A. II only B. III only C. II and III D. I only 6. A hydrate is a A. buffer solution of water B. compound in which hydrogen is combined with an element less electronegative than itself C. compound containing a definite number of water molecules in its chemical composition D. salt containing the hydroxyl radical 7. Two moles of hydrogen react with 1 mole of oxygen to produce which of the following? A. 1 mole of water B.
For this lab we want to observe how the chloro substituent has an effect on the reactivity of the possible hydrogen atoms. Experimental Results The following results on the table below was not from our own experiment but was obtained through a previous lab report that was posted in aumoodle.andrews.edu for our use by Dr. Ahlberg. Products | Relative % amounts of product | Relative Reactivity= (Relative % amount/number of hydrogen on the atom with the chloro substituent) | 1,1-dichlorobutane (minor product) | 5.97% | 2.98 | 1,2-dichlorobutane (minor product) | 23.98% | 11.99 | 1,3-dichlorobutane (major product) | 47.74% | 23.87 | 1,4-dichlorobutane (minor product) | 22.28% | 7.42 | Discussion: Based on the results of our table we can see that the relative reactivity of hydrogen atoms is influenced by several factors including the chloro substituent. One factor that determines the reactivity of the hydrogen atoms is based on how highly the carbon is substituted. For free radical formation, the more highly substituted the carbon atom is (methyl > primary > secondary >tertiary), the less energy it will require (Wade 2010).
Empirical formula: CH5N Steps for molecular formula: 1- Calculate the molar mass of the empirical formula. 2- Divide the known (given) molar mass by the calculated empirical formula molar mass to get a whole number 3- Multiply that whole number through subscripts of the empirical formula to obtain the molecular formula. Example CH5N 12.01 g C x 1 C= 12.01 g/mol 1.008 g H x 5 H = 5.040
The relative reactivity of the hydrogens H1, H2, H3 , and H4 were 0.37, 1.4, 2.9, and 1.0 respectively. The radical chlorination of 1-chlorobutane follows the radical reaction mechanism. Abstraction of hydrogen from 1-chlorobutane by the chlorine radical occurs in the first part of the propagation step. Depending on which hydrogen is abstracted by the chlorine radical, determines which product is formed. Hydrogens on the alkene have different reactivity which determines which isomer is favored.
100. g Al reacts with excess O2 to produce 150. g Al2O3 according to Calculate the theoretical and percentage yield. 4Al + 302 → 2 Al2O3. 79.4 % 14. Calculate the energy produced by the complete reaction of 150. g H2. 2H2 + O2 → 2H2O + 130KJ 4.83 x 103 kJ 15.
ABSTRACT Isopropyltoluene isomers were synthesized through the friedel-crafts alkylation of toluene with 2-chloropropane in the presence of aluminum chloride as a catalyst. Through extraction of the distillate with water and 5% NaHCO3, followed by a fractional vacuum distillation, the desired aromatic organic compound was isolated. Infrared Spectroscopy and Gas Chromatography were used to analyze the composition, purity and to confirm the identity of the prepared product. The sample weighed approximately 2.66g, which reflected a low yield at 47%. However, from the GC the area % (also known as percent purity) was 91.8%, which indicates that a very pure product was obtained.
Conclusion 10 Grams of Potassium chlorate when decomposed produces 3.915576 grams oxygen gas and 6.083363 grams potassium chloride Atomic Weight of Magnesium Introduction In this lab we will determine the atomic weight of magnesium by measuring the amount of hydrogen gas evolved when hydrochloric acid reacts with magnesium. The reaction is as follows: Mg + 2HCl -> H2 + Mg2+ (aq) + 2Cl- (aq) There is a one to one relationship between the number of moles of hydrogen gas evolved and the
(2 points) Mg(s) + 2 HCl(aq) → H2(g) + MgCl2(aq) 2. Determine the partial pressure of the hydrogen gas collected in the gas collection tube. (3 points) partial pressure H2 = total pressure - vapor pressure of water = 746mmHg - 19.8mmHg = 726mmHg 3. Calculate the moles of hydrogen gas collected. (4 points) n = 125 4.
Percent H2O in Hydrate is equal 0.34/2.33=14.6% 3. The general formula of barium chloride hydrate is BaClg-nHZO, where n is the number of water molecules. Calculate the theoretical percent water for each value of n—divide the sum of the atomic masses due to the water molecules by the sum of all the atomic masses in the hydrate, and multiply the result by 100. Complete the table. | BaCl2 | BaCl2•H2O | BaCl2•2H2O | BaCl•3H2O | Sum of atomic masses (BaCl2) | 208.23 | 208.23 | 208.23 | 208.23 | Sum of atomic masses (nH2O) | 0 | 18.02 | 36.04 | 54.06 | Sum of atomic masses (hydrate) | 208.23 | 226.25 | 244.27 | 262.29 | Percent water in hydrate (theoretical) | 0% | 7.96% | 14.75% | 20.61% | In this lab we used a Balance, centigram
101 g Fe c. How many moles of Fe2O3 will react with 99.0 g of Al? ans. 1.83 mol Fe2O3 3. The reaction N2(g) + 3H2(g) ( 2NH3(g) is used to produce ammonia commercially. If 1.40 g of N2 are used in the reaction, how many grams of H2 will be needed?