(57.10) 7 in. 3. What friction rate should be used to size a duct for a static pressure drop of 0.1 in wc if the duct has total equivalent length of 50 ft? (57.10) 0.2 4. What size metal duct should be used to deliver 270 CFM with a pressure drop of 0.15 in wc if the total equivalent length is 80 ft?
System boundary (rectangle surrounding use cases) 3. Association (line between use case and actor) A standard use case diagram is used to analyze requirements of a new system at the beginning of the system analysis. A standard use case diagram is very easy to describe, since its notation is simple (Kawabata, Kasahara and Itoh et al., 2007). The diagram in this research is for RMO CSMS marketing subsystem. In this use case diagram there are two actors, merchandising and marketing.
Friction Objectives: To provide an understanding of the concept of friction. To calculate the coefficient of friction of an object by two methods. Materials: Ramp board: 3 - 4 feet long, 10 cm wide Can of soft drink or item of similar weight Friction block set-PK Protractor Scale-Spring-500-g Tape measure, 3-m Lab notes: Using the wooden block provided in LabPaq, a long board, a can of beans and the 500-g spring scale I will try and determine the force of kinetic friction, N, and the force of static friction, N while pulling the block at a constant speed. I will convert kg-mass to Newtons by multiplying the kg-weight by 9.8 m/s2, i.e., 100 g = 0.1 kg = 0.1 x 9.8 = .98 N. Observations: Mass of block (with can): 3995 kg Weight: 3.91 N Data Table 1: Flat board Flat board Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.1 0.6 Trial 2 1 0.7 Trial 3 1 0.9 Average 1.03 0.73 Data table 2: Flat board - Block Sideways Mass of block (with can) 3995 kg Weight: 3.91 N Flat Board - Block sideways Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.3 1.4 Trial 2 1.1 1.5 Trial 3 1.1 1.1 Average 1.2 1.5 Data Table 3: Different surfaces Surfaces tried: Glass surface Force of Kinetic Friction, N Force of Static Friction, N Trial 1 0.4 0.1 Trial 2 0.4 0.1 Trial 3 0.4 0.2 Average 0.4 0.13 Data Table 4: Different Surfaces Surfaces tried: Sandpaper Force of Kinetic Friction, N Force of Static Friction, N Trial 1 2.2 1.5 Trial 2 2.1 1.7 Trial 3 2 1.1 Average 2.1 1.43 Data Table 5: Different Surfaces Surfaces tried: Wood on Carpet Force of Kinetic Friction, N Force of Static Friction, N Trial 1 1.4 1.9 Trial 2 1.5 1.6 Trial 3 1.5 1.7 Average 1.47 1.73 Data Table 6: Raised Board Height Base Length θ max μs Trial 1 .44196 m .71120 m 60 deg 0.62143 Trial 2
Part B: The graduated pipet’s average density at 22.3 °C was determined to be 0.9785g/mL with a percentage error of 1.89% shows the graduated pipet to be more accurate and precise. Part C: Density of an unknown NaCl solution was measured and a calibration curve used to determine the percentage of NaCl by mass in the solution. y=0.007x + 0.998 which concluded that the concentration of the sodium chloride solution was 3.14%. INTRODUCTION Anything that you can see, touch, taste or smell, occupies space and has mass, it is called matter. Matter can be a gas, a liquid,
Determine the percent yield of this reaction, showing all steps of your calculation. (3 points) heoretical yield of H2 gas: (1.156 x 10^-3 moles)(1 mole H2/ 1 mole Mg) = 1.156 x 10^-3 moles Theoretical mass: (1.156 x 10^-3 moles)(2.02 g/mole) = 2.335 x 10^-3 g Using ideal gas law: P = (1.1 atm)(760 torr / 1 atm) - 19.8 torr = 816.2 torr V = 0.026 L T = 295 K Solve for n: n = PV/(RT) n = (816.2 torr)(0.026
The more CO2 produced over this time, the higher the rate of reaction. In this equation, there are 3 possible independent variables: a) changing the size of the marble chips (e.g. large, small, powdered) whilst keeping the mass the same, b) changing the mass of the marble chips whilst keeping the size the same (e.g. all powdered), or c) changing the concentration of the hydrochloric acid. In equation 2, the hydrogen is measured by the loss of mass.
The maximum frictional force that must be overcome before movement is able to begin is μsFN. If you apply a constant force to pull an object along a horizontal surface at a constant speed, then the frictional force opposing the motion is equal and opposite to the applied force, Fp. Therefore, Fp = Ff. The normal force is equal and opposite to the object’s weight when the object is on a horizontal surface and the applied force is horizontal. The question to be answered by performing this lab is how can the coefficient of static and kinetic friction be determined for an object on a horizontal surface?
Q = Mc Cc ΔT (2) Where Cc = 0.215 cal/(g °C) A nylon cord is wound five times around the aluminum calorimeter. The frictional force between the band and the calorimeter is large enough that one end of the band can lift a 10 kg weight while the other end becomes slack. As a result of this mechanical trick, the frictional force is equal to the weight of the 10 kg mass and is to a large extent independent of the speed at which the drum is rotated. The work of friction (Wf) is
While others may be pessimistic about the situation, there is always something you can do to help the situation, no matter how hopeless. This story could be a good beacon of hope to a hurricane survivor or the like, as I think it would be especially powerful to them to see their own struggle detailed right there on paper. I thought Crane was trying to draw attention to the importance of working together and valuing your fellow man as you value yourself. Since we are all in the boat together, we might as well
Place your answers in the blanks below. Batman’s velocity: ________________ The Joker’s velocity: __________________ d) Make a rough sketch of (a) position vs time graphs (b) velocity vs time graphs (c) acceleration vs time graph of Batman and Joker. 20) An object has a speed of Vi it accelerates at a for t seconds and ends with a speed of Vf . If it accelerated for 3t seconds find the final velocity in terms of Vi and Vf. 21) One rock is dropped from the top of a cliff of height h at the same time as a second rock is tossed upward at speed v. if the rock that was tossed upward takes twice as much time to reach the ground as the one that was dropped, what was the initial speed, v, of the rock that was thrown (state in terms of g and h)?