If the reaction is first order, its graphical representation is seen as ln[A] (natural log of concentration) vs. time, and the slope of its like is also the negative rate constant. Finally, for a second order reaction the graph is shown as 1/[A] (inverse of concentration) vs. time, and the slope of its given line is the positive rate constant. By understanding the rate law and finding the value of the correct rate constant with respect to the order of the reaction, one can determine the half-life of the crystal violet. This is because the crystal violet undergoes a decay reaction with the sodium hydroxide. According to Beer's Law, the absorbance of crystal violet is proportional to its concentration.
This is used when a weak acid is being used in the reaction as it acid does not fully dissociated and there is an A- value. This is the equation used for reaction (ii) as it used ClCHCOOH as the acid. Results, Observations and Discussion: (ii) 0.25M HCl | (iii) 0.5M Cl2CHCOOH | (iv) 0.125M HCl | Time(mins) | Vol (Na2S2O3) | Time(mins) | Vol(Na2S2O3) | Time(min) | Vol (Na2S2O3) | 0 | 0.46 | 0 | 0.4 | 0 | 0.33 | 6 | 0.44 | 8 | 0.4 | 6 | 0.28 | 12 | 0.4 | 16 | 0.36 | 12 | 0.24 | 18 | 0.36 | 24 | 0.29 | 18 | 0.22 | 24 | 0.32 | 32 | 0.26 | 24 | 0.2 | 30 | 0.28 | 40 | 0.2 | 30 | 0.19 | Calculations: Finding Kobs - (ii) -dI2dt=0.005
Calculate the molarity of the original vinegar solution and its concentration in gdm-3, given that it reacts with NaOH in a 1:1 ratio. 7. 2.5 g of a sample of ethanedioic acid, H2C2O4.nH2O, was dissolved in water and the solution made up to 250 cm3. This solution was placed in a burette and 15.8 cm3 were required to neutralise 25 cm3 of 0.1 moldm-3 NaOH. Given that ethanedioic acid reacts with NaOH
________________________________________ Chart 1.2: the difference between the readings in each of the trails. Chart 1.3: the difference between the sum and the average. CONCLUSION AND EVALUATION CONCLUSION: Equivalence point is the point at which the moles of H+ is equal to the moles of OH+,an indicator is used to show the equivalence point during a titration. in a titration the method is about totaling one reactant from the burette (regularly the acid),to a known volume of the other reactant in a conical flask(regularly the base) . In order to find the concentration of NaOH we need to tag along the following steps: a- note down the balanced chemical equation for the reaction C8H5O5K+NaOH→C8H4O4KNa+H2O b- pull out applicable information from the experiment: C8H5O5K V=0.025 dm3 C=0.2M NaOH V=0.021 dm3 C= ??
The purpose of the lab was to determine which reactant was the limiting reactant, and to see how much of the other reactant was used. The true molarity of a compound can be defined as the amount of moles per liter of that substance. The equation of this single displacement chemical reaction done during this lab is 2Al(s) + 3CuCl(aq) → 3Cu (s) + 2AlCl2 (aq). In the reaction, the solid Aluminum replaces the Copper in Copper (II) Chloride to produce solid copper, and Aluminum Chloride. In order to find which reactant is the limiting reactant, an equation based on the molarity of the Copper (II) Chloride may be used, or the products of the reaction may be observed.
==> NaHCO3(aq.) + NaCl(aq.) We will standardize the HCl solution to use it in the titration. The standardization will come as a result of the 1:1 molar ratio above. Thus, the molarity of the HCl solution can be calculated by dividing the number of moles of HCl by the volume of HCl (in liters) used to neutralize the Na2CO3 .
Therefore the alkalinity of water samples is being calculated. In the second approach, the two volume readings for the respective amounts of sulfuric acid used are being determined an indicator based method. Congo red and bromocresol green are being used as the indicators. Procedure (Outline provided as pre-lab): A. The pH meter was calibrated using standard pH solutions provided.
b. Calculate the fuel value in kJ/g for each of these compounds. c. FOr each hydrocarbon determine the percentage of hydrogen by mass. d. By comparing your answers for part (b) and (c), propose a relationship between hydrogen content and fuel value in hydrocarbons. a) for a we first need to find a balanced equation for when the hydrocarbons combust to form CO2 and H20.
The Ksp of Magnesium Oxalate Abstract The Ksp for the acid catalyzed titration of the saturated oxalate is 1.8 x 10-3. Introduction In this experiment, the solubility equilibrium for the salt magnesium oxalate must be found in order to determine a solubility product constant. Solubility equilibrium is a type of dynamic equilibrium which exists when a chemical compound in the solid state is in chemical equilibrium with a solution of that compound. At the point of equilibrium the solution becomes saturated. The chemical reaction used to find this constant is as follows: MgC2O4 (s) ↔Mg(aq)2++ C2O4 (aq)2- Kc= Mg2+[C2O42-][MgC2O4] Ksp=Mg2+[C2O42-] The solid salt magnesium oxalate is prepared through the following precipitation reaction: Mg(SO4)(aq)+NaC2O4 (aq) → MgC2O4 (s)+NaSO4 (aq) Next, the concentration of the Mg2+ and C2O42- ions is found through a redox titration.
½ mark 10 Outline the reaction pathway to produce propanoic acid from propane. Write the chemical reactions (using chemical structures) indicating reactants and any special conditions. 2 marks 11 Name all the chemical species in Q10 using the IUPAC system. 1 mark 12 If you put the product formed in Q10 in a basic solution, what would the resulting ion look like? 1 mark 13a Indicate the chemical equation when your product from question 10 undergoes a