 75 PV=nRT n = PV/RT n = (1.013*105 Pa * 65 * 10-3 m3) / (8.314 J/mol*K * 298 K) = 2.65 mol Answer: n = 2.65 mol 76 PV=nRT n = PV/RT n = (1.013*105 Pa * 7.5 * 10-3 m3) / (8.314 J/mol*K * 298 K)
2. (n + 11)2 3. (t + 7)2 4. (3m + 6)2 5. (4x + 1)2 6.
(a) (e) (i) 2 5 3 250 41 125 (b) (f) (j) 2 25 81 500 7 500 (c) (g) (k) 27 50 6 125 1 125 (d) (h) (l) 3 500 21 25 27 250 5. (a) (d) 3 1
(1983). Elliotts Inc. v. Commissioner. Retrieved October 9, 2010, from www.bvresources.com/BVWireCentral/Material/BVWire52-4/Elliots.pdf+ELLIOTTS+CASE&hl=en&gl=ke&pid=bl&srcid=ADGEESgBbJ3e8oifazpEIV7y7dOZwZ-YxLwZ6wO6svMZKPubg3_-Jh-b8boKReI1BeB-WnWcTglvTOvNdyKCfC9YOPchp2Y IRC Section 4958. (2010). Retrieved October 10, 2010, from http://www.sharinglaw.net/npo/section_4958.htm IRS Press.
8us; 1us 14. SECTION 1-3 15. L on = SW1 + SW2 + SW1 *SW2 16. 17. AND gate 18.
of penny | wt. of Zn(OH)2 | 0.1751 g | 27.4610 g | 18.0 mL | 30.22 g | 0.0604 g | 5.5839 g | 5.58 g Zn(OH)2 | 1 mol Zn(OH)2 | 1 mol ZnCl2 | 135 g ZnCl2= | 7.61 g
____ HCl + ____Ba(OH)2 ( ____ BaCl2 + ____ H2O 12. ____ Na + ____ O2 ( ____ Na2O 13. ____KClO3 ( ____ KCl + ____ O2 14. ____ Al + ____O2 ( ____ Al2O3 15. ____ Al + ____ CuCl2 ( ____ Cu + ____
(3d) 97, 127 B.C.A.C. 76, 207 W.A.C. 76, 175 D.L.R. (4th) 1, 25 C.R. (5th) 215, 69 B.C.L.R.