For the first procedure, we increased the frequency until we found resonance, and recorded frequencies and nodes to calculate wavelength. We did this for first harmonic through fourth harmonic, and then found the velocities using our measurements. In the first harmonic phase, our signal generated frequency was 36±1 Hz, wire frequency was 72 Hz, the number of nodes was 2 and the wavelength was 1.200 m. This was found by using the equation λ=2L/n. For the second procedure, using a wire of a certain linear mass density we found the frequency of the wire as it oscillated in its fundamental mode, or lowest resonance mode, as we increased the tension by moving the hanging mass to a higher notch. We performed this procedure again using a wire with a different linear mass
Description and Theories A. Principles and Theories Used to Obtain our Result An conventional spring, when subjected the weight (w=mg) of an object at one of its terminations, will displace a certain distance, x, with an equal and opposite force, F, being created in the spring of which opposes the pull of the weight. This conventional spring will become significantly distorted if it is subjected to a large enough weight and the force, F, will only be able to return the spring to its original configuration once the burden is removed. The force that will restore the spring to its original configuration is directly proportional to the displacement that occurred. The following equation represents this relationship where k denotes the spring constant or stiffness of the spring, F=-kx Since x symbolizes the displacement or change in the length of the spring the above equation can now be surmised in the following manner, F=mg=-k∆l This new form makes it evident that a linear proportion exists between the plot of F as function of changing in length, ∆, thus confirming the spring does in fact obey Hooke’s Law.
ID: A CHEM 1120, Dr. Gellert Mezei, Spring 2014, Practice Exam 2 Multiple Choice Identify the choice that best completes the statement or answers the question. Zero order: rate = k; [A] = [A]0 - akt; t1/2 = [A]0/2ak; First order: rate = k[A]; ln([A]0/[A]) = akt; t1/2 = ln2/ak; Second order: rate = k[A]2; 1/[A] - 1/[A]0 = akt; t1/2 = 1/ak[A]0 ____ 1. Which of the following statements about reaction orders in the rate law expression is incorrect? a. Their values may equal the stoichiometric coefficients in the balanced equation.
The weigh get heavier, the faster the punk goes. Experimental design In this experiment, the acceleration of the punk was measured with a timer and will make dots on the paper. By using different mass of weight, to calculate how does the mass affect the acceleration. Variables: Independent var. the mass of the weight dependent var.
The results can be calculated with the following formula: "trial 1 + trial 2; then divide the result by 2 to get the average mean results”. Change in Length ±0.5mm/g | | Mass ±0.5mm/g | Artery | Vein | 0 | 0 | 0 | 10 | 0.1 | 0.2 | 20 | 0.2 | 0.4 | 30 | 0.3 | 0.6 | 40 | 0.4 | 0.8 | 50 | 0.5 | 1 | Graph The graph below shows the average length of the Artery with a ±1mm difference, whilst the average length of the Vein has a ±2mm difference. The Artery and the Vein was hanged with the use of 10g to 50g of mass to distinguish how long it stretches. Conclusion: Based on the results, it can now be determined that the vein stretches longer than the artery. By these results, it can be observed that the vein stretches ±2mm per 10g of mass, while the artery stretches ±1mm per 10g of mass.
How does the rate of reaction in Task 2 compare with the rate in Task 1? Suggest a reason for the change. By comparing the two curves and the times taken to reach 0.0 g (the last times on the list), predict the time it would take for the reaction to finish if 100 chips were used. Task 3 Press back but not clear and change the number of chips to 100 but leave the acid concentration at 1.0 mol/dm3 . Click start and take readings as often as possible (by clicking the take readings button) until the mass reaches 0.0 g. Stop the reaction immediately.
Which of the following diagrams best represents the directions of the actual forces acting on the box as it moves upward after the push? 3. An ideal spring obeys Hooke's law, F = kx. A mass of 0.50 kilogram hung vertically from this spring stretches the spring 0.075 meter. The value of the force constant for the spring is most nearly (A) 0.33 N/m (B) 0.66 N/m (C) 6.6 N/m (D) 33 N/m (E) 66 N/m 4.
(b) Hence solve the equation x 2 + 6 x − 7 = 0 . (c) (i) Sketch the graph y = x 2 + 6 x − 7 . (ii) Mark and label the coordinates of the points where the graph cuts the axes. (iii) Write down the equation of the line of symmetry. Question 10 Given that the curve y = x 2 + ax − b crosses the x-axis at values of a and b. .
HSC Syllabus Summary - Space 1. The Earth has a gravitational field that exerts a force on objects both on it and around it Students learn to: * Define weight as the force on an object due to a gravitational field. * Weight is the force on an object due to a gravitational field. This force is created by the gravitational field that surrounds the Earth: F=mg. This field, given by g=GMr2, (where g is the acceleration due to gravity or the gravitational field strength, G is he universal gravitational constant, M is the mass and r is the radius of the planet) acts on objects both on Earth and around it.
Experiment #1 Reaction Time Purpose and Preliminary Discussion: In this experiment, we tested reaction times for ourselves and various objects. For part 1, the purpose was to test our individual reaction time using a stop watch, measuring how long it would take to start and stop. Part 2 was measuring eye and hand reaction time, using a pencil and piece of paper, the object was to make as many dots as possible within 5 seconds. Part 3, again testing our own reaction time, involved dropping a meter stick from a certain height and recording the time it took to catch it. Part 4 involved using a 2-meter stick and dropping various objects and recording the time it took for them to fall.