The second simulated cell will be 1% sucrose solution placed into a 50% sucrose solution. I believe this simulated cell will show us the hypertonic part of this lab. Because of the cell having a less concentration than the sucrose solution it is being place, water will move out of the simulated cell and into the surrounding solution trying to even out their environment. The third simulated cell will be 50% sucrose solution placed into a 1% sucrose solution. I believe this simulated cell will show us the hypotonic part of this lab.
Osmosis is a specialized case of diffusion that involves the passive transport of water. In osmosis, water moves through a semipermeable membrane from a region of higher concentration of water to a region of lower concentration. When two solutions have the same concentrations of a solute they are said to be isotonic. When one solution has more solute than another solution it is said to be hypertonic to the other. When one solution has less solute than another solution it is said to be hypotonic.
A) is neutralized by water B) is surrounded by water molecules C) reacts and forms a covalent bond to water D) aggregates with other molecules or ions to form a micelle in water Answer: B Page Ref: Section 3 11 9) Which would you expect to be most soluble in water? A) I B) II C) III D) IV Answer: A Page Ref: Section 3 10) Solutes diffuse more slowly in cytoplasm than in water because of A) the higher viscosity of water. B) the higher heat of vaporization of water. C) the presence of many crowded molecules in the cytoplasm. D) the absence of charged molecules inside cells.
If we place the potato in a sucrose solution with a similar solute concentration as a potato, then the least amount of water will diffuse into or out of the potato cells. This occurs because this scenario will be initially closest to an isotonic solution, allowing us to determine the solute concentration of a potato. Materials: * Knife/ Cork Borer * Seven 30 cm pieces of Dialysis tubing * Thirteen 250 mL Beakers * 15% Glucose Solution * Glucose Test Strips * 1% Starch Solution * Distilled water * Lugol’s solution * 25 mL of: * .2 M sucrose * .4 M sucrose * .6 M sucrose * .8 M sucrose * 1 M sucrose * Paper Towels * Clock * Potatoes * Plastic
No matter the variety, original, crinkle, or baked, they are all manufactured with oil. This test will show how much oil each of these types of chips hold. I will be preforming a test with three varieties of 7-11 Select brand chips; Original Potato Chips, BIG BITE Hot Dog Potato Chips, and Kettle Style Salt and Vinegar Potato Chips. I will weigh out 0.5oz of potato chips, crush them on graph paper, and let them set for 1 minute. I will then remove the chips, observe the oil residue left behind, and record the data.
If the solute floats, then the density of the solvent is greater than the density of the solute. If the solute sinks, then the density of the solute is greater than the density of the solvent. In this lab, the density
The salts will be dissolved in distilled water by small quantities until the reaction reaches When ionic compounds dissolve in water, they either absorb energy from or release energy to the surroundings. If a chemical reaction absorbs heat from the surroundings, it is an endothermic reaction. If a solution releases heat to its surroundings, it is an exothermic reaction. The enthalpy of dissolution is the enthalpy change associated with the dissolution of a substance in a solvent at a constant pressure. The change in enthalpy relies on the concentration of the salt solution, because different concentrations will produce different enthalpies.
Part E – Deriving a solubility curve Aim: To be able to calculate the solubility of the compound in a certain amount of water as the temperature increases or decreases. Hypothesis: As the water increases, the solubility decreases and the substance’ saturation would get lower. And as the volume increases, the substance won’t separate to the water anymore which makes it dissolved forever without getting crystallized when the water cools down. Apparatus & Method: [refer to the sheet p. 64] Result: Temperature | Volume [ml] | Solubility [g/100g] | 65 ̊ C | 5 ml | 130.44 g | 46 ̊ C | 8 ml | 81.525 g | 39 ̊ C | 11 ml | 59.29 g | 28 ̊ C | 14 ml | 46.586 g | 22 ̊ C | 17 ml | 38.36 g | 16 ̊ C | 20 ml | 32.61 g | 12 ̊ C | 23 ml | 28.35 g | 12 ̊ C | 26 ml | 25.08 g | The solubility was calculated with the formula of: Solubility=6.522gml of waterx 100 The solubility of Potassium Nitrate is directly affected by the temperature of the solution. As the temperature of the solution rises, the solubility of Potassium Nitrate increases.
When cells are placed in a hypertonic solution, water moves into the solution instead of the cell. 3. A hypotonic solution has a lower solute which means higher amounts of water and concentration than the cell. When cells are placed in a hypotonic solution, water moves into the cell and leaves the solution. The pH level of a solution tells whether the solution has hydrogen ion concentration [H±].
The temperature at which a membrane solidifies depends on its fatty acid composition. A membrane rich in unsaturated tails will remain fluid to a lower temperature. How are the proteins attached to cell membrane via lipids? They are attached through lipid-anchored cell membrane proteins. They are attached through myristoylation, palmitoylation, or isoprenylation.