White precipitate shows the presence of chloride (Cl-). Chloride anion equation: HCl(aq) + AgNO3 (aq) → HNO3 (aq) + AgCl(s). The nitrate anion test involves cooling a mixture containing 1 mL of test solution and 3mL 18M H2SO4. 2mL is poured down the inner test tube side and the presence of a brown ring shows nitrate (NO3-) to be present. The carbonate anion test mixes 1 mL of test solution and drops of 6M HCl.
To perform this experiment, we will utilize emission spectra, titrations, and thermal gravimetric analysis, using knowledge from Experiments 10, 4, Titrations of Na2CO3 and NAHCO3 by HCl (hydrochloric acid) will be performed to determine the concentration of HCl, as well as the number of moles of HCl present within the sample of baking soda. As a result, we will be able to determine the molar concentration of HCl by determining its equivalence point (the point on the graph where the exact amount of rectant needed to perform a reaction has been added) from graphical analysis. Na2CO3(aq.) + HCl(aq.) ==> NaHCO3(aq.)
9) The number of moles of H2CO3 in the reaction NaHCO3 + C2H4O2 NaC2H3O2 + H2CO3 is also the number of moles of NaHCO3. 10) Calculate the number of grams of sodium bicarbonate by multiplying the number of moles of sodium bicarbonate by its molar mass. OBSERVATIONS BEFORE REACTION Total Mass: 165.93 g Total Mass: 165.93 g Mass: Alka Seltzer Tablet: 3.82 g Beaker + Vinegar: 162.11 g Temperature: 20.9 °C DURING REACTION Observations: Alka Seltzer is fizzing and dissolving into the vinegar Gas is being released as bubbles form; it’s carbon dioxide Looks like a nice glass of frothy beer AFTER REACTION Observations:
Chemistry: Molarity and Stoichiometry Directions: Using the definition of molarity, the given balanced equations, and stoichiometry, solve the following problems. Please submit your work via the link provided. 1. Calcium hydroxide (“slaked lime”) and sulfuric acid react to produce calcium sulfate and water according to the following balanced equation: Ca(OH)2(aq) + H2SO4(aq) ⋄ CaSO4(s) + 2 H2O(l) a. How many liters of 0.2 M calcium hydroxide do you need in order to have 6.0 moles of calcium hydroxide?
NaHCO3 (sodium bicarbonate - baking soda) and HCl (hydrochloric acid). The bubbles formed are carbon dioxide. HCl (hydrochloric acid) and BTB (bromothymol blue). Bromothymol blue is one of many acid-base indicators. What color do you observe?
Results - After transferring the distillate to a reaction group the halide form the top layer. The final weight of the halide was 0.17 g. % yield = (experiment yield / Theoretical yield) * 100 Calculating theoretical yield: 1 ml butanol * (0.81 g butanol / 1 ml butanol) * (1 Mole butanol / 74.12 g butanol) * (137.03 bromobutane /1 mole bromobutane) = 1.497 g of 1-bromobutane. 1.33 g of NaBr * (1 mole NaBr / 102.91 g NaBr) * (1 mole bromobutane / 1 mole NaBr) * (137.03 g bromobutane / 1 moe bromobutane) = 1.77 g of 1-bromobutane The result shows that the 1-butanol is the limiting reagent so the theoretical yield is 1.497 g of 1-bromobutane. % yield = (0.17 / 1.497)* 100 =
Using a measuring cylinder, add 50cm3 of 1.0mol dm-3 sulphuric(VI) acid to the thyme extract in the conical flask. 8. Titrate the solution in the conical flask with the potassium manganate(VII) solution until a pale pink colour persists for 10 seconds. 9. Repeat the titration until there are two titres within 0.1cm3 of each other.
Percent H2O in Hydrate is equal 0.34/2.33=14.6% 3. The general formula of barium chloride hydrate is BaClg-nHZO, where n is the number of water molecules. Calculate the theoretical percent water for each value of n—divide the sum of the atomic masses due to the water molecules by the sum of all the atomic masses in the hydrate, and multiply the result by 100. Complete the table. | BaCl2 | BaCl2•H2O | BaCl2•2H2O | BaCl•3H2O | Sum of atomic masses (BaCl2) | 208.23 | 208.23 | 208.23 | 208.23 | Sum of atomic masses (nH2O) | 0 | 18.02 | 36.04 | 54.06 | Sum of atomic masses (hydrate) | 208.23 | 226.25 | 244.27 | 262.29 | Percent water in hydrate (theoretical) | 0% | 7.96% | 14.75% | 20.61% | In this lab we used a Balance, centigram
The reaction is a synthesis. The Kc for this reaction is Kc = 49.7 at 458oC [Answer: [H2] = [I2] = 1.2 × 10-2 M, [HI] = 8.6 × 10-2 M] 2. Iodine and bromine react to give iodine monobromide, IBr. What is the equilibrium composition of a mixture at 150oC that initially contained 0.0015 mol each of iodine and bromine in a 5.0 L vessel? The equilibrium constant Kc for this reaction at 150oC is 1.2 102.
Determine ( a) The limiting reactant ( b) The percentage of excess reactant ( c) The degree of completion ( d) The percentage conversion based on Sb2 S 3 ( e) The y ield of k g Sb produced/ kg Sb 2S 3 fed to the reactor. Prob.3 A common method used in manufacturing sodium hypochlorite bleach is by the reaction C l2 + 2 NaOH = NaC l + NaOCl + H2 O C hlorine gas is bubbled through an aqueous solution of sodium hydroxide, after which the desired product is separated from the sodium chloride ( a by product of the reaction). A water NaOH solution that contains 520.5 k g of pure NaOH is reacted with 386.8 k g of g aseous chlorine. The NaOC l formed weighs 280.9 k g. (a) What was the limiting reactant? ( b) What was the percentag e excess of the excess reactant used?