I am somewhat confident with my answer because I used simulation process correctly to find the loss of revenue and also, I used random numbers for calculating this. There are some limitations with the simulation process. The first one is that the cumulative weeks will generally not add up to accurate 52 as in my work, the final cumulative week comes as 50.968 so this is not the revenue lost in exactly 1 year. Also, if we apply simulation again then we will get the different answer for revenue loss. Therefore, it is better to apply simulation a number of times and then take the average of all those
G. Compare the values of the measured angles with the average computed values and determine their difference. 2. Determination of the sides of a right triangle when the hypotenuse and one angle are measured: A. Create a new triangle by taping the bottom of the string to a different position on the floor or table, as in Procedure 1. B.
3.03 Periodic Trends Julianne Mazzaro 1. Refer to the graph that you created in Part I of this assignment. Describe the general trend or patterns that you observed in the atomic radius as you go across the periodic table. As the number of protons (atomic number) gets bigger, the atomic radius gets smaller. The largest decrease in size was from 3 to 4, and it leveled out after the 5 to 6 decrease.
This leads to a price of 10 + 8 + 6 = 24 because the first stick was of 10 m, the resulting stick of 8 m, and the last one of 6 m. Another choice could cut at 4, then at 2, then at This would lead to a price of 10 + 4 + 6 = 20, which is better for us. Your boss demands that you design an algorithm to find the minimum possible cutting cost for any given stick. 7) Interleaving of Strings For bit strings X = x1 ... xm
We made this inference due to our slope of each of the graphs. Given the mole ratios, the slope of our newer lab, comparing H2 to moles of Mg, should’ve been a slope of 1. But our first point skewed our results giving us an actual slop of 0.7, which was short from a more accurate result. And given our results last week, we concluded that our titration method was more accurate than our crystallization method due to the basically perfect slope of 2.0018 which is very close to the theoretical slope of 2. 5.
The total risk score is 4.14, the greatest relative or standardized difference between pretest and 3 month outcomes. This t ratio has a statistical significance of 0.05 - the least acceptable value for statistical significance. Also the larger the t ratio, the smaller the observed p value and increased odds of being able to reject the null hypothesis. 3. Which t-ratio listed in Table 3 represents the smallest relative difference between the pretest and 3 months?
Begin by writing the corresponding linear equations, and then use back-substitution to solve your variables. 10–1301–8001 159–1 = x-13z=15y-8z=9z=-1 = x-13(-1)=15y-8(-1)=9z=-1 = x=2y=1z=-1 x,y,z=(2 , 1 , -1) Determinants and Cramer’s Rule: 2. Find the determinant of the given matrix. 8–2–12 = 8*2 - (-1)(-2) = 16 - 2 = 14 3. Solve the given linear system using Cramer’s rule.
Then measure the Beaker by itself and calculate the weight of the slug by difference. Then record all of the values in the table below. Then repeat this process using a second copper slug and a second 100ml Beaker and a second Centigram Balance. Next, use an electronic balance to calculate all of the same weights as mentioned before. Do this twice to get a more accurate measurement.
See the mathematics review appendix for a review of ``factor'' and ``times''. Some more examples are given in the table below. Notice how quickly an inverse square law gets very small. A comparison of inverse and inverse square relations distance | inverse | inverse square | 1 | 1/1 = 1 | 1/12 = 1 | 2 | 1/2 = 0.5 | 1/22 = 1/4 = 0.25 | 3 | 1/3 = 0.33 | 1/32 = 1/9 = 0.11 | 4 | 1/4 = 0.25 | 1/42 = 1/16 = 0.0625 | 7 | 1/7 = 0.14 | 1/72 = 1/49 = 0.02 | 10 | 1/10 = 0.1 | 1/102 = 1/100 = 0.01 | 100 | 1/100 = 0.01 | 1/1002 = 1/10,000 = 0.0001 | Example: Joe Average has a mass of 63.5 kilograms, so he weighs 623 newtons (=140 pounds) on the Earth's surface. If he moves up 1 Earth radius (= 6378 kilometers) above the surface, he will be two times farther away from the Earth's center (remember that distances are measured from center-to-center!
I first start with 0.00 less than the probability which is 0.20 then we start at 0.21 less than 0.53. I came up with 0.53 from adding the initial probability of 0.20 and the second 0.33. Next I start at 0.54 less than 0.90 these figures come from adding 0.53 plus the third probability of 0.37. Lastly, I start at 0.91 less than 1 and again I adding 0.90 plus the last probability of 0.10. Now let’s find the Average materials cost per unit.