With the use of this technique we placed chlorine, bromine, and iodine into solutions containing chloride, bromide, and iodide. In the reaction the free halogen (X2) oxidizes the other halide ion (Y-) and gets reduced by gaining electron(s). In table 3, chlorine was the strongest oxidizing agent and iodine was the weakest oxidizing agent. Since chlorine was the strongest oxidizing agent it will react more and the weak agent will react less. This explanation can be demonstrated in table 3 also because the results of the reactions demonstrates that chloride reacted more by the color of the product compared to the color of chloride in the mineral oil.
Write these concentrations down in your lab notebook. 4. Now, starting with cup 5 and working your way up, test the egg in each solution to see if it will float. Use a soup spoon to lift the egg in and out of the cups. 5.
Rotational rubbing of left thumb clasped in right palm and vice versa 8. Rotational rubbing, backwards and forwards with clasped fingers of right hand in left palm and vice versa 9. Rinse hands with water 10. Dry thoroughly with single use towel 11. Use towel off faucet Instructions for proper diaper-changing technique 1.
Obtain an Erlenmeyer flask that has a vacuum opening and attach the vacuum tube to it 8. Insert funnel and rinse the funnel with distilled water 9. Turn vacuum on and pour the pink solution into the Erlenmeyer flask, the precipitate should stay on top of the filter 10. Rinse the beaker out until all residue is gone 11. Try to rinse the precipitate in the funnel until the pink color is gone 12.
2-propanol (bp=82 degrees C) 3. tetrahydofuran (bp=65 degrees C) 4. 1-butanol (bp=118 degrees C) 5. butanone (bp=80 degrees C) Give a better separation for the mixture to be distilled tetrahydofuran (bp=65 degrees C) because it is farthest from 100 degrees C Which alkyl halide would react fastest in a nucleophilic substitution using silver nitrate in ethanol (weak nucleophile, protic solvent)? 3-bromo-3-methylpentane (most
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Use your 4 markers to draw a different colored dot on each of the pencil marks on the paper strip. Allow the markers ink to dry, and then go back recolor each dot. 5. Prepare the saltwater mixture by mixing 1/8 teaspoon of salt and three cups of water in a clean 2-liter bottle. Stir or shake the solution until it is dissolved.
(h) "Hard" water contains a high concentration of calcium ions. Suggest a way to make hard water "softer: Answers: a) It could have been improved if the experimental design said " you have to place seven different nitrates in three different sodium solutions to see if a reaction occur." b) With my evidence silver nitrate was the would the cation that would make most of the anions create a precipitate. c) Chlorine can selectively remove silver ions from a solution because silver has a positive 1 charge and chlorine has a negative 1 charge so when they react it is a perfect
(3) (b) An oil sample containing 0.0100 mol of oil was found to react with 7.61 g of iodine, I2. Determine the number of C=C double bonds present in each molecule of the oil. (b) [pic]= 0.03 (mol) 3 (double bonds) (ECF); 2 Correct answer scores [2]. If 6 is given, with no working, award [1]. (2) [May 2006 SL P3] ER: In (a), the structure of glycerol was well known by the better candidates, although quite a number of alcohols with only one –OH group, or with more than one –OH group on the same carbon, were seen.
Strychnine with its molecular formula C21H22N2O2 weights 334.41158 [g/mol]. It is soluble in water, boiling water, alcohol, chloroform, benzene, toluene, methanol, glycerol, amyl alcohol and highly soluble in ether. However each one depends on its volume: 1 g dissolves in: 6400 mL of water, 3100 mL of boiling water, 150 mL of alcohol, 35 mL of chloroform,180 mL of benzene, 200 mL of toluene, 260 mL of methanol, 320 mL of glycerol, 220 mL of amyl alcohol. (1) Strychnine is one of the alkaloids. These are group of naturally occurring chemical compounds, that contain mostly basic nitrogen atoms.