Chemistry Lab Report

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Lab Report Determination of Density of Aluminum January 25, 2011 Tinisha Hallback (Chem 1211L,Tues. 7:00-9:15pm) Partners: Henrietta Mofoke & Shante Blackburn Objective: To determine the Density of aluminum by water displacement and geometric formulas. Procedure: The relationship between the mass of an object and its volume is called density. The mass and volume of aluminum was determined. The density was calculated by dividing the mass of the piece aluminum by its volume. Results/Discussion Table 1 Density of aluminum based on dimensions Trial 1 Mass of aluminum sample 17.266 g Dimensions of aluminum sample (length) 5 cm (diameter) 1.2 cm Volume of aluminum sample 5.655 cm3 Density of aluminum sample 3.028g/cm3 Trial 2 Mass of aluminum 17.110g Dimensions of aluminum sample (length) 5 cm (diameter) 1.2 cm Volume of aluminum sample 5.655 cm3 Density of aluminum sample 3.026 g/cm3 Table 2 Density of aluminum based displacement of water Trial 1 Mass of aluminum sample 17.1240 g Final volume of the water in the buret 15 ml Initial volume of the water in the buret 8.5 ml Volume of water dispensed from the buret 5.655 cm3 Volume of water level on graduated cylinder N/A Volume of aluminum sample 6.5 ml Density of aluminum sample 2.634 g/cm3 Trial 2 Mass of aluminum sample 17.1112g Final volume of the water in the buret 18 ml initial Volume of the water in the buret 11.5 ml Volume of water dispensed from the buret 5.655 cm3 Volume of water level on graduated cylinder N/A Volume of aluminum sample 6.5 ml Density of aluminum sample 2.6324 g/cm3 Avg density: 2.6332 g/cm3 Percent error is 12% Calculations D = M/V 17.1240/5.6555 = 3.027 Avg density: 3.028 + 3.026 / 2 = 3.027 Volume: 3.14159 x (1.2/2)2 x 5= 18.84954 Percent Value: 2.7-3.027/2.7 x 100 = -12.1 (Therical Value 2.7) 2.7 – 2.633/2.7 x 100 Conclusion:

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