Then, subtract 4 from 7. h4=3 3 When subtracting 4 from 7 the answer is 3. h4=3 3 Cancel out the common factors of 3 from the expression. h4=1 The final answer is 1. Simplifying the f function = f4=2(4)+5 Replace the variable x within the expression f4=2•4+5 Remove the parenthesis and multiply 2 by
Write assignment statements that perform the following operations with the variables a,b,c A. set b=a+2 B. set a=b*2 C. set b=a/3.14 D. set a=b-8 4. Assume the variables result, w,x,y, and z are all integers and that w=5, x=4, y=8, and z=2. What value will be stored in result in each in of the following statements? A. Set result = 4+8 B.
TOPIC 8 Chi-Square goodness-of-fit test Problem 12.1 Use a chi-square goodness-of-fit to determine whether the observed frequencies are distributed the same as the expected frequencies (α = .05) Category | fo | fe | 1 | 53 | 68 | 2 | 37 | 42 | 3 | 32 | 33 | 4 | 28 | 22 | 5 | 18 | 10 | 6 | 15 | 8 | Step 1 Ho: The observed frequencies are distributed the same as the expected frequencies Ha: The observed frequencies are not distributed the same as the expected frequencies Step 2 df = k – m – 1 Step 3 α = 0.05 x 2 0.05, 5df = 11.0705 Step 4 Reject Ho if x 2 > 11.0705 Category | fo | fe | | 1 | 53 | 68 | | 2 | 37 | 42 | | 3 | 32 | 33 | | 4 | 28 | 22 | | 5 | 18 | 10 | | 6 | 15 | 8
The ratio of the tagged bears to the random sample size is 48/150. 300 = 48 This is the proportion set up which makes it ready to solve. Cross multiplication X 150 is necessary at this point. The extremes are 300 and 150 and the means are x and 48. 150(300) = 48x 45000 = 48x Now we need to divide both sides 48.
ALGEBRA II Regents Review 1. Simplify: = 1 2. The expressionis equivalent to which of the following? a) b) c) d) 3. Solve for x: x = 5 4.
STAT 533 COURSE PROJECT – PART C Using MINITAB perform the regression and correlation analysis for the data on CREDIT BALANCE (Y) and SIZE (X) by answering the following. 1. Generate a scatterplot for CREDIT BALANCE vs. SIZE, including the graph of the ‘best fit’ line. Interpret.
9.2 Q1 Determine (f+g)(4) when f(x)=x^2-3 and g(x)=-6/(x-2). A1 10 Q2 What is the domain of (f-g),where f(x)=√(x+1) and g(x)=2log⁡[-(x+1) ]? A2 {x∈R|-1≤x≤1} Q3 a) Is the sum of two even functions even,odd,or neither?Explain. b) Is the sum of two odd functions even,odd,or neither?Explain. c) Is the sum of an even function and an odd function even,odd,or neither?Explain.
Problem 2. Find a recurrence relation for un , the number of bit strings of length n that do not contain two consecutive zeros, by (a): using the recurrence relation zn for the number of bit strings of length n that do contain two consecutive zeros. SOLUTION: We simply observe that all strings of length n either do or don’t have two consecutive zeros; mathematically, this means that zn +un = 2n . Hence, un = 2n −zn = 2n −(zn−1 +zn−2 +2n−2 ). (b): by reasoning from scratch.
Set up the matrix equation to solve this system. 2. Given the inequality y < x2 + 2x – 3, is the point (0, -3) part of the solution? Name a point that is part of the solution and one that is not. 3.
Statistics 121 Problem set #1 1. Suppose {A, B, C, D, E, F} is a partition of the sample space Ω. Suppose it is known that P(A∪B∪C)= 0.6. The probability of event B is the same as the probability of event D. It is also known that P(A∪B)= P(E∪F)= 0.5 P(B∪C). Find the probabilities of the following events: a) B Solution: PA∪B∪C=0.6 ; PD∪E∪F=0.4 PB= PD = PA∪B= PE∪F = PA+ PB= PE+ PF = PA+ PB= 0.4- PD = PA+ PB= 0.4- PB = PA+ 2PB= 0.4 PA∪B= 0.5PB∪C 2PA+ 2PB= PB+ PC 0.4 + PA= PB+ PC 0.4 + PA+PA= PA+PB+ PC 0.4 + 2PA= 0.6 2PA= 0.2 PA= 0.1 PA+ 2PB= 0.4 0.1 + 2PB= 0.4 2PB=0.3 PB=0.15 b) c) A∪B∪D = PA+ PB+ PD = PA+ 2PB = 0.1 + 2(0.15) P(A∪B∪D)= 0.4 * I can’t find numbers 2, 3 and 4 5.