In the first trail it held 875.96g, second 861.60 and the third trial it held 919.04g. Figure 1 shows a basic graph for the paper towels. The graph is based on the average grams that the paper towel held. Its shows that the generic recycled paper towels held more average weight then all the other paper towels. Figure 2 shows the results from all three trails including the average, standard deviation, and standard error.
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Part I: Density of Unknown Liquid | | Trial 1 | Trial 2 | Trial 3 | Mass of Empty 10 mL graduated cylinder (grams) | 25.5g | 25g | 25g | Volume of liquid (milliliters) | 8.6mL | 8.7mL | 8.4mL | Mass of graduated cylinder and liquid (grams) | 36g | 36g | 35.5g | Part II: Density of Irregular-Shaped Solid | Mass of solid (grams) | 38.74g | 39.002g | 42.489g | Volume of water (milliliters) | 50mL | 49mL | 51mL | Volume of water and solid (milliliters) | 54mL | 53mL | 56mL | Part III: Density of Regular-Shaped Solid | Mass of solid (grams) | 26g | 27g | 26g | Length of solid (centimeters) | 5.2cm | 5cm | 4.5cm | Width of solid (centimeters) | 3cm | 4cm | 3.5cm | Height of solid (centimeters) | 2.5cm | 3cm | 2cm | Calculations Show all of your work for each of the following calculations and be careful to follow significant figure rules in each calculation. Part I: Density of Unknown Liquid 1. Calculate the mass of the liquid for each trial. (Subtract the mass of the empty graduated cylinder from the mass of the graduated cylinder with liquid.) * Trial 1 36-25.5=10g * Trial 2 36-25=11g * Trial 3 35.5-25=10g 2.
Explain your answer. It is homogenous because you can't see the different parts in it Procedure: 1. Cut 3 strips of coffee filter. Be sure that the strips are much narrower and slightly taller than the drinking glasses. 2.
| 4. | Ryan has three times as many stamps as Hal and twice as many stamps as Jimmy. If they have 220 stamps altogether, how many more stamps does Jimmy have than Hal? | 5. | Lucy and Jean have 240 stickers altogether.
Experimental Data Trial 1 Trial 2 Trial 3 Sample Volume 10 mL 10 mL 10 mL Weight sample + capped vial 26.5g 26.5g 26.3g Weight vial + cap 15.5g 15.4g 15.4g Sample weight 11.0g 11.1g 10.9g Calculated Results Trial 1 Trial 2 Trial 3 Density of samples: 1.10g/mL 1.11g/mL 1.09g/mL Average density: 1.10g/mL 1.10g/mL 1.10g/mL Deviation from Average: ±0.00g/mL ±0.01g/mL -0.01g/mL Average Deviation: add absolute values of deviations from average and divide by the number of trials. +0.00++0.01+-0.01= 0.02 ∴ Therefore, the average deviation in density = ±0.02/3 = ±0.01 Average weight of 10mL Volume Samples 10mL x 1.1g/mL = 11g Percent Inherent Error in Average Weight of Samples ±0.1 g/reading*2 readings 11* 100 = 1.8~2% Percent Inherent Error in Average Volume of Samples ±0.1 mL/reading*1 readings 10 mL*100 = 1% Total Percent Inherent Error in Density ±2%+ ±1%= ±3% Inherent Error in Density 1.10g/mL x (±3/100) = ±0.03g/mL Conclusions Since the deviations from the average density are equal to or less than the total possible inherent error computed, it is concluded that the precision of the data collected was good. Second
Using the same electronic balance, the average mass of five copper slugs, in grams, will be determined. Lastly, by using the electronic balance again, the weight of two different unknown weights, in grams, will be determined by the weighing by difference method. Using both the direct weight and weighing by difference techniques, the weight of the copper slug (2.98 g) and the two unknown weights can be fairly accurately determined using the centigram balance. However, since the electronic balance can determine mass out to three decimal places, the electronic balance was more accurate weighing the copper slug (3.022 g) than the centigram balance using the direct weight and weighing by difference methods. Determining the mass of the two unknown weights (unknown weight #1 and #2) was determined using only the centigram balance using the weighing by difference method.
b. multiplication and division The answer can have no more significant figures than are in the measurement that has the fewest number of significant figures 31. What is the general form for writing numbers in scientific notation? M x 10n, where M is greater than or equal to 1 but less than 10 and n is a whole number 32. a. By using x and y, state the general equation for quantities that are directly proportional. y/x=k or y=kx b.
a. )1 ml of water contains 7.14g of zinc b. )7.14 mL of water will hold 7.14g of zinc c.)One mL of water is equal in weight to 7.14g of zinc d.)7.14g of zinc occupies 1 mL in volume e.) there is a 1mL rise in water for every 7.14g of zinc added f.) 1 mL of zinc weighs
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