Experiment 11 is composed of cold liver and 2 mL H2O2. We anticipated that the reaction rate should be very low because a low temperature means a low reaction rate. At low temperatures, particles move slower and therefore there is a lower amount of collisions between the enzymes and the substrates. Based on observations, the reaction rate was fairly high which came as a surprise for us, this is not what we had anticipated. The reaction rate was given a 3.
So we concluded that this Zinc did not contain significant amounts of iodide ion. There might have been slight amounts of iodide ion from the gray solids not being washed properly after it was isolated from the zinc iodine solution (the colorless solution after the completion of the reaction). Next time, we would need to wash the zinc granules more vigorously, to clearly identify that there is no AgI precipitation to indicate the presence of iodide
This is because it traveled the longest distance. In Exercise 4B, in Table 4.4, the most light travel through the third cuvette. This happened because the pigment did not absorb the light, it went straight through. In Graph 4.1 the fourth cuvette’s line is the completely straight because there was no chloroplast to absorbed the light. This make each time the exact same.
Lack of equipment could’ve been one of factors that contributed to our errors. During this lab, we only had access to one spatula. Due to the lack of time we continued to use this one spatula despite the fact that it may not be cleaned properly and could still be dirty. The dirty spatula could’ve caused our results to be inaccurate because the different samples could’ve mixed causing the color of the flames emitted to vary. Another error that we made was due to lack of equipment once again.
Carbonate could be used to remove silver ions. This is because when carbonate reacts with a cation other the H+ and NH4+, it has a low solubility. Meaning it would form a precipitate with silver and the ions would be removed. Evidence that suggest nitrate compound are soluble is that they didn’t with most compounds, they remained aqueous. Also, there was never a formation of a precipitate when reacting with nitrate ions.
This causes it to reproduce blue colonies of bacteria. 5. We did not add plasmid to the control plate because it did not have any bacteria on it to cause a reaction. 6. We put the bacteria through a heat shock because that is how hot it would be in a human body, therefore, making it a natural
The catecholase enzyme and its substrate catechol cannot react in a pH level of 3, which is too acidic. The acidity of this pH level denatured the enzyme, thus destroying its ability to catalyze the reaction and stopping the production of benzoquinone.
Was the reaction in Test 3 a physical or chemical change? Why? The reaction in Test 3 was most likely a physically change, because as it went over the Bunsen burner, it did not change the shape or did not burst in flames, nor had it stayed light with fire. The only thing that changes was the color of the steel wool and that is not a chemical change. 7.
Sodium chloride and sucrose have none conductivity and non electrolyte. Acetic acid and ammonia are weak. Conclusion: Analyzing the data I found out that my hypothesis is right. Sucrose did not have positively or negative particles with made it none conductivity and non electrolyte. Based on the the lab the hypothesis was
4) When naming an ionic compound, which ion is given first? The metal ion is named first 5) Give explanations for the following: a. Argon will not react with any other element It already has a complete number of eight, a full number in its valance shell so it cannot react with itself or another element b. The reaction between sodium chloride gives out a lot of heat and light. The chemical energy of the product is less then the chemical energy of the reactants. This energy is indestructible and is converted to light and heat.