Chemistry Lab # 10

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Confidence Report For this experiment, we need to perform two reactions. I’m very confident for the results, because we used accurate amount of the chemicals and observed very carefully of the changes. Reaction I For the first reaction, we need 25 mL of 0.005 M lead nitrate and a clean 50 mL graduated cylinder. Add 1.4 mL of 0.025 M sodium carbonate into the cylinder. Set up the vacuum filtration apparatus. Pour the prepared solution into the flask. Decant the solution evenly into two beakers. For the first beaker, we add 1 mL of 0.1 M nickel (II) nitrate. The purpose is to test the presence of excess carbonate in to solution. The result is positive due to the presence of pale green precipitation. For the second beaker, we add 1 mL of 0.1 M potassium phosphate. It is also positive due to the presence of white precipitation. Reaction II For the second reaction, we need 25 mL of 0.005 M lead nitrate and a clean 50 mL graduated cylinder. Add 1.4 mL of 0.25 M potassium iodide (we used 30 drops) into the flask. Pour the solution into the vacuum flask. Decant the solution evenly into two beakers. For the first beaker, we add 1 mL of 0.1 M potassium phosphate. The purpose is to test the excess of lead, and it is positive due to the presence of white precipitation. We add 1 mL of 0.1 M silver nitrate into the second beaker to test for excess iodide. It is positive due to the presence of yellow precipitation. Next, take out the filter paper and add 50 mL of water. Pour the solution into the vacuum flask and decant evenly into two beakers. Add 1 mL of 0.1 M potassium phosphate into the first beaker. It is negative and indicated no excess lead ion in the solution. Add 1 mL of 0.1 M silver nitrate into the second beaker. It is positive due to the presence of pale yellow

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